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Algebraic Expressions and Identities Test - 17

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Algebraic Expressions and Identities Test - 17
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  • Question 1
    1 / -0
    $$(2x + 3y)^{2} = 4x^{2} + 9y^{2} + M$$, find M.
    Solution
    $$(2x + 3y)^{2} = 4x^{2} + 9y^{2} + 12xy$$,       ................. $$(a+b)^2= a^2+2ab+b^2$$

    hence, $$M = 12xy$$
  • Question 2
    1 / -0
    Find the product of the following pairs of monomials.
    $$4p\  \&\  0$$
    Solution
    $$4p, 0$$
    The product of the monomial pair is,
    $$=4\times p\times 0$$
    $$=0$$
  • Question 3
    1 / -0
    Find the product of the following pair of monomials.
    $$4p$$ & $$7p$$
    Solution
    Given: $$4p, 7p$$
    The product of the monomial pair is:
    $$=4\times p\times 7\times p$$
    $$=(4\times 7)\times(p\times p)$$
    $$=28p^2$$
  • Question 4
    1 / -0
    Find the product of the following pairs of monomials.
    $$4p, 7pq$$
    Solution
    $$4p, 7pq$$
    The product of the monomial pair is,
    $$=4\times p\times 7\times p\times q$$
    $$=(4\times 7)\times(p\times p\times q)$$
    $$=28p^2q$$
  • Question 5
    1 / -0
    Multiply: $$4p, q + r$$
    Solution
    $$4p, q + r$$
    $$=4p\times( q + r)$$
    $$=4pq+4pr$$
  • Question 6
    1 / -0
    The coefficient of $$x^2$$ in $$(2-3x^2) (x^2-5)$$ is :
    Solution
      $$(2-3x^2)(x^2-5)$$
    $$=-3x^4+17x^2-10$$
    Coefficient is a constant number multiplied with a variable.
    Here as $$17$$ is multiplied with $$x^2$$. so it becomes the coefficient.
    Hence, $$D$$ is the correct answer.
  • Question 7
    1 / -0
    Find the product of the following pairs of monomials.
    $$4p^3, 3p$$
    Solution
    $$4p^3, 3p$$
    The product of the monomial pair is,
    $$=4\times p\times p\times p\times 3\times p$$
    $$=(4\times 3)\times(p\times p\times p\times p)$$
    $$=12p^4$$
  • Question 8
    1 / -0
    Obtain the product of: $$xy, yz, zx$$
    Solution
    $$xy, yz, zx$$
    $$=xy\times yz\times zx$$
    $$=x^2y^2z^2$$
  • Question 9
    1 / -0
    Find the product of the following pairs of monomials
    $$4$$ & $$7p$$
    Solution
    $$\begin{aligned}{}4 \times 7p &= \left( {4 \times 7} \right)p\\ &= 28p\end{aligned}$$
  • Question 10
    1 / -0
    Obtain the product of: $$m, mn, mnp$$
    Solution
    $$m,  mn, mnp$$
    $$=m\times  mn\times mnp$$
    $$=m^3n^2p$$
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