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Comparing Quantities Test - 59

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Comparing Quantities Test - 59
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  • Question 1
    1 / -0
    A manufacturer reckons that the value of a machine which costs him Rs. $$15025,$$ will depreciate each year by $$20$$%. Find the estimated value at the end of $$5$$ years.
    Solution

    Value after 5 years $$=15025\times(1-(\dfrac{20}{100})^5)$$

                                     $$=15025\times\>0.32768=Rs.4923.39$$

  • Question 2
    1 / -0
    Mr. X, a business man had the income in the year $$2000$$, such that he earned a profit of $$20$$% n his investment in the business. In the year $$2001$$, his investment was less by Rs. $$5000$$ but still had the same income (Income=Investment+Profit) as that in $$2000$$. Thus, the percent profit earned in $$2001$$ increased by $$6$$%. What was his investment in $$2000$$?
    Solution
    Let investment of Mr. X be 'I' in $$2000$$
    Profit in year $$2000=20$$% on investment
    $$=\cfrac { I }{ 5 } $$
    $$\therefore $$ Total income in year $$2000=I+\cfrac { I }{ 5 } $$
    $$=\cfrac { 6I }{ 5 } $$
    Investment of Mr. X in $$2001=(I-5000)$$
    Income is same in both $$2000$$ and $$2001$$
    $$\therefore (I--5000)+P=\cfrac { 6I }{ 5 } $$, P is iprofit in year $$2001$$
    $$P=\cfrac { I }{ 5 } +5000$$
    Profit percent increased by $$6$$%, $$\therefore $$ New profit percent $$20+6=26$$%
    $$\cfrac { \cfrac { I }{ 5 } +5000 }{ I-500 } =\cfrac { 26 }{ 100 } \Rightarrow 20I+5000(100)=26I-26(5000)$$
    $$\Rightarrow 6I=(126)5000$$
    $$\therefore I=$$Rs. $$1,05,000$$
  • Question 3
    1 / -0
    A shopkeeper cheats to the extent of 10% while buying as well as selling, by using false weights . His total gain is :
    Solution
    So let, while buying Rs paid for n items.
    But Rs made gain of 10% .Thus Rs. received
    $$ 1.1 x$$ items. Now on selling again Rs.
    made $$ 1.1(1.1x)= 1.21x $$
    So,
    the net profit Rs moles = $$ \left ( \dfrac{1.21x}{x} - 1 \right )\times 100 \% $$
    $$ = 21 \%$$

  • Question 4
    1 / -0
    Hemant sold 10 sarees for a total profit of Rs.460 and 12 sarees for a total profit of Rs. 144. At what profit per saree should he sell the remaining 20 sarees so that he gets an average profit of Rs. 18 per saree ?
  • Question 5
    1 / -0
    A house and a shop were sold for Rs. 1 lakh each. In this transaction, the house sale resulted into 20% loss whereas the shop sale resulted into 20% profit. The entire transaction resulted in:
  • Question 6
    1 / -0
    The price of a scooter is $$Rs.14000$$. If it depreciates by $$2\% $$ of its value at the beginning of each year. Find the sale value after $$4$$ years.
    Solution

    Given that

    Original value of the scooter $$=Rs.14000$$

    Rate of depreciation   $$=2$$%

    The value of the scooter after $$4$$  years

    $$ =14000\times {{\left( 1-\dfrac{2}{100} \right)}^{4}} $$

    $$ =14000\times {{\left( 0.98 \right)}^{4}} $$

    $$ =14000\times 0.92236816 $$

    $$ =12913.154 $$

    Thus, the value of the scooter after $$4$$  years $$=Rs\,\,12913.154$$

    Hence, this is the answer.

  • Question 7
    1 / -0
    The lebelled price of a cupboard is $$Rs. 6500$$. The shopkeeper sold it by giving $$5%$$ discount on the labelled price and earned a profit of $$15%$$. What approximately is the cost price of the cupboard?
  • Question 8
    1 / -0
    If Aparna got Rs.25 discount on purchasing a book for Rs.225, then the discount percentage is :
    Solution
    Price of the book $$= Rs. 225$$
    Discount $$Rs. 25$$
    Actual price $$= Rs. \left( 225 + 25 \right) = Rs. 250$$
    Discount $$\% = \cfrac{25}{250} \times 100 = 10 \%$$
    Hence the discount percentage is $$10 \%$$.
    Hence the correct answer is $$\left( C \right) 10 \%$$.
  • Question 9
    1 / -0
    $$12$$ Copies of book were sold for $$Rs. 1800$$ thereby gaining cost price of $$3$$ copies. The cost price of a copy of the book is
    Solution
    Let Cost price of $$1$$ book $$=x$$
    Selling price of $$12$$ books $$=Rs.1800$$
    Gain $$=3x$$
    Selling price of $$12$$ book -Cost price of $$12$$ books = Gain 
    $$1800-12x=3x$$
    $$1800=12x+3x$$
    $$1800=15x$$
    $$x=120$$
    $$\therefore$$ Cost of $$1$$ book $$=Rs\ 120$$
  • Question 10
    1 / -0
    If selling price = $$Rs.900$$. Discount is $$20\%$$, then find the market price.
    Solution
    Let the market price be $$x$$,

    According to question, Discount is $$20$$%,

    So,  $$x-\dfrac{20}{100}x=SP$$

    $$\implies \dfrac{4x}{5}=900$$

    $$\implies x=1125$$

    Hence , Market Price $$=Rs.\ 1125$$
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