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Algebraic Expressions and Identities Test - 32

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Algebraic Expressions and Identities Test - 32
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Weekly Quiz Competition
  • Question 1
    1 / -0
    2x×10y×3z=-2x\times 10y\times -3z=
    Solution
    2x×10y×3z=2×10×3×x×y×z-2x\times 10y\times -3z= -2\times 10\times -3\times x\times y\times z
                                   =60xyz=60xyz
  • Question 2
    1 / -0
    8yz×2xy=-8yz\times -2xy=
    Solution
    8yz×2xy=(8×2)×yz×xy-8yz\times -2xy = (-8\times -2)\times yz\times xy
                            =16×y2zx=16xy2z= 16\times y^2zx=16xy^2z
  • Question 3
    1 / -0
    2xy×7yz×9xz2xy\times 7yz\times 9xz
    Solution
    2xy×7yz×9xz=(2×7×9)×xy×yx×xz2xy\times 7yz\times 9xz= (2\times 7\times 9)\times xy\times yx\times xz
                                  =126x2y2z2=126x^2y^2z^2
  • Question 4
    1 / -0
    Find the product of x2yz×xy2z3x^2yz\times xy^2z^3.
    Solution
    x2yz×xy2z3=x2×y×z×x×y2×z3x^2yz\times xy^2z^3 = x^2\times y\times z\times x\times y^2\times z^3
            x2×x×y×y2×z×z3=x3y3z4x^2\times x\times y\times y^2\times z\times z^3=x^3y^3z^4
  • Question 5
    1 / -0
    Find the product (a+b)(a2b)(a+b)(a-2b), when a=1a=1, b=2 b=2.
    Solution
    =(a+b)(a2b) =a×a+b×(2b)+b×a+a×(2b)=(a+b)(a-2b) =a\times a+b\times (-2b)+b\times a+a\times (-2b)
                 =a22b2ab=a^2-2b^2-ab

    a=1,b=2a=1, b=2
               =12×221×2=1-2\times 2^2-1\times 2
               =9=-9
  • Question 6
    1 / -0
    Find the product x2×(2x+4xy+6z)\dfrac{x}{2}\times (2x+4xy+6z).
    Solution
    x2×(2x+4xy+6x)\dfrac{x}{2} \times(2x+4xy+6x)
    =x2×2x+x2×4xy+x2×6z=\dfrac{x}{2}\times 2x+\dfrac{x}{2}\times 4xy+\dfrac{x}{2}\times 6z
    =x2+2x2y+3xz=x^2+2x^2y+3xz
  • Question 7
    1 / -0
    Find the product 12m×(n+2p+3m)12m\times (n+2p+3m).
    Solution
    12m(n+2p+3m)12m(n+2p+3m)
    =12m×n+12m×2p+12m×3m=12m\times n +12 m\times 2p+12m\times 3m
    =12mn+24mp+36m2= 12mn+24mp+36m^2
  • Question 8
    1 / -0
    Multiply ((25x+y)(x+35y))\displaystyle \left((\frac{2}{5}x+y)(x+\frac{3}{5}y)\right)
    Solution
    ((25x+y)(x+35y)((\dfrac{2}{5}x+y)(x+\dfrac{3}{5}y)

    =25x2+625xy+xy+35x2\dfrac{2}{5}x^2+\dfrac{6}{25}xy+xy+\dfrac{3}{5}x^2

    =25x2+3125xy+35y2\dfrac{2}{5}x^2+\dfrac{31}{25}xy+\dfrac{3}{5}y^2


  • Question 9
    1 / -0
    Find the product (x+4)(x2+2x+1)(x+4)(x^2+2x+1)
    Solution
    (x+4)(x2+2x+1)=x×(x2+2x+1)+4(x2+2x+1)(x+4)(x^2+2x+1) = x\times(x^2+2x+1)+4(x^2+2x+1)
                                          =x3+2x2+x+4x2+8x+4=x^3+2x^2+x+4x^2+8x+4
                                          =x3+6x2+9x+4=x^3+6x^2+9x+4
  • Question 10
    1 / -0
    Which of the following is correct?
    Solution
    We know, (ab)2=a22ab+b2(a-b)^2=a^2-2ab+b^2.

    Then,
    (xy)2(x-y)^2
    =x22(x)(y)+y2=x^2-2(x)(y)+y^2 =x22xy+y2= x^2-2xy+y^2.

    To verify this, let us consider:
    (xy)2(x-y)^2 =(xy)=(x-y)(xy)(x-y)
    =x(xy)y(xy)=x(x-y)-y(x-y)
    =x2xyyx+y2=x^2-xy-yx+y^2
    =x2xyxy+y2=x^2-xy-xy+y^2
    =x22xy+y2=x^2-2xy+y^2.

    Hence, (xy)2(x-y)^2 =x22xy+y2= x^2-2xy+y^2

    Therefore, option BB is correct.
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