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Understanding Quadrilaterals Test - 27

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Understanding Quadrilaterals Test - 27
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  • Question 1
    1 / -0
    If the two adjacent angles of a parallelogram are $$(3x-20^\circ)$$ and $$(50^\circ -x)$$, then the value of $$x$$ is:
    Solution

    We know that sum of adjacent angles of a parallelogram is $$180^o$$.
    Therefore,
    $$(3x-20^o)+(50^o-x)=180^o$$
    $$2x+30^o=180^o$$
    $$2x=150^o$$
    $$x=75^o$$
    Option B is correct.

  • Question 2
    1 / -0
    If an angle of a parallelogram is four-fifths of its adjacent angle, what are the angles of the parallelogram?



  • Question 3
    1 / -0
    A parallelogram and a triangle stand on the same side of the base with the same base and on the same side of the base with the same height. If $${l}_{1}$$, $${l}_{2}$$ be the perimeters of the parallelogram and the rectangle respectively, then the which one of the  following is correct?
  • Question 4
    1 / -0
    A school was having 4 Hexagonal buildings joined to each other. They wanted to utilize the space between the 4 buildings to make a playground. The shape is that of a parallelogram. Can you find the measure of the angles as opposite angles are equal?
    Solution
    $$x$$ and $$y$$ are exterior angles of the regular polygon.
    $$\displaystyle \frac{360}{6} = 60$$ i.e value of $$x$$ angle
    Opposite angles are $$60^o+60^o$$
    $$360^o - 120^o           (60^o + 60^o)$$
    $$360^o = 60^o + 60^o + y + y$$
    $$2y = 360^o - 120^o$$
    $$y  =$$ $$    \dfrac{240^o }{ 2}$$
    $$y = 120^o$$
    Therefore, option A is the correct answer.
  • Question 5
    1 / -0
    Which of the following statement(s) is/are correct ?
    Solution

  • Question 6
    1 / -0
    The parallelogram PQRS is formed by joining together four equilateral triangles of side 1 unit, as shown in the figure.
    What is the length of the diagonal SQ?










  • Question 7
    1 / -0
    In a parallelogram $$ABCD$$, if $$AB = 2x + 5, CD = y + 1, AD = y + 5$$ and $$BC = 3x - 4$$, what is the ratio of $$AB$$ and $$BC$$?
    Solution
    In parallelogram, opposite sides are parallel and equal
    $$\therefore AB=CD$$ and $$AD=BC$$
    $$\Rightarrow 2x+5=y+1\longrightarrow 1$$
    $$\Rightarrow 3x-4=y+5\longrightarrow 2$$
    Equation 2-equation 1
    $$\left( 3x-2x \right) -4-5=0+4$$
    $$x=13$$
    Put value of x in 1
    $$2(13)+5-1=y$$
    $$y=30$$
    $$\cfrac { AB }{ BC } =\cfrac { 2x+5 }{ 3x-4 } =\cfrac { 2(13)+5 }{ 3(13)-4 } $$
    $$\cfrac { AB }{ BC } =\cfrac { 31 }{ 35 } $$
    $$\therefore AB:BC=31:35$$

  • Question 8
    1 / -0
    In the given figure, ABCD is a parallelogram, AL $$\perp$$ BC, AM$$\perp$$ CD, AL$$=4$$cm and AM$$=5$$cm. If BC$$=6.5$$cm, then find CD.

    Solution

  • Question 9
    1 / -0
    Which of the following closed plane figures is/are not polygons?
    Solution

  • Question 10
    1 / -0
    A parallelogram with all equal sides are called _________.
    Solution

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