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Comparing Quantities Test - 67

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Comparing Quantities Test - 67
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  • Question 1
    1 / -0
    The cash difference between the selling prices of an article at a profit of $$4 \%$$ and $$6 \%$$ is Rs. $$3$$. The ratio of the two selling prices is:
    Solution
    Let the C.P be $$x$$
    Then S.P for $$4\%$$ profit $$=\dfrac {104 \times x}{100}$$
    S.P for $$6\%$$  profit $$=\dfrac{106x}{100}$$
    Then according to the question, we have
    $$\Rightarrow \dfrac{106x}{100}-\dfrac{104x}{100}=3$$
    $$\Rightarrow 2x=300$$
    $$\Rightarrow x=$$ Rs. $$150$$
    Then S.P for $$4\%$$ profit $$=\dfrac{104}{100}\times150 =$$ Rs. $$156$$
    S.P for $$6\%$$ profit $$=\dfrac{106}{100}\times 150=$$ Rs. $$159$$
    Ratio of both S.P $$=156:159=52:53$$
  • Question 2
    1 / -0
    $$83.33\% $$ of coins out of $$36$$ coins are $$20$$ paise coins and rest are $$10$$ paise coins which amounts to $$6.60$$. Find the number of $$10$$ paise coins.
    Solution

    Given : $$83.33$$% of $$36$$ coins are $$20$$ paisa coins

    $$83.33$$% of $$36 =\left( \cfrac { 83.33 }{ 100 }  \right) \times 36=30$$

    So, $$30$$ coins are $$20$$ paise coins and remaining $$(36-30)= 6$$ coins are $$10$$ paise coins.

    Value $$=30\times 20+6\times 10=660$$ Paise $$=Rs. 6.60$$, which is the given amount.

    $$\therefore $$ Number of $$10$$ paise coins are $$6$$.

  • Question 3
    1 / -0
    The population of a State increased from $$100$$ million to $$169$$ million in two decades. What is the average increase in population per decade?
  • Question 4
    1 / -0
    If the list price of a toy is reduced by $$Rs. 2$$ a person can buy $$2$$ toys more for $$Rs. 360$$. Find the original price of the toy.
    Solution

    Let the price of toys be $${{Rs}}\;x$$ and the number of toys be $$y$$. So,

    $$xy = 360$$

    $$y = \dfrac{{360}}{x}$$

    According to the question,

    $$\left( {x - 2} \right)\left( {y + 2} \right) = 360$$

    $$xy - 2y + 2x - 4 = 360$$

    $$360 - 2\left( {\dfrac{{360}}{x}} \right) + 2x - 4 = 360$$

    $${x^2} - 2x - 360 = 0$$

    $${x^2} - 20x + 18x - 360 = 0$$

    $$\left( {x - 20} \right)\left( {x + 18} \right) = 0$$

    $$x = 20,x =  - 18$$

    As the price cannot be negative, so the original price of the toy is $${{Rs}}\;20$$.

    Hence option (C) is correct

  • Question 5
    1 / -0
    If you plan to save Rs.$$5,000$$ with a bank an interest rate of $$8\%$$ what will be the worth of your amount after $$4$$ years if interest is compounded annually?
    Solution

  • Question 6
    1 / -0
    Ajay has purchased a second hand car by taking a loan of Rs$$5000$$ from bank at a rate of interest of $$8\%$$ for $$4$$ years. Calculate the total amount he will be paying to bank a loan of Rs$$5000$$ at the end of $$4$$ years
  • Question 7
    1 / -0
    If the price of a book is reduced by Rs. $$5$$, a person can buy $$5$$ more books for Rs $$300$$. Find the original list price of the book.
    Solution
    $$\textbf{Step 1: Stating given conditions}$$
                    $$\text{Given that the person can buy 5 more books for Rs.300 is the price is reduced by Rs.5}$$
                    $$\text{Let the original price of the book be }Rs.x$$
                    $$\Rightarrow \text{Number of books he can buy before the price is reduced}=\dfrac{300}{x}$$
                    $$\Rightarrow \text{Number of books he can buys after the price is reduced}=\dfrac{300}{x-5}$$
                    $$\Rightarrow \dfrac{300}{x}=\dfrac{300}{x-5}+5$$
    $$\textbf{Step 2: Solving}$$
                    $$\Rightarrow \dfrac{300}{x}+5=\dfrac{300}{x-5}$$
                    $$\Rightarrow 300[\dfrac1{x-5}-\dfrac1{x}]=5$$
                  
                    $$\Rightarrow 300[\dfrac{x-x+5}{x(x-5)}]=5$$
                    $$\Rightarrow x(x-5)=300$$
                    $$\Rightarrow x^2-5x-300=0$$
                    $$\Rightarrow x=\dfrac{5\pm\sqrt{1225}}{2}$$
                    $$\Rightarrow x=\dfrac{5\pm35}{2}$$
                    $$\Rightarrow x=Rs.20$$
    $$\textbf{Hence , the cost of one book is Rs.20. Option B is correct.}$$
  • Question 8
    1 / -0
    You need Rs.$$10,000$$ to buy a new television. If you have Rs.$$6,000$$ to invest at $$5$$ percent compounded annually, how long will you have to wait to buy the telivisions?
    Solution

  • Question 9
    1 / -0
    A shirt was sold at a profit of $$15\%$$. If its cost had been $$5\%$$ less and it had been sold for $$Rs.\; 21$$ less, then profit would have been $$10\%$$. Find the cost of the shirt.
    Solution

  • Question 10
    1 / -0
    Compound interest is 
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