Comparing Quantities Test

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Comparing Quantities Test - 56

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Weekly Quiz Competition

Question 1
1 / -0

$$?\ \%\ of\ 250\ +\ 25\%\ of\ 68 = 67$$

A
10

B
15

C
20

D
25

Solution

solution:
$$\dfrac{x}{100}$$x 250 + $$\dfrac{25}{100}$$ x 68 = 67
$$\dfrac{x}{100}$$x 250 + 17 = 67
$$\dfrac{x}{100}$$ x 250 = 50
$$\dfrac{x}{100}$$ x =$$\dfrac{50}{250}$$
$$\dfrac{x}{100}$$ x =$$\dfrac{1}{5}$$
$$x=20$$
hence the correct opt: C
Question 2
1 / -0

A customized jewellery was sold at Rs$$1000$$ with $$90\%$$ discount on the 'making charges'. If the payment made for making charges was $$Rs100$$, what was the approximate rate of discount on the product?

A
$$35$$

B
$$45$$

C
$$47$$

D
$$90$$

Solution

SP of jewellery include Rs$$100$$ making charges = $$1000$$
Where cost of jewellery = Rs $$900$$
After $$90\%$$ discount, $$10\%$$ of making charge = Rs$$100$$
Let making charge be = $$x$$
$$\dfrac{10x}{100} = 100$$
$$x = 1000$$
Total CP of jewellery = $$1000+900 = Rs 1900$$
Overall discount = $$\dfrac{900}{1900}\times100 = 47\%$$ approx
Question 3
1 / -0

A shop gives $$15$$% discount on the purchase of a T.V. If paid for a cash immediately, a further discount of $$12$$% is given. If the marked price is Rs. $$15,000$$ ,what is the price of the T.V if cash purchase is made?

A
Rs. $$11,475$$

B
Rs. $$11,220$$

C
Rs. $$12,750$$

D
Rs. $$10,950$$

Solution

Price of TV$$=15000$$
After successive discount of $$15 \%$$ and $$12 \ $$% ,
We have $$ 15000\times \left( 1-\cfrac { 15 }{ 100 } \right) \times \left( 1-\cfrac { 12 }{ 100 } \right) $$
$$=Rs.11220$$
Question 4
1 / -0

What is 25% of 25% equal to ?

A
6.25

B
0.625

C
0.0625

D
0.00625

Solution

solution:
$$\Rightarrow \dfrac{25}{100}$$ x $$\dfrac{25}{100}$$

$$\Rightarrow \dfrac{625}{10000}$$
$$\Rightarrow$$ 0.0625
hence the correct opt: C
Question 5
1 / -0

$$P$$ sells a table to $$Q$$ at a profit of $$10$$% and $$Q$$ sells it to $$R$$ at a profit of $$12$$%. If $$R$$ pays Rs. $$246.40$$ for it, then how much had $$P$$ paid for it?

A
$$200.00$$

B
$$300.00$$

C
$$248.00$$

D
$$346.00$$

Solution

Let $$P$$ paid for table $$=$$ Rs. $$P$$
After all $$R$$ paid =Rs. $$246.40$$
According to the question,
$$246.40=P\left[ \cfrac { 110 }{ 100 } \right] \left[ \cfrac { 112 }{ 100 } \right] $$
$$P=\cfrac { 246.40\times 100\times 100 }{ 110\times 112 }$$
$$=\cfrac { 246400 }{ 11\times 112 }$$
$$ =Rs.200$$
Question 6
1 / -0

The compound interest on Rs. 5,000 for two years at 4% is

A
Rs. 400

B
Rs. 408

C
Rs. 420

D
Rs. 440

Solution

SOLUTION:
The formula for compound interest is:
$$A=P (1+\dfrac{r}{n})^{nt}$$
$$A=5000(1+\dfrac{4}{100})^{2}$$
$$A= 5408$$
$$interest = P -A = 408$$
hence the correct opt: B
Question 7
1 / -0

