Comparing Quantities Test

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Comparing Quantities Test - 37

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Weekly Quiz Competition

Question 1
1 / -0

The present population of a town is $$35,000$$. If the population becomes $$35,700$$ next year, the rate of growth is

A
$$2\%$$

B
$$20\%$$

C
$$70\%$$

D
$$7\%$$

Solution

Population next year, $$P = 35700$$
Current population, $$P_o = 35000$$
$$P = P_o \left(1 + \cfrac{R}{100}\right)^T$$
$$35700 = 35000 \left(1+ \cfrac{R}{100}\right)^1$$
$$35700 - 35000 = \cfrac{35000 R}{100}$$
$$R = \cfrac{700 \times 100}{35000}$$
$$R = 2\%$$
Question 2
1 / -0

The population of a town increases from $$10000$$ to $$10400$$. The growth rate is

A
$$4\%$$

B
$$40\%$$

C
$$2\%$$

D
$$20\%$$

Solution

Population an year ago, $$P_o = 100000$$
Population after one year $$P = 10400$$
Let the growth rate be R,
then $$ P = P_o \left(1 + \cfrac{R}{100}\right)^T$$
$$10400 = 10000\left(1 + \cfrac{R}{100}\right)$$
$$10400 = 10000 + 100 R$$
$$R = \cfrac{400}{100} = 4\%$$
Thus, growth rate $$= 4\%$$
Question 3
1 / -0

A scooter was bought at $$\text{Rs. } 42000$$. Its value depreciated at the rate of $$8\%$$ per annum, find its value after one year.

A
$$\text{Rs. } 38640$$

B
$$\text{Rs. } 37740$$

C
$$\text{Rs. } 38145$$

D
$$\text{Rs. } 39640$$
Question 4
1 / -0

By selling a pen for $$\text{Rs. } 15$$, a man loses one-sixteenth of what it costs him. Find the cost price of one pen.

A
$$\text{Rs. } 16$$

B
$$\text{Rs. } 18$$

C
$$\text{Rs. } 20$$

D
$$\text{Rs. } 21$$

Solution

Let's assume the cost price of the pen is $$x$$
According to the question, Loss $$=\cfrac { x }{ 16 } $$
Cost Price$$ = $$ Selling Price $$ + $$ Loss
Hence,
$$15+\dfrac { x }{ 16 } =x$$
$$15=x-\dfrac { x }{ 16 } $$
$$15=\dfrac { 15x }{ 16 } $$
$$x=16$$
Hence, the cost of $$1$$ pen is $$\text{Rs. } 16$$
Question 5
1 / -0

Jill is putting a tile floor in her kitchen. She needs $$52$$ tiles to cover the whole floor. There are $$24$$ tiles in a box. A box costs $$Rs$$. $$23.95$$. Individual tiles cost $$Rs$$. $$2.95$$. Sales tax is $$5\%$$. How much will $$52$$ tiles cost approximately, including sales tax?

A
$$Rs$$. $$50$$

B
$$Rs$$. $$57$$

C
$$Rs$$. $$60$$

D
$$Rs$$. $$63$$

Solution

Total tiles required=52 tiles
1 box has 24 tiles.
So, 2 box+ 4 tiles are required.
cost=cost of 2 box+4 tiles cost+service tax
$$C=(2\times 23.95+4\times 2.95)\times 1.05$$
$$C=62.69$$
Answer (D) Rs. 63
Question 6
1 / -0

What percentage of a day is six hours and 45 minutes?

A
7.218%

B
8.3%

C
28.125%

D
None of these

Solution

A day is 24hrs.
six hours and 45 minutes=
$$6\frac { 45 }{ 60 } =6\frac { 3 }{ 4 } =\frac { 27 }{ 4 } Hrs$$
So, % of a day=
$$=\frac { 27 }{ 4*24 } \times 100$$
$$=\frac { 27 }{ 4*24 } \times 100=28.13%$$
Answer (C) 28.125%
Question 7
1 / -0

A shopkeeper sold sarees at $$\text{Rs. }266$$ each after giving a $$5 \%$$ discount on labeled price. Had he not given the discount, he would have earned a profit of $$12 \%$$ on the cost price. what was the cost price of each saree?

