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Comparing Quantities Test - 42

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Comparing Quantities Test - 42
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  • Question 1
    1 / -0
    When the rate of sale-tax is decreased from 9% to 6% for a coloured T.V.; Mrs. Geeta will save Rs. 780 in buying this T.V. Find the list price of the T.V.
    Solution
    Let the List price of the T.V=Rs.x
    Then according to the question
    $$(x+9\%  of x)-(x+6\% of x)=780$$
    $$\Rightarrow x+\frac{9x}{100}-x-\frac{6x}{100}=780$$
    $$\Rightarrow \frac{9x}{100}-\frac{6x}{100}=780$$
    $$\Rightarrow 3x=78000$$
    $$\Rightarrow x=\frac{78000}{3}=Rs. 26000$$
  • Question 2
    1 / -0
    Ramesh invests Rs. 12,800 for three years at the rate of 10% per annum compound interest. Find the interest he earns for the second year.
    Solution
    P $$=Rs.12800$$

    Rate of interest $$=10$$ %

    Interest for the first year $$=\dfrac{PRT}{100}$$

    $$\Rightarrow \dfrac{12800\times 10\times 1}{100}=Rs.1280$$

    Amount after first year$$=12800+1280=Rs.14080$$

    For Second year
    Principal $$=Rs.14080$$
    R $$=10$$%
    T $$=1$$ year

    then Interest for second year$$=\dfrac{PRT}{100}$$

    $$\Rightarrow \dfrac{14080\times 10\times 1}{100}=Rs.1408$$
  • Question 3
    1 / -0
    Saurabh invests $$Rs.\ 48,000$$ for $$7$$ year at $$10\%$$ per annum compound interest. Calculate the interest for the first year.
    Solution
    Given:
    $$P=Rs.\ 48000$$
    $$r=10\%$$
    $$t=1 $$ year

    $$CI$$ for $$1^{st}$$ year $$=$$ $$SI$$ for $$1^{st}$$ year

                               $$=\dfrac{PRT}{100}$$

                               $$=\dfrac{48000\times 10\times 1}{100}$$

                               $$=Rs.\ 4800$$

    Hence, option $$A$$ is correct.
  • Question 4
    1 / -0
    A sum of Rs. $$13,500$$ is invested at $$16\%$$ per annum compound interest for $$5$$ years. Calculate the interest for the second year, correct to the nearest rupee.
    Solution
    Sum=Rs 13,500
    Rate=16%
    Amount at the end of first year$$=P\left(1+\frac{R}{100}\right)^T$$
    $$\Rightarrow 13500\left(1+\dfrac{16}{100}\right)$$
    $$\Rightarrow 13500\times \dfrac{116}{100}=Rs.15,660$$
    For the second year
    Sum $$=Rs\,15,660$$
    Then amount after second year$$=15660\left(1+\dfrac{16}{100}\right)$$
    $$\Rightarrow 15,660\times \dfrac{116}{100}=Rs.18165.6$$
    $$\therefore$$ Interest for second year $$=18,165.6-15,660$$
                                                $$=Rs\,2505.6$$
    Rounding off $$Rs\,2505.6$$ we get $$Rs\,2,506$$ 
     Therefore interest for the second year is $$Rs\,2,506$$ 
  • Question 5
    1 / -0

    Directions For Questions

    A man buys$$120$$ shares of face value $$Rs. 75$$ shares at a discount of $$Rs. 15$$ of a company paying $$20\%$$ dividend.

