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Light Test - 32

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Light Test - 32
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Weekly Quiz Competition
  • Question 1
    1 / -0
    We can see the objects only when:
    Solution
    Objects can only be seen when light falls onto the object and is reflected back to our eyes to form an image on the retina.
  • Question 2
    1 / -0
    Light shows:
    Solution
    Light shows Rectilinear propagation.
    Rectilinear Propagation of Light is the tendency of light to travel in a straight line.
  • Question 3
    1 / -0
    A narrow stream of light is called as :
    Solution
    Ray of light is defined as each of the lines in which light may seem to stream from the sun or any luminous body or pass through a small opening. A narrow beam of light is made up of several rays.
  • Question 4
    1 / -0
    A point source of light is placed in front of a plane mirror, then :
    Solution
    The image of a point source in plane mirror will be a virtual point image, behind the mirror. So the reflected rays should meet at this point when produced backwards.
  • Question 5
    1 / -0
    We cannot see anything in a dark room because:
    Solution
    We can only see objects when light falls into are eyes after being reflected from the objects.
  • Question 6
    1 / -0
    Which of the following is an example of a self-luminous body?
    Solution
    Self-luminous bodies are those bodies that produce light of their own.
    Sun has its own light.
  • Question 7
    1 / -0
    We are able to see objects because 
    Solution
    We can only see objects when light reflected from the objects falls on our eyes.
  • Question 8
    1 / -0
    Two mirrors M1 and M2 are placed at right angle to each others as shown. The total number of images of an object 'O' that can be seen are

    Solution
    When two plane mirrors are inclined to each other at an angle $$\theta $$  then no. of images formed, 

    is given by, $$ n = \left ( \dfrac{360^{\circ}}{\theta } -1 \right )$$

    now, if $$\dfrac{360^{\circ}}{\theta }$$ is an even integer,

    Number of image $$ = \dfrac{360^{\circ}}{90^{\circ} } - 1 = 4 - 1= 3$$
  • Question 9
    1 / -0
    Which of the following statements is true?
    Solution
    A) The angle of incidence is equal to the angle of reflection.

    B) The incident ray, the reflected ray, and the normal drawn at the point of incidence lie in the same plane.

    C) Virtual images cannot be caught on the screens.

    D) Convex mirrors always form virtual images.
  • Question 10
    1 / -0
    If the angle of incidence is $$80^{\circ}$$, what will be the angle of reflection with respect to the normal drawn perpendicular at the point of reflection?
    Solution
    The angle off incidence and the angle of reflection are measured with respect to the normal drawn at the point of reflection.
    And, as per laws of reflection, the angle of incidence is equal to the angle of reflection.
    So, angle of reflection, with respect to the normal drawn at the point of incidence is $$80^0$$.
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