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Linear Equations in One Variable Test - 38

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Linear Equations in One Variable Test - 38
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  • Question 1
    1 / -0
    The sum of four consecutive odd positive integers is $$160$$. Find the largest among them.
    Solution
    Let the four consecutive odd positive integers are $$x,x+2,x+4,x+6$$
    $$\therefore x+x+2+x+4+x+6=160$$
    $$ 4x+12=160$$
    $$ 4x=160-12$$
    $$ 4x=148$$
    $$x=\dfrac{148}{4}$$
    $$=37$$
    $$\therefore $$ Largest odd integer is $$37+6=43$$.
  • Question 2
    1 / -0
    If the number of boys in a class is thrice the number of girls and the total number of boys is 84, calculate the number of girls in the class.
    Solution
    Let the number of girls are $$x$$
    Then number of boys $$=3x$$
    $$\Rightarrow  3x=84$$
    $$\Rightarrow x=\dfrac{84}{3}=28$$
    Then number of girls $$=28$$
  • Question 3
    1 / -0
    The sum of five positive, consecutive integers is $$115$$. Find the value of the smallest integer among these.
    Solution
    Let the five consecutive integers are $$x,x+1,x+2,x+3,x+4$$
    $$\therefore x+x+1+x+2+x+3+x+4=115$$
    $$\Rightarrow 5x+10=115$$
    $$\Rightarrow 5x=115-10$$
    $$\Rightarrow 5x=105$$
    $$\Rightarrow x=\dfrac{105}{5}=21$$
    The smallest integer $$=21$$
  • Question 4
    1 / -0
    If $$\dfrac{2}{3}(5x+7)=8x$$,then $$x$$ is equal to:
    Solution
    Given, $$ \dfrac{2}{3}(5x+7)=8x$$.

    $$\Rightarrow \dfrac{10x}{3}+\dfrac{14}{3}=8x$$  ...[By Distribution Law]

    $$\Rightarrow \dfrac{10x+14}{3}=8x$$  …[Cross-multiplying the denominators on the LHS]

    $$\Rightarrow 10x+14=24x$$ ...[Multiplying $$3$$ on both sides].

    Transposing $$x$$ terms to one side, we get,
    $$\Rightarrow 10x-24x=-14$$

    $$\Rightarrow -14x=-14$$

    $$\Rightarrow x=\dfrac{-14}{-14}=1$$.

    Hence, option $$A$$ is correct.
  • Question 5
    1 / -0
    A club has $$27$$ employees. If there are seven more women than men in the club, calculate the number of men in the club.
    Solution
    Let the number of men in the club $$=x$$
    Then number of women $$=$$ $$x+7$$
    Then according to the question,
    $$\Rightarrow x+x+7=27$$
    $$\Rightarrow 2x=27-7$$
    $$\Rightarrow 2x=20$$
    $$\Rightarrow x=\dfrac{20}{2}=10$$
    Then number of men $$=10$$
  • Question 6
    1 / -0
    $$280$$ meals are to be prepared by three chefs. Every chef has its own speed but the combined output of all three is modelled by the equation $$8x+4x+2x=280$$. If $$x$$ is a positive integer, which of the following could $$8x$$ represent in the equation?
    Solution
    In given equation $$8x+4x+2x=280$$
    Then $$14x=280$$
    $$\therefore x=20$$
    Then $$x$$ is $$20$$ meals
    Then mean of $$8x$$ in equation is 
    $$8x=8\times 20=160$$ meals
    Then the meal output by the fastest chef, who made $$160$$ meals.
  • Question 7
    1 / -0
    The value of $$d$$ which satisfies the expression $$\cfrac{4(d+3)-9}{8}=\cfrac{10-(2-d)}{6}$$ is:
    Solution
    Given, $$\dfrac {4(d+3)-9}{8}=\dfrac {10-
    (2-d)}{6}$$.

    Cross multiplying, we get,
    $$24(d+3)-54=80-8(2-d)$$

    $$\Rightarrow 24d+72-54=80-16+8d$$  ...[By Distribution Law]

    $$\Rightarrow 24d+18=64+8d$$.

    Transposing $$d$$ terms to one side, we get,
    $$\Rightarrow 24d-8d=64-18$$

    $$\Rightarrow 16d=46$$

    $$\Rightarrow d=\dfrac{23}{8}$$.

    Hence, option $$B$$ is correct.
  • Question 8
    1 / -0
    Consider two consecutive positive integers. It is given that the result of adding the smaller integer and triple the larger integer is $$79$$. Find the $$2$$ integers.
    Solution
    Let the two consecutive positive integers are $$x,x+1$$
    The according to the question,
    $$\Rightarrow x+3(x+1)=79$$
    $$\Rightarrow x+3x+3=79$$
    $$\Rightarrow 4x=79-3$$
    $$\Rightarrow 4x=76$$
    $$\Rightarrow x=\dfrac{76}{4}=19$$
    Another integer $$=19+1=20$$
    So, the two integers are $$19,20$$.
  • Question 9
    1 / -0
    The sum of three consecutive integers is equal to $$192$$. What is the product of these numbers?
    Solution
    Let the three consecutive numbers be $$x,x+1,x+2$$.
    To get the three consecutive numbers whose sum is $$192$$, we get the equation as,
    $$x+\left( x+1 \right) +\left( x+2 \right) =192$$
    $$3x+3=192$$
    $$3x=192-3$$ $$= 189$$
    $$x=\dfrac { 189 }{ 3 } $$
    $$x=63$$
    So the first number out of the three consecutive numbers is $$63$$,
    The three numbers are $$63,64$$ and $$65$$.

    The product of these numbers is,
    $$63\times 64\times 65=262080$$
    Hence the correct answer is option E.
  • Question 10
    1 / -0
    When a number $$x$$ is subtracted from $$36$$ and then  the difference is divided by $$x$$, the result is $$2$$. Find the value of $$x$$.
    Solution
    Let the number be $$x$$.

    According to the question:

    $$ \dfrac { 36-x }{ x } =2\\ \Rightarrow 36-x=2x\\ \Rightarrow 36=3x$$
    $$ \Rightarrow x=12$$

    Hence option (D) is correct option
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