Squares and Square Roots Test

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Squares and Square Roots Test - 11

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Weekly Quiz Competition

Question 1
1 / -0

What is the value of $$\sqrt{625}$$?

A
$$25$$

B
$$-5$$

C
$$15$$

D
$$-15$$

Solution

The square root of $$625$$ is $$25$$ as $$ 5 \times 5 \times 5 \times 5 = 25\times 25 = (25)^2 =625$$.
Question 2
1 / -0

$$7928$$ is not a perfect square. Give reason.

A
Because last two digits are $$28$$

B
Because last digit of a number is $$8$$

C
Because first two digits are not divisible by $$8$$

D
Data insufficient

Solution

We know that numbers ending with $$2, 3, 7$$ and $$8$$ are not perfect squares.
So, the number $$7928$$ is not a perfect square because it ends with $$8$$.
Question 3
1 / -0

Which of the following is not a perfect square number?

A
$$16$$

B
$$25$$

C
$$37$$

D
None of the above

Solution

Here, $$16$$ can be written as,
$$16=4\times4$$
$$=4^2$$
And, $$25$$ can be written as,
$$25=5\times 5$$
$$=5^2$$
But $$37$$ is a prime number and it cannot be written as a square of any whole number.
Therefore, option $$C$$ is the correct answer.
Question 4
1 / -0

What is the value of $$\sqrt4$$?

A
$$2$$

B
$$3$$

C
$$1$$

D
None of these

Solution

$$4$$ can be written as $$2^2$$
$$\therefore \sqrt4=\sqrt{2^2}=2$$
Hence, option A is correct.
Question 5
1 / -0

If the square number ends with ___, then the number has $$8$$ or $$2$$ at the units place.

A
$$18$$

B
$$6$$

C
$$9$$

D
$$4$$

Solution

$$2 \times 2= 4$$ and $$8 \times 8 = 6\underline{4}$$ (the units place is $$4$$)
So, either $$8$$ or $$2$$ is necessary in the units place.
Question 6
1 / -0

$$42$$ is not a _______ number .

A
minimum

B
perfect square

C
odd

D
prime

Solution

As we know that all the perfect square number ends with $$1,4,9,6,5,00$$T
Therefore, B is the correct answer.
Question 7
1 / -0

The numbers that end in 2, 3, 7 or 8 are called ______ squared numbers.

A
perfect

B
non-perfect

C
rational

D
real

Solution

The numbers end in $$2, 3, 7$$ or $$8$$ are called non-perfect squared numbers.
Question 8
1 / -0

Can we construct sets of Pythagorean Triples with all even numbers?

A
Real

B
Yes

C
No

D
Negative

Solution

Yes we can construct Pythagorean Triples with all even number.
An example of such triplet is $$6,8,10.$$
where $${ \left( 8 \right) }^{ 2 }{ +(6) }^{ 2 }={ \left( 10 \right) }^{ 2 }$$
So option $$B$$ is correct.
Question 9
1 / -0

1 is the square root of

A
$$4$$

B
$$1$$

C
$$3$$

D
None

Solution

$$1^2=1$$ and $$(-1)^2=1$$
Therefore, B is the correct answer.
Question 10
1 / -0

What is the value of $$\sqrt {441}$$?

A
20

B
21

C
22

D
None of these

Solution

$$441$$ can be written as $$(21)^2$$
So, $$\sqrt{441}=\sqrt{(21)^2}=21$$
Hence, option B is correct.

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Re-Attempt Weekly Quiz Competition

Squares and Square Roots Test - 11

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Squares and Square Roots Test - 11

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SHARING IS CARING

Question 1

$$25$$

$$-5$$

$$15$$

$$-15$$

Solution

Question 2

Because last two digits are $$28$$

Because last digit of a number is $$8$$

Because first two digits are not divisible by $$8$$

Data insufficient

Solution

Question 3

$$16$$

$$25$$

$$37$$

None of the above

Solution

Question 4

$$2$$

$$3$$

$$1$$

None of these

Solution

Question 5

$$18$$

$$6$$

$$9$$

$$4$$

Solution

Question 6

minimum

perfect square

odd

prime

Solution

Question 7

perfect

non-perfect

rational

real

Solution

Question 8

Real

Yes

No

Negative

Solution

Question 9

$$4$$

$$1$$

$$3$$

None

Solution

Question 10

20

21

22

None of these

Solution

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