Comparing Quantities Test

Result

Comparing Quantities Test - 53

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

A sum of $$Rs.\ 15,000$$ is invested for $$3$$ years at $$10 \%$$ per annum compound interest. Calculate the interest for the second year.

A
$$Rs.\ 1,680$$

B
$$Rs.\ 1,650$$

C
$$Rs.\ 1,710$$

D
$$Rs.\ 1,640$$
Question 2
1 / -0

The annual production in cement industry is subject to business cycles. The production increases for two consecutive years consistently by 18?

A
$$24$$ % increase

B
$$25$$ % increase

C
$$42$$ % increase

D
$$45$$ % increase

Solution

After every $$2$$ years $$18$$% increase/year third year $$12$$% decrease
Base year is $$2008$$
$$2008+2=2010$$
In $$2010,$$ effect$$=18+18=36$$
$$2010+1=2011$$
In $$2011$$, effect$$=36-12=24$$
$$2012$$ effect$$=24+18=42$$
$$\therefore$$ In $$2012$$, total effect will be $$42$$% increase.
Question 3
1 / -0

By selling on article for $$ Rs \ 950$$, a man loses $$ 5 \%$$. If he had sold it for $$Rs. 1,220$$, the gain would be

A
$$20 \%$$

B
$$22 \%$$

C
$$24 \%$$

D
$$26 \%$$

Solution

Selling price of article $$= 950$$ Rs, Loss $$= 5\%$$

We know that $$SP=CP-Loss$$

$$\Rightarrow 950=CP-5\%\ of\ CP$$

$$\Rightarrow 950=CP-0.05\times CP$$

$$\Rightarrow 950=0.95\times CP$$

$$\therefore CP=\dfrac{950}{0.95}=1000\ Rs$$

Now, Selling Price $$(SP)= 1220$$ Rs

Here $$SP > CP$$, there will be a profit.

$$\therefore$$ Profit $$=SP-CP=1220-1000=220\ Rs$$

$$\Rightarrow Profit\ percentage =\dfrac{Profit\times 100}{CP}=\dfrac{220\times 100}{1000}=22\%$$
Question 4
1 / -0

If SP of an article is $$\displaystyle\frac{5}{4}$$ of its CP then the profit percentage in the transaction is :

A
$$10$$

B
$$20$$

C
$$30$$

D
$$25$$

Solution

Let $$CP = x$$

Given that, $$SP=\dfrac{5}{4}CP=\dfrac{5x}{4}$$

$$\therefore profit = SP-CP=\dfrac{5}{4}SP-SP=\dfrac{SP}{4}=\dfrac{x}{4}$$

$$\therefore profit\ percentage=\dfrac{profit\times100}{CP}=\dfrac{\dfrac{x}{4}\times100}{x}=25\%$$
Question 5
1 / -0

Find the compound interest on Rs. $$70,000$$ for $$2$$ years, compounded annually at $$10\%$$ per annum.

A
$$14,400$$

B
$$14,700$$

C
$$14,300$$

D
$$14,100$$

Solution

Here,$$P=$$ Rs $$70000$$ , $$R=10\%\ p.a$$
interest for the first year $$=\cfrac{P\times R\times T}{100}$$
$$=\cfrac{70000\times 10\times 1}{100}$$
$$=$$ Rs $$7000$$
The amount after the first year $$=$$ Rs $$77000$$
Principal for the second year $$=$$ Rs $$77000$$
Interest for the second year $$=$$ Rs $$\cfrac{77000\times 10\times 1}{100}$$
$$=$$ Rs $$7700$$
The final amount $$=$$ Rs $$77000$$ + Rs $$7700$$
$$=$$ Rs $$84700$$
Compound interest $$= $$ Rs $$84700 -70000$$
$$=$$ Rs $$14700$$
Question 6
1 / -0

The amount on Rs. $$20,500$$ at $$7%$$ per annum compunded annually for $$2$$ years, is:

A
$$22470$$

B
$$23470$$

C
$$24470$$

D
$$25470$$

Solution

$$\Rightarrow$$ $$P=Rs.20,500,\,R=7\%$$ and $$T=2\,years$$

$$\Rightarrow$$ $$A=P(1+\dfrac{R}{100})^T$$

$$\Rightarrow$$ $$A=20500\times (1+\dfrac{7}{100})^2$$

$$\Rightarrow$$ $$A=20500\times (\dfrac{107}{100})^2$$

$$\Rightarrow$$ $$A=20500\times (1.07)^2$$

$$\Rightarrow$$ $$A=20500\times 1.1449$$

$$\therefore$$ $$A=Rs.23470.$$
Question 7
1 / -0

A sum of Rs $$15,000$$ is invested for $$3$$ years at $$13$$ % per annum compound interest. Calculate the approx interest for the second year.

