Comparing Quantities Test

Result

Comparing Quantities Test - 62

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

If a mobile costs Rs. $$2786$$, then $$257$$ mobiles costs?

A
Rs. $$716002$$

B
Rs. $$4279$$

C
Rs. $$72002$$

D
Rs. $$716232$$

Solution

The cost of $$1$$ mobile phone is $$Rs. 2786$$
$$\Rightarrow$$ The cost of $$257$$ mobile phone are $$Rs \left( 257\times 2786\right)$$
$$=Rs. 7,16,002$$
Hence, the answer is $$Rs. 7,16,002.$$
Question 2
1 / -0

Rani bought a piece of cloth for $$Rs.950$$ and spend $$Rs.300$$ on designing it. At what price should she sell it to make $$30$$% profit?

A
$$1525$$

B
$$1625$$

C
$$1600$$

D
$$1500$$

Solution

Total price of cloth $$= 950 + 300$$

$$= Rs. 1250$$

Let she sell in $$Rs. x$$

$$Profit = \dfrac {x - 1250}{1250} \times 100 = 30$$

$$10x = 13\times 1250$$

$$x = 1625$$.
Question 3
1 / -0

Calculate the amount and compound interest on
(i) INR $$10800$$ for $$3$$ years at $$12\dfrac{1}{2}\% $$ per annum compounded annually .

A
$$4555.25$$

B
$$4050.42$$

C
$$4577.34$$

D
$$4566.20$$

Solution

The amount after $$n$$ years compounded annually is given as,
$$A=P\left(1+\dfrac{r}{100}\right)^n$$
Where,
$$P=$$Principal
$$r=$$ rate of interest
According to the given condition,

Amount After three years $$=10800\left({1}+{\dfrac{12.5}{100}}\right)^3$$

$$=10800\left (\dfrac{112.5}{100}\right)^3\\$$
$$=15377.34$$

compound interest $$=15377.34-10800$$
$$=Rs\ 4577.34$$
Question 4
1 / -0

To get $$55\%$$ of a number, the number should be multiplied by

A
$$\dfrac {11}{20}$$

B
$$3.5$$

C
$$\dfrac {7}{50}$$

D
$$0.035$$

Solution
Question 5
1 / -0

Three hundred oranges were bought at Rs.40 per dozen and sold at a profit of Rs.25. The selling price of the oranges per dozen is

A
Rs. 45

B
Rs. 41.50

C
Rs. 41

D
Rs. 42.50

Solution

Let the selling price of the oranges per dozen $$= x$$

profit for selling one dozen oranges $$= S.P - C.P=(x - 40)$$

$$300$$ oranges $$= 25$$ dozen orange

profit for $$25$$ dozen $$= 25 (x - 40)$$

$$25 = 25(x - 40)$$

$$1 = x - 40$$

$$x = 41$$
Question 6
1 / -0

The owner of an electronics shop charges his customer $$22$$% more then the cost price. If a customer paid $$Rs.10980$$ for a DVD player then what was the cost price of a DVD player?

A
$$Rs. 8000$$

B
$$Rs.8800$$

C
$$Rs.9500$$

D
$$Rs.9000$$

Solution

Let the cost price of DVD player$$=x$$

owner will take$$=x+\dfrac{22}{100}\times x$$ from the customer,
According to the question;
$$\left(x+\dfrac{22}{100}x\right)=10980$$

$$\dfrac{122}{100}x=10980$$

$$x=\dfrac{10980\times 100}{122}$$

$$x=9,000 = $$ Cost price of DVD player
Question 7
1 / -0

Rice costing rs $$480$$ is needed for $$8$$ member for $$20$$ days. What is the cost of the rice required for $$12$$ members for $$15$$ days

A
$$240$$

B
$$540$$

C
$$440$$

D
$$520$$

Solution

Rice cost for $$8$$ members for $$20$$ days= $$480$$rs
$$8$$ members for $$1$$ day = $$480/20=24$$
$$1$$ member for $$1$$ day =$$24/8=3$$
$$12$$ members for $$1$$ day =$$12 \times 3=36$$
$$12$$ members for $$15$$ days =$$36 \times 15=540$$
Cost of rice required for $$12$$ members for $$15$$ days = Rs $$540$$
Question 8
1 / -0

A shopkeeper sells 20 article for Rs. 6000 and earns profit equal to the selling price of 5 articles. Find the cost price of each articles?

A
$$200$$

B
$$225$$

C
$$325$$

D
$$400$$

Solution

Given that,
A shopkeeper sells $$20$$ articles for $$Rs.\ 6000$$.
He earns of profit equal to the selling price of $$5$$ articles.

To find out,
The cost price of each article.

Selling price of $$20$$ articles $$=Rs.\ 6000$$

Hence, the selling price of one article $$=\dfrac{6000}{20}$$

$$=Rs.\ 300$$

Hence, profit $$=$$ selling price of $$5$$ articles $$=5\times 300$$

$$=Rs.\ 1500$$

We know that, $$C.P.=S.P.-\ profit$$

Hence, the cost price of $$20$$ articles $$=Rs.\ 6000-Rs.\ 1500$$

$$=Rs.\ 4500$$

So, the cost price of one article $$=\dfrac{4500}{20}$$

$$=Rs.\ 225$$

Hence, the cost price of each article is $$Rs.\ 225$$.
Question 9
1 / -0

Two continuous discounts of 4% on any thing should be equal to

A
8%

B
7.92%

C
7.84%

D
8.08%

Solution

Let initial cost $$=x$$
After first discount cost $$=x\dfrac{96}{100}$$
After second discount cost will be $$x\dfrac{96}{100}\times\dfrac{96}{100}$$
Net discount will be $$\dfrac{x-x\dfrac{96}{100}\times\dfrac{96}{100}}{x} \times 100=7.84$$ %
Question 10
1 / -0

Amit invested an amount of Rs.25000 in fixed deposit @C.I. 8% per annum for 2 years. What amount Amit will get?

A
Rs. 28240

B
Rs. 28540

C
Rs. 29240

D
Rs. 29160

Solution

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Comparing Quantities Test - 62

Result

Comparing Quantities Test - 62

Score

-

Rank

-

SHARING IS CARING

Question 1

Rs. $$716002$$

Rs. $$4279$$

Rs. $$72002$$

Rs. $$716232$$

Solution

Question 2

$$1525$$

$$1625$$

$$1600$$

$$1500$$

Solution

Question 3

$$4555.25$$

$$4050.42$$

$$4577.34$$

$$4566.20$$

Solution

Question 4

$$\dfrac {11}{20}$$

$$3.5$$

$$\dfrac {7}{50}$$

$$0.035$$

Solution

Question 5

Rs. 45

Rs. 41.50

Rs. 41

Rs. 42.50

Solution

Question 6

$$Rs. 8000$$

$$Rs.8800$$

$$Rs.9500$$

$$Rs.9000$$

Solution

Question 7

$$240$$

$$540$$

$$440$$

$$520$$

Solution

Question 8

$$200$$

$$225$$

$$325$$

$$400$$

Solution

Question 9

8%

7.92%

7.84%

8.08%

Solution

Question 10

Rs. 28240

Rs. 28540

Rs. 29240

Rs. 29160

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.