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Cubes and Cube Roots Test - 11

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Cubes and Cube Roots Test - 11
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Calculate the value of $$\sqrt[3]{-64} + \sqrt{9^{2}}$$.
    Solution

    On prime factorising, we get,

    $$-64=(-4) \times (-4) \times (-4)$$ $$= (-4)^3$$.


    Then,
    $$\sqrt[3]{-64} + \sqrt{9^{2}} = \sqrt[3]{(-4)^3} + 9 =-4+9= 5$$.

    Hence, option $$C$$ is correct.
  • Question 2
    1 / -0
    Cube of $$(-3)$$ is:
    Solution
    Cube of $$(-3)$$ is:
    $$(-3)^3=-3\times -3\times -3=-27$$.

    Hence, option $$D$$ is correct.
  • Question 3
    1 / -0
    Cube root of the quotient of two negative integers is ______.
    Solution
    The quotient of two negative integers, i.e. a negative number when divided by another negative number gives a positive number.
    Then, the cube root of the resultant positive number will be positive.

    E.g.: Let the two integers be $$-16$$ and $$-2$$.
    Then, their quotient $$\dfrac{-16}{-2}=8$$, which is positive.
    Therefore, $$\sqrt[3]{\dfrac{-16}{-2}}=\sqrt[3]{8}=2$$, which is also positive.

    Hence, option $$A$$ is correct.
  • Question 4
    1 / -0
    The value of $$(3.1)^3$$ is:
    Solution
    Cube of $$(3.1)$$ is:
    $$(3.1)^3=3.1 \times 3.1 \times 3.1$$
                $$=29.791$$.
    Hence, option $$B$$ is correct.
  • Question 5
    1 / -0
    There is no perfect cube which ends with $$8$$.
    Solution
    We know,
    cube of $$2$$, i.e. $$2^3=8$$, which is a perfect cube.
    That is, there exists a perfect cube which ends in $$8$$.
    Therefore, the given statement is false and option $$B$$ is correct.
  • Question 6
    1 / -0
    A number raised to power $$3$$ is called the _____.
    Solution
    If a number is raised to the power $$3$$, then it is called the cube of that number.

    Hence, option $$A$$ is correct.
  • Question 7
    1 / -0
    Cube of an odd natural number is an  _____  number.
    Solution
    We know, the multiplication of odd natural numbers $$3$$ times, i.e. the cube of an odd natural number, will always be odd.
    That is because an odd number multiplied to another odd number, always yields an odd number.

    For example, consider the odd natural numbers $$3$$ and $$5$$.
    Then, their cube is $$3^3=27$$ and $$5^3=125$$, whose units place is odd.
    That is, the cubes are also odd.

    Hence, the cube of an odd natural number is an odd number.
  • Question 8
    1 / -0
    Cube of even natural number is _____ number.
    Solution
    We know, the multiplication of $$3$$ even numbers, i.e. the cube of an even natural number, will always be even
    Example, consider the even natural numbers $$2$$ and $$4$$.
    Then, their cube is $$2^3=8$$ and $$4^3=64$$, whose units place is even.
    That is, the cubes are also even.
    Hence, we can say, cube of even natural number is even.
    Therefore, option $$A$$ is correct.
  • Question 9
    1 / -0
    The cube of  the  given number is:
    $$0.4 $$.
    Solution
    Cube of the number $$0.4$$:
    $$(0.4)^{ 3 } = 0.4\times0.4\times 0.4 = 0.064$$.

    Hence, option $$A$$ is correct.
  • Question 10
    1 / -0
    The cube of  the  given number is:
    $$1.3 $$.
    Solution
    Cube of the number $$1.3$$:
    $$(1.3)^{ 3 } = 1.3\times1.3\times1.3 = 2.197$$.

    Hence, option $$A$$ is correct.
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