A
$$\text{Rs. } 240$$

B
$$\text{Rs. } 260$$

C
$$\text{Rs. } 280$$

D
Date indepequate

E
None of these

Solution

Let us assume that the labeled price is equal to $$x$$.

$$\dfrac{95}{100}\times x=266$$
$$\Rightarrow x = \text{Rs. } 280$$

Now consider that the cost price of the saree is equal to $$y$$. Then,
$$\text{Profit}\% = 12=\dfrac{ (280-y)\times 100 }{ y } $$
$$\begin{array}{l}\Rightarrow12y = 28000 - 100y\\\Rightarrow112y = 28000\\\Rightarrow y =\text{Rs. } 250\end{array}$$

Hence, option $$D$$ is the correct answer.
Question 8
1 / -0

Samant brought microwave oven and paid 10% less than the original price. He sold it with 30% profit on the price he had paid. What percentage of profit did Samant earn on the original price?

A
17%

B
20%

C
27%

D
32%

Solution

Lets assume original price of the microwave oven = Rs. 100
So, buying price for samant = Rs. 90
Profit $$\% = 30\% = \dfrac{p\times100}{Cost price}$$
$$30\% = \dfrac{p\times100}{90}$$
$${30\times90}{100}=p$$
$$profit=27$$
Selling price =90+27=117 Rs
Profit =117-100=17 Rs
profit $$\%=\dfrac{17\times100}{100} = 17%$$
Question 9
1 / -0

By selling a book for Rs. 10, the publisher loses $$\displaystyle \frac{1}{11}$$ of what it costs him. His cost price is ....

A
Rs. 9

B
Rs. 10

C
Rs. 11

D
Rs. 12

Solution

Let's assume cost price $$=x$$
Selling price $$=\text{Rs.}\ 10 $$
Loss$$=\dfrac{1}{11}.x$$
$$\text{Cost Price=Selling Price + Loss}$$
$$x=10+\dfrac { x }{ 11 } $$

$$\dfrac { 10x }{ 11 } =10$$
$$x=\text{Rs.}\ 11$$
Answer (C) Rs. 11
Question 10
1 / -0

A person has enough money to buy $$25$$ cycles worth $$Rs.\,500$$ each. How many cycles will the person be able to buy, if each cycle now costs $$Rs.\,125$$ more ?

A
$$40$$ cycles

B
$$70$$ cycles

C
$$20$$ cycles

D
$$65$$ cycles

Solution

Total money=25*500=12500
New cost of cycle=500+125=625
No of cycle person is able to buy
$$N=\frac { Total\quad money }{ cost\quad of\quad 1\quad cycle } $$
$$N=\frac { 12500 }{ 625 } =20$$
Answer (C) 20

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Re-Attempt Weekly Quiz Competition

Comparing Quantities Test - 37

Result

Comparing Quantities Test - 37

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SHARING IS CARING

Question 1

$$2\%$$

$$20\%$$

$$70\%$$

$$7\%$$

Solution

Question 2

$$4\%$$

$$40\%$$

$$2\%$$

$$20\%$$

Solution

Question 3

$$\text{Rs. } 38640$$

$$\text{Rs. } 37740$$

$$\text{Rs. } 38145$$

$$\text{Rs. } 39640$$

Question 4

$$\text{Rs. } 16$$

$$\text{Rs. } 18$$

$$\text{Rs. } 20$$

$$\text{Rs. } 21$$

Solution

Question 5

$$Rs$$. $$50$$

$$Rs$$. $$57$$

$$Rs$$. $$60$$

$$Rs$$. $$63$$

Solution

Question 6

7.218%

8.3%

28.125%

None of these

Solution

Question 7

$$\text{Rs. } 240$$

$$\text{Rs. } 260$$

$$\text{Rs. } 280$$

Date indepequate

None of these

Solution

Question 8

17%

20%

27%

32%

Solution

Question 9

Rs. 9

Rs. 10

Rs. 11

Rs. 12

Solution

Question 10

$$40$$ cycles

$$70$$ cycles

$$20$$ cycles

$$65$$ cycles

Solution

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