A, B, C enter into partnership. A invests some money at the beginning, B invests double the amount after $$6$$ months and C invests thrice the amount after $$8$$ months. If the annual profit is Rs$$27,000$$. C's share is (in Rs)

A
$$11,250$$

B
$$9,000$$

C
$$10,800$$

D
$$8,625$$

Solution

Let the amount A invest is Rs$$x$$.
Time period of investment of A is $$12$$ months.
Amount B invest is Rs$$2$$x.
Time period of investment of B is $$6$$ months.
Amount C investment is Rs$$3$$x.
Time period of investment of C is $$4$$ months.
Profit is divided in the ratio = Amount of investment \times Time period of investment
$$P_A : P_B : P_C = x \times 12 : 2x \times 6 : 3x \times 4$$
=$$12 x : 12 x : 12 x$$
=$$1 : 1 : 1$$
C's share of profit = $$\dfrac{1}{3} \times 27000 = 9000$$
Question 8
1 / -0

Choose the correct answer from the alternative given.
If the annual rate of simple interest increases from 10% to 12.5% . A mans yearly income increases by Rs. 1250. his principal (in rupees) is:

A
50,000

B
45,000

C
60,000

D
65,000

Solution

Change in Rate of interest= $$\left ( \dfrac{25}{2} - 10 \right )\%= \dfrac{5}{2}\%$$
According to the question, $$\dfrac{5}{2}$$% of principal = Rs. 1250
Hence, Principal = $$\dfrac{1250 \times 2 \times 100}{5}$$ = Rs. 50000
Question 9
1 / -0

If some articles are bought at prices ranging from Rs. 200 to Rs. 350 and are sold at prices ranging from Rs. 300 to Rs. 425, what is the maximum possible profit that might be made in selling 16 such articles?

A
Rs. 3600

B
Rs. 1200

C
Rs. 800

D
Rs. 400

Solution

Maximum profit will be if we purchase in minimum
price & sell in maximum price.
Minimum price for purchasing = Rs 200
Maximum price for purchasing = Rs 425
Net profit on 1 article $$ 425 - 200 = Rs\, 225 $$
Net profit on 16 article $$ = 225 \times 16 = Rs \,3600 $$
Question 10
1 / -0

After allowing $$15$$% discount, the selling price of a radio becomes $$Rs. 255$$. The marked price is

A
$$Rs. 500$$

B
$$Rs. 600$$

C
$$Rs. 400$$

D
$$Rs. 300$$

Solution

Let the marked price of Radio be $$Rs. x$$.
After giving $$15\%$$ discount, the selling price will be $$0.85x$$
According to the question, $$0.85x = 255$$
$$x=\dfrac{255}{0.85}$$
$$x = Rs. 300$$
Hence, the marked price of Radio is $$Rs. 300$$.

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Re-Attempt Weekly Quiz Competition

Comparing Quantities Test - 56

Result

Comparing Quantities Test - 56

Score

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Rank

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SHARING IS CARING

Question 1

10

15

20

25

Solution

Question 2

$$35$$

$$45$$

$$47$$

$$90$$

Solution

Question 3

Rs. $$11,475$$

Rs. $$11,220$$

Rs. $$12,750$$

Rs. $$10,950$$

Solution

Question 4

6.25

0.625

0.0625

0.00625

Solution

Question 5

$$200.00$$

$$300.00$$

$$248.00$$

$$346.00$$

Solution

Question 6

Rs. 400

Rs. 408

Rs. 420

Rs. 440

Solution

Question 7

$$11,250$$

$$9,000$$

$$10,800$$

$$8,625$$

Solution

Question 8

50,000

45,000

60,000

65,000

Solution

Question 9

Rs. 3600

Rs. 1200

Rs. 800

Rs. 400

Solution

Question 10

$$Rs. 500$$

$$Rs. 600$$

$$Rs. 400$$

$$Rs. 300$$

Solution

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