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Linear Equations in One Variable Test - 9

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Linear Equations in One Variable Test - 9
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  • Question 1
    1 / -0

     In the set of three consecutive natural numbers, the sum of the last two numbers is equal to the three times the first number. Find the sum of all the three numbers

    Solution

     Let three nos. be (a-1), a, (a +1)  ∴ a + (a + 1) − 3(a − 1) ⇒2a + 1 = 3a − 3 ⇒4 − a ⇒ sum = 12

  • Question 2
    1 / -0

    If the value of 3 + 2x is equal to 3 - 2x, then the value of 5 + 3x is

    Solution

     3 + 2x − 3 − 2x ⇒ x = 0 ⇒ 5 + 3x − 5

  • Question 3
    1 / -0

    The sum of five consecutive natural numbers is 65. Find the mid number

    Solution

    (c): (a −  2) + (a − 1) + a + (a + 1) + (a + 2) = 65  ⇒ 5a = 65  ⇒ a = 13

  • Question 4
    1 / -0

    Twelve years hence Ravi?s age will be nine times his age twelve years ago. find the present age of Ravi?s

    Solution

    (b): Let age on today = x  ⇒ (x + 12)= 9 (x − 12) ⇒12 + 108 = 8x  ⇒ x = 120/8 = 15

  • Question 5
    1 / -0

     Two number are in the ratio 3 : 8. If the sum of the number is 165, then find the numbers

    Solution

    (c): 3x + 8x = 165 ⇒ x = 15 Now are 45, 120.

  • Question 6
    1 / -0

    A boy travels a distance 25 km, in 4 hours partly on foot at rate 3.5 km/hr and partly on cycle at 9 km/hr. Find the distance on foot.

    Solution

    (b): Let 'x' hrs on foot, (4 - x) hrs on cycle Distance on foot = 3.5 × x  Distance on cycle = 9 × (4 − x)  ⇒ 3.5x + 9 (4 − x) = 25 ⇒ 36 − 5. 5x = 25  ⇒ x = 2 ∴ 3. 5x = 7 km on foot.

  • Question 7
    1 / -0

    A father's age is 7 times as old as his son. Two year ago, the father was 13 times as old as his son. What are their present ages? (Son and father respectively)

    Solution

    (c): x&y be ages Then, x = 7y (x − 2) = 13(y − 2)  ⇒ 7y  −2 = 13y − 26 ⇒ 24 = 6y = y = 4  ∴ x = 28.

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