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Playing with Numbers Test - 3

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Playing with Numbers Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0

    The number(10n−1)is divisible by 11 for____.

    Solution

    (10n−1) is divisible by 11 for even values of n as 102 − 1 = 99,
    104−1=9999, 106−1=999999 etc.,
    are divisible fay 11.

  • Question 2
    1 / -0

    The greatest value that must be given to x so that the number 7713x8 is divisible by 4 is______.

    Solution

    7713x8 is divisible by 4 if ifs last two digits is divisible by 4.

    So, we have x8 to be divisible by 4.

    Therefore, greatest value of x is 8.

  • Question 3
    1 / -0

    Suppose that the division N÷5 leaves a remainder of 4 and the division N÷2 leaves a remainder of 1. What must be the ones digit of N?

    Solution

      

  • Question 4
    1 / -0

    Given that the number 148101a095 is divisible by 11, where a is single digit number, what are the possible values of a?

    Solution

    If 148101a095 is divisible by 11,
    then (1+8+0+a+9)−(4+1+1+0+5) is either 0 or a multiple of 11
    ⇒ (a+18)−11 is either 0 or a multiple of 11
    ⇒ a+7=0 or a multiple of 11
    ∴ a+7=11
    ⇒a=4

  • Question 5
    1 / -0

    The largest natural number by which the product of three consecutive even natural numbers is always divisible, is ______.

    Solution

    The required number would be the product of three smallest even natural number i.e. 2 × 4 × 6 = 48.

  • Question 6
    1 / -0

    If in a number, difference between the sum of digits at its odd places and that of digits at the even places is given 0, then the number is divisible by _____.

  • Question 7
    1 / -0

    A 5-digit number xy235 is divisible by 3 such that x + y < 5, where x and y are single digits, then possible values of (x, y) are _____.

    Solution

    xy235 is divisible by 3 so sum of its digits is also divisible by 3,
    ∴ x + y + 2 + 3 + 5 = x + y + 10 is divisible by 3 and x + y < 5.
    So possible values of (x, y) are (1, 1) or (2, 0),

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