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Practical Geometry Test - 6

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Practical Geometry Test - 6
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  • Question 1
    1 / -0
    Draw rectangle PQRS by using given information-
    $$PQ=5\ cm$$, $$QR=3.5\ cm$$
    Given below are the steps to construct rectangle ABCD. Arrange them in proper order-
    1) Taking point Q as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Point R is $$3.5\ cm$$ away from point Q. Taking Q as centre and $$3.5\ cm$$ as radius, draw an arc which will cut previously drawn arc at point R.
    2) Point of intersection of two lines will be last point S.
    3) Taking point P as centre, draw a line at angle of $${ 90 }^{ 0 }$$. Taking point R as centre, draw a line at angle of $${ 90 }^{ 0 }$$.
    4) Draw segment PQ of length 5 cm as base of rectangle
    Solution

  • Question 2
    1 / -0
    Construct a rhombus ABCD from following dimensions-
    $$AC=5.2\ cm$$ and $$BD=6.4\ cm$$
    Following are the steps given to construct rhombus ABCD. Arrange them in proper order-
    1) Join points A, B, C and D to complete rhombus ABCD
    2) Taking O as centre and radius of $$\frac { 6.4 }{ 2 } =3.2\ cm$$, draw arcs on both sides of segment AC to intersect perpendicular bisector in B and D respectively.
    3) Draw perpendicular bisector of segment AC which will intersect segment AC at point O.
    4) Draw segment AC of length 5.2 cm as base of rhombus.

    Solution

  • Question 3
    1 / -0
    Construct a rhombus DEAR from following dimensions-
    $$DA=5.5\ cm$$ and $$ER=4.8\ cm$$
    Following are the steps given to construct rhombus DEAR. Arrange them in proper order-
    1) Draw perpendicular bisector of segment DA which will intersect segment DA at point O.
    2) Join points D, E, A and R to complete rhombus DEAR
    3) Taking O as centre and radius of $$\frac { 4.8 }{ 2 } =2.4\ cm$$, draw arcs on both sides of segment DA to intersect perpendicular bisector in E and R respectively.
    4) Draw segment DA of length 5.5 cm as base of rhombus.
    Solution

  • Question 4
    1 / -0
    Construct a rhombus LIFT from following dimensions-
    $$LF=6\ cm$$ and $$IT=10\ cm$$
    Following are the steps given to construct rhombus LIFT. Arrange them in proper order-
    1) Join points L, I, F and T to complete rhombus LIFT
    2) Draw perpendicular bisector of segment LF which will intersect segment LF at point O.
    3) Taking O as centre and radius of $$\frac { 10 }{ 2 } =5\ cm$$, draw arcs on both sides of segment LF to intersect perpendicular bisector in I and T respectively.
    4) Draw segment LF of length 6 cm as base of rhombus.
    Solution

  • Question 5
    1 / -0
    Draw rectangle GOLD by using given information-
    $$GO=6\ cm$$, $$OL=4.2\ cm$$
    Given below are the steps to construct rectangle GOLD. Arrange them in proper order-
    1) Point of intersection of two lines will be last point D.
    2) Taking point O as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Point L is $$4.2\ cm$$ away from point O. Taking O as centre and $$4.2\ cm$$ as radius, draw an arc which will cut previously drawn arc at point L.
    3) Draw segment GO of length $$6\ cm$$ as base of rectangle
    4) Taking point G as centre, draw a line at angle of $${ 90 }^{ 0 }$$. Taking point L as centre, draw a line at angle of $${ 90 }^{ 0 }$$.
    Solution

  • Question 6
    1 / -0
    Construct a rhombus MORE from following dimensions-
    $$MR=6\ cm$$ and $$OE=8\ cm$$
    Following are the steps given to construct rhombus MORE. Arrange them in proper order-
    1) Draw perpendicular bisector of segment MR which will intersect segment MR at point O.
    2) Draw segment MR of length 6 cm as base of rhombus.
    3) Join points M, O, R and E to complete rhombus MORE
    4) Taking O as centre and radius of $$\frac { 8 }{ 2 } =4\ cm$$, draw arcs on both sides of segment MR to intersect perpendicular bisector in O and E respectively.
    Solution

  • Question 7
    1 / -0
    Construct square READ given $$RE=5.1\ cm$$
    Following are the steps given to construct square READ. Arrange them in proper order-
    1) Taking point R as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Taking R as centre and radius as 5.1 cm, draw an arc which will intersect previously drawn line at D
    2) Connect points A and D to complete square READ
    3) Draw segment RE of length 5.1 cm as base of square.
    4) Taking point E as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Taking E as centre and radius as 5.1 cm, draw an arc which will intersect previously drawn line at A
    Solution

  • Question 8
    1 / -0
    Draw rectangle MIST by using given information-
    $$MI=8\ cm$$, $$IS=6.4\ cm$$
    Given below are the steps to construct rectangle MIST. Arrange them in proper order-
    1) Taking point M as centre, draw a line at angle of $${ 90 }^{ 0 }$$. Taking point S as centre, draw a line at angle of $${ 90 }^{ 0 }$$.
    2) Taking point I as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Point S is $$6.4\ cm$$ away from point I. Taking I as centre and $$6.4\ cm$$ as radius, draw an arc which will cut previously drawn arc at point S.
    3) Point of intersection of two lines will be last point T.
    4) Draw segment MI of length $$8\ cm$$ as base of rectangle
  • Question 9
    1 / -0
    Construct square PQRS given $$RS=4.1\ cm$$
    Following are the steps given to construct square PQRS. Arrange them in proper order-
    1) Connect points P and Q to complete square PQRS
    2) Draw segment RS of length 4.1 cm as base of square.
    3) Taking point S as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Taking S as centre and radius as 4.1 cm, draw an arc which will intersect previously drawn line at P
    4) Taking point R as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Taking R as centre and radius as 4.1 cm, draw an arc which will intersect previously drawn line at Q
    Solution

  • Question 10
    1 / -0
    Construct square LIFT given $$LI=4.5\ cm$$
    Following are the steps given to construct square LIFT. Arrange them in proper order-
    1) Connect points F and T to complete square LIFT
    2) Taking point I as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Taking I as centre and radius as 4.5 cm, draw an arc which will intersect previously drawn line at F
    3) Taking point L as centre, draw a line at an angle of $${ 90 }^{ 0 }$$. Taking L as centre and radius as 4.5 cm, draw an arc which will intersect previously drawn line at T
    4) Draw segment LI of length 4.5 cm as base of square.
    Solution

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