A
$$2100$$

B
$$2200$$

C
$$2300$$

D
$$2400$$

Solution

Interst for the first year
$$=Rs \cfrac{15000\times 13\times 1}{100}$$
$$=Rs1950$$
Amount after the first year
$$=Rs15000+Rs1950$$
$$Rs16950$$
Interest for the second year
$$=Rs\cfrac{16950\times 13\times 1}{100}$$
$$=Rs2203.5$$
$$=Rs2200$$(approx)
Question 8
1 / -0

Raman borrowed Rs.$$1,20,000$$ for $$4$$ years at $$8$$ % per year compound interest. Calculate the final amount at the end of four years.

A
$$1,63,250$$

B
$$1,53,250$$

C
$$1,63,700$$

D
$$1,66,250$$

Solution

We have,
$$P=Rs.\ 120, 000$$
$$T=4\ years$$
$$R=8\%$$
$$A=?$$

We know that
$$A=P\left(1+\dfrac{R}{100}\right)^T$$

So,
$$A=120000\left(1+\dfrac{8}{100}\right)^4$$

$$A=120000\left(\dfrac{108}{100}\right)^4$$

$$A=120000\left(\dfrac{108\times 108\times 108\times 108}{100\times 100\times 100\times 100}\right)$$

$$A=12\left(\dfrac{11664\times 11664}{10000}\right)$$

$$A=Rs.\ 163258.675\approx Rs.\ 163250$$

Hence, this is the answer.
Question 9
1 / -0

A sum of Rs.$$15,000$$ is invested for $$3$$ years at $$13$$ % per annum compound interest. Calculate the compound interest.

A
$$6500.435$$

B
$$6689.245$$

C
$$6643.455$$

D
$$6276.585$$

Solution

We have,
$$P=Rs.\ 15000$$
$$T=3\ years$$
$$R=13\%$$
$$C.I=?$$

We know that
$$A=P\left(1+\dfrac{R}{100}\right)^T$$

$$A=15000\left(1+\dfrac{13}{100}\right)^3$$

$$A=15000\left(\dfrac{113}{100}\right)^3$$

$$A=15000\left(\dfrac{113\times 113\times 113}{100\times 100\times 100}\right)$$

$$A=15\left(\dfrac{113\times 113\times 113}{1000}\right)$$

$$A=Rs.\ 21,643.455$$

So, the compound interest
$$=21.643.455-15000=Rs.\ 6643.455$$
Question 10
1 / -0

Find the compound interest on Rs. $$2,000$$ for $$3$$ years, compounded annually at $$12\%$$ per annum.

A
$$764$$

B
$$810$$

C
$$820$$

D
$$850$$

Solution

Given: $$P=Rs\ 2000$$

$$T=3$$ years

$$R=12\%$$ p.a.

So, Interst for the first year $$=\cfrac{2000\times 12\times 1}{100}$$

$$=Rs\ 240$$

Amount after the first year $$=P+$$ Interest for the first year

$$=Rs.\ 2000+Rs.\ 240=Rs.\ 2240$$

Interst for the second year $$=\cfrac{2240\times 12\times 1}{100}$$

$$=Rs.\ 268.8$$

Hence, the amount after the second year $$=Rs.\ 2240+Rs.\ 268.8=Rs.\ 2508.8$$

Interst for the third year $$=\cfrac{2508.8\times 12\times 1}{100}$$

$$=Rs.\ 301.056$$

Amount after the third year $$=Rs.\ 2508.8+Rs.\ 301.056=Rs.\ 2809.856$$

Compound interest $$=$$ Final amount $$-$$ original amount

$$=Rs.\ 2809.856-Rs.\ 2000$$

$$=Rs.\ 809.856$$

$$\approx Rs.\ 810$$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Comparing Quantities Test - 53

Result

Comparing Quantities Test - 53

Score

-

Rank

-

SHARING IS CARING

Question 1

$$Rs.\ 1,680$$

$$Rs.\ 1,650$$

$$Rs.\ 1,710$$

$$Rs.\ 1,640$$

Question 2

$$24$$ % increase

$$25$$ % increase

$$42$$ % increase

$$45$$ % increase

Solution

Question 3

$$20 \%$$

$$22 \%$$

$$24 \%$$

$$26 \%$$

Solution

Question 4

$$10$$

$$20$$

$$30$$

$$25$$

Solution

Question 5

$$14,400$$

$$14,700$$

$$14,300$$

$$14,100$$

Solution

Question 6

$$22470$$

$$23470$$

$$24470$$

$$25470$$

Solution

Question 7

$$2100$$

$$2200$$

$$2300$$

$$2400$$

Solution

Question 8

$$1,63,250$$

$$1,53,250$$

$$1,63,700$$

$$1,66,250$$

Solution

Question 9

$$6500.435$$

$$6689.245$$

$$6643.455$$

$$6276.585$$

Solution

Question 10

$$764$$

$$810$$

$$820$$

$$850$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.