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Data Handling Test - 31

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Data Handling Test - 31
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  • Question 1
    1 / -0
    Total number of students in all are:

    Solution
    From the histogram:
    Height (in cm)No. of students 
    $$150-155 $$ $$5 $$
    $$155-160$$ $$1$$
    $$160-165$$ $$ 5$$
    $$ 165-170$$ $$5$$
    $$ 170-175$$ $$ 9$$
    $$ 175-180$$ $$5$$
    Total no. of students $$=n(150)+n(155)+n(160)+n(165)+n(170)+n(175)$$
    $$=5+1+5+5+9+5$$ $$=30$$.

    Therefore, there are $$30$$ students in total.
    Hence, option $$D$$ is correct.
  • Question 2
    1 / -0
    What is the minimum height possible of the tallest student?

    Solution
    From the histogram:
    Height (in cm)No. of students 
    $$150-155 $$ $$5 $$
    $$155-160$$ $$1$$
    $$160-165$$ $$ 5$$
    $$ 165-170$$ $$5$$
    $$ 170-175$$ $$ 9$$
    $$ 175-180$$ $$5$$
    The minimum height of the tallest student belongs to class interval $$175-180.$$
    Thus, the minimum height possible is $$175$$ [$$\because$$ In class $$175-180, 175$$ is lower limit and can be included in class $$175-180$$]. 

    Hence, option $$B$$ is correct.
  • Question 3
    1 / -0
    The number of votes received in the election of class monitor are
    Mona $$-$$ $$6$$ votes, 
    Payal $$-$$ $$10$$ votes, 
    Prashant $$-$$ $$2$$ votes, 
    Sona $$-$$ $$20$$ votes, 
    Rajen $$-$$ $$15$$ votes, 
    Meera $$-$$ $$4$$ votes, 
    Subhash $$-$$ $$3$$ votes
    In a circle graph the central angle corresponding to the votes of Sona, Mona, Meera and Subhash are
    Solution
    Total no of votes $$= 6 + 10 +2 + 20 + 15 + 4 + 3 = 60$$
    Central angles corresponding to the various votes 
    Mona $$=\cfrac{6\times 360^o}{60}=36^\circ$$
    Payal $$=\cfrac{10\times 360^o}{60}=60^\circ$$
    Prashant $$=\cfrac{2\times 360^o}{60}=12^\circ$$
    Rajen $$=\cfrac{15\times 360^o}{60}=90^\circ$$
    Subhash $$=\cfrac{3\times 360^o}{60}=18^\circ$$
    Sona $$=\cfrac{20\times 360^o}{60}=120^\circ$$
    Meera $$=\cfrac{4\times 360^o}{60}=24^\circ$$
  • Question 4
    1 / -0

    Directions For Questions

    900 men volunteered for joining the armed force. study the pie-graph and answer the following

    ...view full instructions

    What percentage of men volunteered to join navy force?

    Solution
    Percentage of men volunteered to join navy force $$=\frac{60}{360}\times 100 = 16.67\%$$
  • Question 5
    1 / -0
    Which of the following are equally likely outcomes?
    Solution
    A) A coin is tossed. The probability of head or tail is $$\cfrac{1}{2}$$.
    B) A die is thrown. The probability of any one of $$6$$ numbers is $$\cfrac{1}{6}$$
  • Question 6
    1 / -0
    The number of students in a hostel, speaking hindi is $$40$$, bengali is $$25$$ and english $$35$$. If it is represented in pie chart central angle corresponding to hindi is _____
    Solution
    Central angle $$=\dfrac{40}{40+25+35}\times 360^\circ=\dfrac{40}{100} \times 360^\circ = 144^\circ$$
  • Question 7
    1 / -0

    Directions For Questions

    900 men volunteered for joining the armed force. study the pie-graph and answer the following

    ...view full instructions

    How many men volunteered for air force?

    Solution
    No of men joining air force $$=\dfrac{100}{360}\times 900 = 250$$
  • Question 8
    1 / -0
    How many students are over $$170\:cm$$ tall?

    Solution
    From the histogram:
    Height (in cm)No. of students 
    $$150-155 $$ $$5 $$
    $$155-160$$ $$1$$
    $$160-165$$ $$ 5$$
    $$ 165-170$$ $$5$$
    $$ 170-175$$ $$ 9$$
    $$ 175-180$$ $$5$$
    Then, number of students whose height is over $$170 cm$$
    $$=n(170)+n(175)$$
    $$=9+5$$
    $$=14$$.

    Hence, $$14$$ students are over $$170 cm$$ tall.
    Therefore, option $$A$$ is correct.
  • Question 9
    1 / -0
    The histogram shows that the level of diabetic (in mg per dl) of $$105$$ children. How many children have a level of diabetic between $$60-80$$?

    Solution
    By referring the histogram, number of students with diabetic level:
    $$20-40$$ is $$5$$ students
    $$40-60$$ is $$20$$ students
    $$60-80$$ is $$35$$ students
    $$80-100$$ is $$15$$ students
    $$100-120$$ is $$10$$ students
    $$120-140$$ is $$20$$ students.

    Therefore, $$35$$ children have a level of diabetic between $$60-80$$.

    Hence, option $$D$$ is correct.
  • Question 10
    1 / -0

    Directions For Questions

    Mr. Daniel surveyed his employees on the time it takes them to get to work. The result are shown in the histogram.

    ...view full instructions

    How many employees get to work in more than $$100$$ minutes?

    Solution
    From the histogram, we can observe the class width of:
    $$100-120$$ minutes $$= 4$$ employees.
    Therefore, number of employees get into work in more than $$100$$ minutes $$= 4$$.
    So, $$4$$ employees get into work more than $$100$$ minutes.

    Hence, option $$C$$ is correct.
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