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Comparing Quantities Test - 54

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Comparing Quantities Test - 54
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  • Question 1
    1 / -0
    The discount is always on the _________.
    Solution
    The discount is always on the Market price.
  • Question 2
    1 / -0
    The value of a machine depreciates every year by $$5\%$$. If the present value of the machine be Rs. $$100,000$$, what will be its value after two years?
    Solution
    current value of Machine $$=Rs. 100,00$$

    After 1 year  
    value  decreased by $$5 \%$$

    value of Machine  is
    $$ Rs. 95 \% $$ $$of$$ $$100,000  $$ 

    $$\Rightarrow \dfrac{95}{100} \times 100,000 = Rs. 95,000$$ 

    After 2 years 

    again the value is  decreased by $$5 \%$$ from previous year' s Value 

    Now  value of Machine  is
    $$= 95 \% $$ $$of$$ $$95,000$$

    $$=  \dfrac{95}{100} \times  95,000$$ 

    $$=0.95\times  95,000 $$ 

    $$ = Rs. 90,250$$ is the value of machine at the of two years
  • Question 3
    1 / -0

    Directions For Questions

    Study the following table carefully to answer the question that follow.
    Number of Items Produced (P) and Sold (S) (in thousands) by five different Companies over the years
    YearCompanies
    ABCDE
    PSPSPSPSPS
    201012.51196.17.54.416.512.315.813
    20111511119.7159.613.510.51411.1
    201210.281310.41813.912914.212.2
    201397.514910.4710.7813.611.4
    20141411.315.512.112119.95.410.67
    201513.41016131713.211.28.29.85
    2016161416.214106.111108.94.9

    ...view full instructions

    The number of items sold by Company C in the year 2011 is $$9.6$$, what percent of the number of items produced by it in that year?
    Solution
    Required percentage
    $$=\cfrac { \text{Items sold by C in 2011} }{ \text{Items produced by C in 2011}} \times 100$$
    $$=\cfrac { 9.6 }{ 15 } \times 100=64$$%
  • Question 4
    1 / -0
    A particular sum was divided among A, B and C in the ratio $$2:6:7$$ respectively. If the amount received by A was Rs. $$4,908$$, what was the difference between the amounts received by B and C?
    Solution
    Amount received by A$$=$$ Rs. $$4908$$
    Amount received by B$$=\displaystyle\frac{4908}{2}\times 6=$$Rs.$$14724$$
    Amount received by C$$=\displaystyle\frac{4908}{2}\times 7=$$Rs. $$17178$$
    Required difference $$=17178-14724$$
    $$=$$Rs. $$2454$$.
  • Question 5
    1 / -0
    Direct tax is:
    Solution

    A direct tax is paid directly by an individual or organization to an imposing entity. A taxpayer, for example, pays direct taxes to the government for different purposes, including real property tax, personal property tax, income tax or taxes on assets so we can say direct tax is property tax.

  • Question 6
    1 / -0
    Aarati bought 10 dresses at Rs 6300. She paid Rs 200 extra as expenses. If she sold all the dresses at the cost of Rs 780 per dress, how much percentage profit or loss does she make?
    Solution
    Cost price of $$10$$ dresses is $$Rs.\ 6300$$ and expanses is $$Rs.\ 200$$.

    So, cost price after expanses$$=Rs.\ (6300+200)=Rs.\ 6500$$

    Also, selling price of $$1$$ dress is $$Rs.\ 780$$.

    Hence, selling prince $$10$$ dresses$$=10\times 780=Rs.\ 7800$$

    Now, $$SP>CP$$, so their will be net profit.

    So, profit percent is,

    $$Profit(\%)=\dfrac{7800-6500}{6500}\times 100=\dfrac{1300}{65}=20\%$$
  • Question 7
    1 / -0
    Sugar is bought at Rs. $$16.20$$ per kg and sold at Rs. $$17.28$$ per kg. The gain percent is ____________.
    Solution
    Cost Price (CP) of 1 kg of sugar $$= 16.20$$ Rs

    Selling Price (SP) of 1 kg of sugar $$=17.28$$ Rs

    $$Gain = SP-CP=17.28-16.20=1.08\ Rs$$

    $$Gain\ Percent=\dfrac{Gain\times100}{CP}=\dfrac{1.08\times100}{16.20}=\dfrac{20}{3}=6\dfrac{2}{3}\%$$
  • Question 8
    1 / -0
    The compound interest on Rs. $$100000$$ at $$20\%$$ per annum for $$2$$ years $$3$$ months, compound annually is ________.
    Solution
    Given, $$P=100000$$, $$r=0.2$$, $$n=2+\dfrac{1}{4}$$ (converting $$2$$ years $$3$$ months to years) $$=n=2.25$$
    Interest is compounded anually,
    For first year $$=100000\times 0.2\times 1=20000$$
    For second year $$P_{new }= 120000$$
    Interest $$=120000\times 0 .2\times 1=24000$$
    For last $$0.02544$$ year, $$p_{new}=144000$$
    Interest $$ = 144000\times 0.2\times 0.25=7200$$
    New amount $$=144000+7200 = 151200$$
    $$\text{Interest} = 151200+100000=51200$$
  • Question 9
    1 / -0
    Bhajan Singh purchased $$120$$ reams of paper at Rs. $$80$$ per ream. He spent Rs. $$280$$ on transportation, paid octroi at the rate of $$40$$ paise per ream and paid Rs. $$72$$ to the coolie. If he wants to have a gain of $$8\%$$, what must be the selling price per ream?
    Solution
    Total money he spent $$=(120\times 80)+(280+0.4)\times (120+72)$$ 
                                         $$=10000$$
    Let the selling price of paper per ream is $$x$$ then total $$S.P.=120x$$

    If he wants to have a gain of $$8\% $$.

    Then by using the formula $$P\%=\dfrac{S.P.-C.P.}{C.P.}\times100$$

    $$8=\dfrac{120x-10000}{10000}\times100$$

    $$\Rightarrow 120x=1.08\times 10000$$

    $$\Rightarrow x=90$$

    Therefore, selling price per ream is Rs. $$90$$.
  • Question 10
    1 / -0
    After allowing a discount of $$25\%$$ on the marked price of a shirt, it is sold for Rs. $$240$$. Find the marked price of the shirt. 
    Solution
    Let marked price be $$x$$
    Selling price $$=$$ Rs $$240$$
    Discount allowed on the shirt $$= 25\%$$

    $$\Rightarrow x - \dfrac{25 x}{100} = 240$$

    $$\Rightarrow \dfrac{75x}{100} = 240$$

    $$\Rightarrow x =$$ Rs. $$320$$
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