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Data Handling Test - 28

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Data Handling Test - 28
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  • Question 1
    1 / -0
    .

    Solution

    $$\Rightarrow$$  One symbol represents $$5$$ balloons.
    $$\Rightarrow$$  Then, $$60$$ balloons represents how many symbols.
    $$\therefore$$  Required symbols $$=\dfrac{60}{5}=12$$
    $$\therefore$$  The number of symbols to be drawn to represent $$60$$ ballons is $$12$$
  • Question 2
    1 / -0
    A student represents his scores in Mathematics Statistics and Economics in a pie chart The central angle for Mathematics is $$\displaystyle 120^{\circ}$$ He scored $$96$$ in Statistics and $$84$$ in Economics The central angle for Statistics is?
    Solution
    Marks in Statistics $$=96$$
    Marks in Economics $$=84$$
    total angle in a pie chart$$=360^{\circ}$$
    Angle for Maths $$=120^{\circ}$$
    Angle for Statistics and Economics $$=360-120=240^{\circ}$$
    Total marks $$=\dfrac{360}{240}\times (96+84)=270$$
    $$\therefore $$ Angle for statics $$=\dfrac{96}{270}\times 360=128^{\circ}$$
  • Question 3
    1 / -0
    From the pie graph shown alongside Find the percent of students that are seventh grades

    Solution
    Angle at the centre representing Grade $$7$$
      $$=\displaystyle  360^{\circ}-\left ( 126^{\circ}+144^{\circ} \right )=360^{\circ}-270^{\circ}=90^{\circ}$$
    $$\displaystyle \therefore $$ Reqd. %  $$=\displaystyle \frac{90^{\circ}}{360^{\circ}}\times 100=25\% $$
  • Question 4
    1 / -0
    If one symbol of image(Ref image) Represents $$10$$ bottles of apple juice then $$35$$ bottles of apple juice represented by

    Solution
    $$3$$ full and one half are required to show $$35$$.
    Hence the answer is option C
  • Question 5
    1 / -0
    The pie chart shows the profit made by a company in the first $$4$$ months of the year. The total amount of profit made in the $$4$$ months was Rs. $$80000$$. How much profit did the company make in February?

    Solution
    Profit made in February $$=27\%$$ of $$80000$$
    $$\dfrac{27}{100}\times 80000=$$ Rs. $$21600$$
  • Question 6
    1 / -0
    Which of the following is an outcome?
    Solution
    An outcome is the result of a single trial of an experiment.
    A. Rolling a pair dice is an experiment that results in $$36$$ possible outcomes.
    B. Landing on red is an outcome as after performing an experiment, the result can be landing on red. 
    C. Choosing $$2$$ marbles from a jar cannot be an outcome, because it is not known how many balls are there,  but it can be an experiment.
  • Question 7
    1 / -0
    Sapna found the following data in an almanac.

    CropArea planted (in acres)
    Wheat$$55,000$$
    Corn$$32,500$$
    Potatoes$$30,000$$
    Lettuce$$40,000$$
    Carrots$$22,500$$
    Total$$180,000$$

    She needs to use it to make a circle graph. What is the best estimate of the number of degrees that should be in the central angle of the section that represents wheat?
    Solution
    Angle represent the wheat=$$\dfrac{55000}{180000}\times 360=110^{\circ}$$
  • Question 8
    1 / -0
    If the monthly expenditure pattern of a person who earns a monthly salary of Rs. 15,000 is represented in a pie graph, then the sector angle of an item on transport expenses measures $$15^o$$. What is his monthly expenditure on transport? 
    Solution
    Using the formula for area of a sector, monthly expenditure on transport 
    =$$\displaystyle \frac { { 15 }^{ o } }{ { 360 }^{ o } } \times Rs.15000=Rs.625$$.
  • Question 9
    1 / -0
    Out of total of $$1080$$ workers,$$420$$ workers belong to category $$A, 300$$ to category $$B, 225$$ belong to category $$C$$ and $$135$$ are category $$D$$ workers.
    Can we represent the given data in a pie chart.
    Solution
    Let us first find out the central angle for the sectors to be represented by these parts.
    (i) Category A $$=\dfrac {420}{1080}\times 360^{\circ}=140^{\circ}$$

    (ii) Category B $$=\dfrac {300}{1080}\times 360^{\circ}=100^{\circ}$$

    (iii) Category C $$=\dfrac {225}{1080}\times 360^{\circ}=75^{\circ}$$

    (iv) Category D $$=\dfrac {135}{1080}\times 360^{\circ}=40^{\circ}$$
    Let us add the central angles to check their correctness, $$140^{\circ} + 100^{\circ} + 75^{\circ} + 45^{\circ} = 360^{\circ}$$
    Draw a circle and mark the radius OA. Then at 0 draw successive angles(in a clockwise direction) of measures $$140^{\circ}, 100^{\circ}, 756^{\circ}$$ and $$45^{\circ}$$, These angles are $$\angle  AOB, \angle BOC, \angle COD$$ and $$\angle DOA$$.

  • Question 10
    1 / -0
    The pictogram shows the number of visitors to an exhibition in a particular week. The number of visitors recorded after Wednesday is:

    Solution
    Number of visitors in an exhibition after Wednesday $$=$$ Number of visitors in an exhibition on Thursday + Number of visitors in an exhibition on Friday
    Number of visitors in an exhibition after Wednesday $$=$$ $$(6\times 6) + (6\times 4)$$
                                                                                           $$=$$ $$ 36 + 24 = 60$$  

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