Sound Test

Result

Sound Test - 43

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Weekly Quiz Competition

Question 1
1 / -0

A man can hear the sound of frequency:

A
$$1\,Hz$$

B
$$1000\,Hz$$

C
$$200\,kHz$$

D
$$5\,MHz$$

Solution

Frequencies in the range $$20 \ Hz-20 \ kHz$$ are audible to humans. Hence, option B $$1000 \ Hz$$ is correct.
Question 2
1 / -0

Low sound such as normal breathing has loudness up to

A
$$5$$ decibel

B
$$20-30$$ decibel

C
$$10$$ decibel

D
$$50-60$$ decibel

Solution

Low sound such as normal breathing has loudness up to 10 decibel.
Question 3
1 / -0

The sound in the audible range is called

A
Ultra sonic

B
Sonic

C
Sub sonic

D
Light sound

Solution

The sound in the audible range is called Sonic.
Question 4
1 / -0

Relation between frequency and time period is

A
Time period = frequency

B
(Frequency) =$$2 \times$$ time period

C
Frequency $$ = \dfrac{1}{{\text{Time period}}} $$

D
Frequency $$ = \dfrac{{\text{Time period}}}{2} $$

Solution

The relation is $$f =\dfrac 1T$$ or $$frequency = \dfrac{1}{Time \ period}$$
Question 5
1 / -0

The sound of frequency less than $$20\ Hz$$ is known as:

A
Ultrasonic

B
Infrasonic

C
Audible

D
None of these

Solution

Sounds with frequencies below $$20\ Hz$$ are called infrasound. Infrasound is too low-pitched for humans to hear.
Question 6
1 / -0

A pendulum oscillates $$20$$ times in $$2$$ seconds then its time period is

A
$$0.01 $$ sec

B
$$ 0.001 $$ sec

C
$$ 0.02 $$ sec

D
$$ 0.1 $$ sec

Solution

Time period is $$T=\dfrac 2 {20} = 0.1 / sec$$
Question 7
1 / -0

In a clock, the time period of hour hand is :

A
$$1$$ hour

B
$$24$$ hour

C
$$12$$ hours

D
None of these

Solution

The hour hand of a clock completes one revolution in $$12\ hr$$. If the hour hand starts from $$12$$ in the noon then it will come back to $$12$$ at night. So it takes $$12\ hours$$ to complete one revolution.
Hence, the time period of the hound hand is $$12\ hours$$.
Question 8
1 / -0

The time period of the second hand in a clock is :

A
$$1$$ minute

B
$$1$$ hour

C
$$2$$ hours

D
$$24$$ hours

Solution

The seconds hand in a clock completes one full cycle in $$60 \ seconds = 1 \ minute$$

Hence, time period $$T = 1 \ minute$$
Question 9
1 / -0

The siren of an ambulance needs to be a loud and piercing sound. Therefore, its main characteristics should be:

A
high pitch and large amplitude

B
low pitch and large amplitude

C
high pitch and small amplitude

D
low pitch and small amplitude

Solution

For loud and piercing sound the siren needs to be high pitch and large amplitude An ambulance needs to be loud and piercing sound to give warnings on road. Sirens were created to notify drivers to give way to the ambulance as an emergency is waiving.
Option A is correct answer.
Question 10
1 / -0

.......... is the number of vibrations of a body in one second.

A
Frequency

B
Pitch

C
Time-period

D
Compression

Solution

Number of vibration of a body in one second is known as frequency of the body.
$$frequency = \dfrac{1}{time\ period}$$

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Re-Attempt Weekly Quiz Competition

Sound Test - 43

Result

Sound Test - 43

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SHARING IS CARING

Question 1

$$1\,Hz$$

$$1000\,Hz$$

$$200\,kHz$$

$$5\,MHz$$

Solution

Question 2

$$5$$ decibel

$$20-30$$ decibel

$$10$$ decibel

$$50-60$$ decibel

Solution

Question 3

Ultra sonic

Sonic

Sub sonic

Light sound

Solution

Question 4

Time period = frequency

(Frequency) =$$2 \times$$ time period

Frequency $$ = \dfrac{1}{{\text{Time period}}} $$

Frequency $$ = \dfrac{{\text{Time period}}}{2} $$

Solution

Question 5

Ultrasonic

Infrasonic

Audible

None of these

Solution

Question 6

$$0.01 $$ sec

$$ 0.001 $$ sec

$$ 0.02 $$ sec

$$ 0.1 $$ sec

Solution

Question 7

$$1$$ hour

$$24$$ hour

$$12$$ hours

None of these

Solution

Question 8

$$1$$ minute

$$1$$ hour

$$2$$ hours

$$24$$ hours

Solution

Question 9

high pitch and large amplitude

low pitch and large amplitude

high pitch and small amplitude

low pitch and small amplitude

Solution

Question 10

Frequency

Pitch

Time-period

Compression

Solution

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