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Data Handling Test - 26

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Data Handling Test - 26
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  • Question 1
    1 / -0
    To draw a histogram to represent the following frequency distribution:
    Class Interval 
    $$5-10$$
    $$10-15$$
    $$15-25$$
    $$25-45$$
    $$45-75$$
    Frequency
    $$6$$
    $$12$$
    $$10$$
    $$8$$
    $$15$$
    The adjusted frequency for the class $$25-45$$ is:
    Solution
    The frequency distribution will consist of classes with an interval of $$5$$. The class $$25-45$$ includes four such classes with an interval of $$5$$. Thus the adjusted frequency will be $$\dfrac{8}{4}=2$$
  • Question 2
    1 / -0
    In the figure, there is a histogram depicting daily wages of workers in a factory. Construct the frequency distribution table and find the total number of workers.

    Solution
    Frequency Distribution table for Daily wages & Number of workers is:

    Class IntervalFrequency
    $$150-200$$$$50$$
    $$200-250$$$$30$$
    $$250-300$$$$35$$
    $$300-350$$$$20$$
    $$350-400$$$$10$$
    Total Workers$$145$$

    Hence, the total number of workers is $$145$$.
    Thus, option $$A$$ is correct.
  • Question 3
    1 / -0
    According to above histogram, which group has the maximum number of workers?

    Solution
    From the given histogram,
    $$800-810$$ rupees was given to $$3$$ workers,
    $$810-820$$ rupees was given to $$2$$ workers,
    $$820-830$$ rupees was given to $$1$$ workers,
    $$830-840$$ rupees was given to $$9$$ workers,
    $$840-850$$ rupees was given to $$5$$ workers,
    $$850-860$$ rupees was given to $$1$$ workers,
    $$860-870$$ rupees was given to $$3$$ workers,
    $$870-880$$ rupees was given to $$1$$ workers,
    $$880-890$$ rupees was given to $$1$$ workers,
    $$890-900$$ rupees was given to $$4$$ workers.

    Hence, $$830-840$$ rupees was given to maximum number of workers, i.e. $$9$$.

    Therefore, $$830$$ group has the maximum number of workers.
    Thus, option $$C$$ is correct.
  • Question 4
    1 / -0

    Directions For Questions


    ...view full instructions

    How many students watched TV for less than 4 hours?

    Solution
    From the given diagram, we have 
    $$4$$ students watch television for $$1-2$$ hours
    $$8$$ students watch television for $$2 - 3$$ hours
    $$22$$ students watch television for $$3-4$$ hours
    Thus, in total $$4+8+22 = 34$$ students watch television for less than $$4$$ hours
  • Question 5
    1 / -0
    According to above histogram, how many workers earn less than $$Rs. 850$$?

    Solution
    From the given histogram,
    $$800-810$$ rupees was given to $$3$$ workers,
    $$810-820$$ rupees was given to $$2$$ workers,
    $$820-830$$ rupees was given to $$1$$ workers.
    $$830-840$$ rupees was given to $$9$$ workers,
    $$840-850$$ rupees was given to $$5$$ workers,
    $$850-860$$ rupees was given to $$1$$ workers,
    $$860-870$$ rupees was given to $$3$$ workers.
    $$870-880$$ rupees was given to $$1$$ workers,
    $$880-890$$ rupees was given to $$1$$ workers,
    $$890-900$$ rupees was given to $$4$$ workers.

    Then, the number of workers who earn less than rupees $$850$$
    $$=n(800)+n(810)+n(820)+n(830)+n(840)$$
    $$=3+2+1+9+5=20$$.

    Hence, option $$B$$ is correct.
  • Question 6
    1 / -0

    Directions For Questions


    ...view full instructions

    The number of hours for which students of a particular class watched television during holidays are shown through the given graph.
    For how many hours did the maximum number of students watch TV?

    Solution
    Class Interval         Frequency
    No. of hours No. of Students
    $$1 -2$$ $$4$$
    $$2 - 3$$ $$8$$
    $$3 - 4$$ $$22$$
    $$4 - 5$$ $$32$$
    $$5 - 6$$ $$8$$
    $$6 - 7$$ $$6$$
    Total-  $$80$$

    The highest frequency is $$32$$, and the corresponding class interval is $$4-5$$
    Hence, maximum number of students watched TV for $$4-5$$ hours,
  • Question 7
    1 / -0
    Which class-interval has the minimum frequency ?

    Solution

    We will form a table from the above histogram:
    Class IntervalFrequency
     $$0-10$$$$15$$ 
     $$10-20$$$$10$$ 
     $$20-30$$$$20$$ 
     $$30-40$$$$25$$ 
     $$40-50$$$$10$$ 
     $$50-60$$$$5$$ 
    $$\Rightarrow$$  From above table table we can see, $$50-60$$ has frequency $$5$$ which is minimum.
    $$\therefore$$  The class-interval that has the minimum frequency is $$50-60$$

  • Question 8
    1 / -0
    Refer the pie chart and answer.
    To show the distribution of proteins and other dry elements in the human body, the arc of the circle should subtend at the center an angle of:

    Solution
    Percentage of proteins and other dry elements in the body is  ($$16\% + 14\%) $$ which is equal to $$ 30\%$$

    $$\therefore$$ Central angle corresponding to proteins and other dry elements together  $$=30\% \ of \ 360^\circ$$
    $$\Rightarrow \dfrac{30}{100} \times 360$$  
    $$=108^\circ$$
  • Question 9
    1 / -0
    Answer the following question by reading the given pictograph.
    Number of TV sets sold in the year 2005 is

    Solution
    From the given pictograph, $$2005$$ has one tv symbol.
    Given that one symbol represents $$500$$ tv sets.
    Therefore the $$2005$$ has $$1\times500=500$$ tv sets.
  • Question 10
    1 / -0
    After the reading the pictograph,find the number of TV sets sold in the year $$1990$$ is

    Solution
    Given that each TV symbol represents $$500$$ TV sets.
    In the given pictograph, $$1990$$ year has $$2$$ TV symbols.
    Therefore, number of TV sets sold in the year $$1990$$ are $$2\times500=1000$$
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