    ...view full instructions

    the market value of 120 shares;
    Solution
    As the discount is Rs.15 then market value of  1 share$$=75-15=Rs.60$$
    $$\therefore $$Market Value of 120 share$$=120\times 60= Rs. 7200$$
  • Question 6
    1 / -0
    During every financial year, the value of a machine depreciates by 12%. Find the original cost of a machine which depreciates to Rs. 2,640 during the second financial year of its purchase.
    Solution
    $$\textbf{Step 1: Calculating the cost for the }\mathbf{1^{st}} \textbf{ year}$$
                    $$\text{Consider the original value to be x,}$$
                    $$\text{After the first year the value reduces to}$$
                    $$=x-\dfrac{12}{100}x=x-0.12x=0.88x$$
    $$\textbf{Step 2: Calculating the cost for the }\mathbf{2^{nd}}\textbf{ year}$$
                     $$\text{The value reduces to}$$
                     $$=0.88x-\dfrac{12}{100}0.88x=0.88x\times(1-0.12)=0.7744x$$
                    $$\implies 0.7744x=2640$$
                    $$\implies x=3409$$
    $$\textbf{Hence, The original value is Rs.3409}$$
  • Question 7
    1 / -0

    Directions For Questions

    Saurabh invests Rs. $$48,000$$ for $$7$$ year at $$10\%$$ per annum compound interest.

    ...view full instructions

    Calculate the amount at the end of the second year.
    Solution
    Given,
    Sum $$(P)=Rs.48000$$
    Rate $$=10\%$$
    Time $$=2\ year$$
    $$Amount=P\left(1+\dfrac{R}{100}\right)^t$$
    $$= 48000\left(1+\dfrac{10}{100}\right)^2$$
    $$= 48000\times \dfrac{110}{100}\times \dfrac{110}{100}\\=Rs.58080$$
  • Question 8
    1 / -0
    A shopkeeper announces a discount of $$15\%$$ on his goods. If the marked price of an article, in his shop is $$Rs. 6,000$$; how much a customer has to pay for it, if the rate of Sales Tax is $$10\%$$?
    Solution
    Given,$$M.P=Rs.6000$$
    Sales tax$$=10\%$$
    S.P including sales tax$$=Rs.(6000+\dfrac{10}{100}\times 6000)$$
                                          $$= Rs(6000+600)$$
                                          $$=Rs.6600$$
    Discount$$=15\%$$
    $$\therefore$$ S.P after discount$$=Rs.(6600-15\%  \ of\  6600)$$
                                     $$=Rs.( 6600- \dfrac{15}{100}\times 6600)$$
                                     $$=Rs.( 6600-990)$$
                                     $$=Rs.5610$$

    Hence, the customer has to pay $$Rs.5610$$

  • Question 9
    1 / -0

    Directions For Questions

    A trader buys an article for Rs. 1,700 at a discount of 15% on its printed price. He raises the printed price of the article by 20% and then sells it for Rs. 2,688 including sales tax on the new marked price. Find:

    ...view full instructions

    The rate of Sales Tax
    Solution
    Let the M.P =Rs.x
    C.P=Rs.1700
    $$\therefore x-15\% of x=1700$$
    $$\Rightarrow x-\frac{15}{100}x=1700$$
    $$\Rightarrow \frac{85x}{100}=1700$$
    $$\Rightarrow 85x=170000$$
    $$\Rightarrow x=\frac{170000}{85}=Rs.2000$$

    If he raised the printed  price of the article=20%
    $$\therefore$$ S.P of the article $$=2000+\frac{20}{100}\times 2000$$
    $$\Rightarrow 2000+400=Rs.2400$$
    S.P of  the article including the tax=Rs.2688
    Let the rate of sales tax=y%
    Then $$2400+y\%  of 2400=2688$$
    $$\Rightarrow \frac{y}{100}\times 2400=2688-2400$$
    $$\Rightarrow 24y=288$$
    $$\Rightarrow y=\frac{288}{24}=12$$%

  • Question 10
    1 / -0
    The catalogue price of an article is Rs. 20,000. The dealer allows two successive discounts 15% and 10%. If Sales Tax at the rate of 10%  is charged on the remaining amount. Find:
    The final total price that customer has to pay for the article.
    Solution
    M.P of the article =Rs.20000
    Discount=15% and 10%
    C.P after discount$$=20000\times \frac{85}{100}\times \frac{90}{100}=Rs.15300$$
    Rate of sales tax=10%
    Sales tax amount=10% of 15300$$=\frac{10}{100}\times 15300=Rs.1530$$
    Final price of the article$$=15300+1530=Rs.16830$$
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