Force and Pressure Test

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Force and Pressure Test - 42

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Question 1
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The force between two charge bodies is called

A
muscular force

B
gravitational force

C
magnetic force

D
electrostatic force

Solution

The force between two charge bodies is called electrostatics force.
Hence,
option $$D$$ is correct answer.
Question 2
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The non-contact force is :

A
Force of reaction

B
Force due to gravity

C
Tension in string

D
Force of the friction

Solution

Force due to gravity
These are the forces that are experienced by the bodies without any physical contact with each other.
Question 3
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Which of the following is a contact force:

A
Electrostatic force

B
Gravitational force

C
Frictional force

D
Magnetic force

Solution

The frictional force is a contact.
These are the forces that act upon bodies when they are in physical contact with each other and one body is trying to slide over the other body.
Question 4
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A force is needed to :

A
Change the state of motion or state of rest of the body

B
Keep the body in motion

C
Keep the body stationary

D
Keep the velocity of body constant

Solution

Force is an effort that comes into use to Change the state of motion or state of rest of the body.
Question 5
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Which of these is an example of a non-contact force?

A
A toy car slides down the ramp

B
A bar magnet moves a paperclip without touching it

C
A child lifts a book lying on the table

D
A marble rolling on the carpet slows down

Solution

Magnetic force is a force, like gravity, that is able to act across a distance without touching an object that is attracted by it. So magnetic force is a non-contact force.
Question 6
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A perpendicular force is applied to a certain area and produces a pressure $$P$$. If the same force is applied to a twice bigger area, the new pressure on the surface is:

A
$$\dfrac{P}{2}$$

B
$$\dfrac{P}{3}$$

C
$$\dfrac{P}{4}$$

D
none

Solution

We know that pressure is force per unit area
$$\Rightarrow P=\frac{F}{A}$$
Given that for the former one , $$P=\frac{F}{A}$$
For the later one , the area is doubled and force is kept constant. So the pressure will become half
Therefore the pressure for new system is $$\frac{P}{2}$$
So the correct option is $$A$$
Question 7
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How could you place an empty bottle on a table so that it produces the greatest amount of pressure on the table?

A
Position $$1$$

B
Position $$2$$

C
Position $$3$$

D
All positions produce the same pressure.

Solution

We know,
$$Pressure=\dfrac{Force}{Area}$$

The empty bottle will exert equal force (weight of the bottle) in all three positions.
$$Pressure\propto \dfrac{1}{Area}$$

The area of contact is minimum for position $$2$$. Therefore, the empty bottle on the table produces the greatest amount of pressure on the table in position $$2$$.
Question 8
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Figure shows a siphon. The liquid is water. The beakers are open and the points A and B are at the surface of water, exposed to the air. The pressure difference $$P_B-P_A$$ between the points A and B

A
$$400 Nm^{-2}$$

B
$$3000 Nm^{-2}$$

C
$$1000 Nm^{-2}$$

D
Zero

Solution

Points A and B are at the surface of water. Hence, pressure at both points will be equal to the atmospheric pressure.

Hence, $$P_A=P_B=P_{atm}$$

$$\implies P_B-P_A= 0$$
Question 9
1 / -0

Tick the most appropriate answer.
If $$F$$ is a force acting normally on a surface of area $$A$$, then the pressure $$P$$ is given by:

A
$$\;F\times A$$

B
$$\;F+A$$

C
$$\;F/A$$

D
None of these.

Solution

We know that pressure is defined as force acting normally per unit area of a surface.
It is given by
$$Pressure=\dfrac{Force}{Area}=\dfrac{F}{A}$$
So option C is correct.
Question 10
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Which of the following activities uses the most force?

A

B

C

D

Solution

Friction opposes the relative motion between two surfaces in contact. It acts on both surfaces. Friction depends on the nature of surfaces in contact. For a given pair of surfaces, friction depends upon the state of smoothness of those surfaces. When one body rolls over another body, rolling friction comes into play. Rolling friction is smaller than sliding friction. Friction is reduced by using ball bearings.
The force will be maximum for the rough surface.