Light Test

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Light Test - 38

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Weekly Quiz Competition

Question 1
1 / -0

Moon is visible to us because:

A
it reflects light

B
it refracts light

C
it emits light

D
it absorbs light

Solution

The moon is not a source of light. When sunlight falls on the moon, it reflects those light. These reflected lights reach our eyes and create the image of the moon, making it visible.
Question 2
1 / -0

If the angle of incidence on a plane mirror is $$\displaystyle { 45 }^{ o }$$. What will be its angle of reflection?

A
$$\displaystyle { 35 }^{ o }$$

B
$$\displaystyle { 45 }^{ o }$$

C
$$\displaystyle { 135 }^{ o }$$

D
$$\displaystyle { 145 }^{ o }$$

Solution

According to laws of reflection, angle of incidence is equal to angle of reflection. So, the angle of incidence being $$45^0$$, the angle of reflection is also $$45^0$$.
Question 3
1 / -0

If the angle between incident ray and normal is $$\displaystyle { 30 }^{ o }$$.what will be the angle of incidence?

A
$$\displaystyle { 60 }^{ o }$$

B
$$\displaystyle { 30 }^{ o }$$

C
$$\displaystyle { 90 }^{ o }$$

D
$$\displaystyle { 150 }^{ o }$$

Solution

The angle between incident ray and normal ray is called angle of incidence.
Thus, $$\text{The angle of incidence}=30^o$$
Question 4
1 / -0

When the angle of reflection is $$\displaystyle { 60 }^{ 0 }$$, what will be the angle between the incident ray and the mirror?

A
$$\displaystyle { 30 }^{ o }$$

B
$$\displaystyle { 60 }^{ o }$$

C
$$\displaystyle { 90 }^{ o }$$

D
$$\displaystyle { 45 }^{ o }$$

Solution

Angle of reflection$$={60^0}$$
So, angle of incidence$$=$$ angle of reflection $$={60^0}$$
Glancing angle of incidence$$={90^0}-$$ angle of incidence$$={90^0}-{60^0}={30^0}$$
The angle between the incident ray and the mirror$$=$$ glancing angle of incidence $$={30^0}$$
Question 5
1 / -0

When the angle of reflection is $$\displaystyle { 40 }^{ o }$$, the angle between normal and the mirror will be :

A
$$\displaystyle { 40 }^{ o }$$

B
$$\displaystyle { 90 }^{ o }$$

C
$$\displaystyle { 45 }^{ o }$$

D
$$\displaystyle { 60 }^{ o }$$

Solution

Normal ray is always perpendicular to the mirror. So normal always makes an angle of $$\displaystyle { 90 }^{ o }$$ with the mirror irrespective of the angle of incidence or of angle of reflection.
Question 6
1 / -0

When the angle between incident ray and mirror is increased, the angle of reflection:

A
will decrease

B
will increase

C
will remain constant

D
will either increase or decrease

Solution

The angle between incident ray and mirror is known as the glancing angle of incidence.
Now,
glancing angle of incidence$$+$$angle of incidence$$=90^0$$
So, when the glancing angle of incidence increases, the angle of incidence decreases.
And, as angle of incidence$$=$$ angle of reflection, therefore, angle of reflection decreases when the angle of incidence decreases.
Question 7
1 / -0

What happens when you throw a ray of light on the mirror along the normal?

A
The ray that comes after reflection makes $$\displaystyle { 60 }^{ o }$$ with the mirror

B
The incident ray do not come back

C
The incident ray retraces its path

D
None of the above

Solution

When a ray is incident normally on a surface, after reflection, it retraces its path. The angle of incidence and that of reflection are both $$0^0$$ in this case.
Question 8
1 / -0

According to the laws of reflection, the angle of incidence is equal to the angle of reflection. This statement:

A
Holds good irrespective of shape of the reflecting surface

B
Holds good only for plane reflecting surface

C
Holds good only for curved reflecting surface

D
Never holds good

Solution

According to the laws of reflection, the angle of incidence is equal to the angle of reflection. The laws of reflection hold good whenever a reflection takes place, irrespective of the shape of the reflecting surface.

Question 9

1 / -0

Match the following

i. Cornea	a. Back surface of eye where image is formed
ii. Pupil	b. Coloured part of eye
iii. Retina	c. Membrane that refracts light and protects the eye
iv. Iris	d. Transparent opening of eye.Light passes through it

i-c ,ii-d,iii-a,iv-b

i-a,ii-c,iii-b,iv-d

i-d,ii-a,iii-b,iv-c

i-b,ii-c,iii-d,iv-a

Solution

Cornea is protective layer,it is transparent in nature.

Pupil is the transparent opening of the eye. It lets light to pass through it.
Iris is responsible for characteristic colour of the eye.
Retina is the image forming screen of the eye.

Question 10

1 / -0

Match the column:

a. optic nerve	i. coloured part of the eye
b. ciliary muscle	ii. refracts light and focuses a real image on the back of eye
c. lens	iii. it can increase or decrease the thickness of lens
d.iris	iv. carries information to the brain about light that strikes the retina

a-i,b-iii,c-iv,d-ii

a-ii,b-i,c-iv,d-iii

a-iii,b-iv,c-i,d-ii

a-iv,b-iii,c-ii,d-i

Solution

Optic nerve carries information from retina to brain.

Iris is the coloured part of eye. It changes in size to vary the amount of light entering through the pupil.

The lens of the eye forms a real,inverted image of the object on the inner coat of the eye. The screen of eye is called the retina.Eye lens is a convex lens.

Ciliary muscle is a muscle surrounding the eye that can increase or decrease the curvature of lens.

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Re-Attempt Weekly Quiz Competition

Light Test - 38

Result

Light Test - 38

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SHARING IS CARING

Question 1

it reflects light

it refracts light

it emits light

it absorbs light

Solution

Question 2

$$\displaystyle { 35 }^{ o }$$

$$\displaystyle { 45 }^{ o }$$

$$\displaystyle { 135 }^{ o }$$

$$\displaystyle { 145 }^{ o }$$

Solution

Question 3

$$\displaystyle { 60 }^{ o }$$

$$\displaystyle { 30 }^{ o }$$

$$\displaystyle { 90 }^{ o }$$

$$\displaystyle { 150 }^{ o }$$

Solution

Question 4

$$\displaystyle { 30 }^{ o }$$

$$\displaystyle { 60 }^{ o }$$

$$\displaystyle { 90 }^{ o }$$

$$\displaystyle { 45 }^{ o }$$

Solution

Question 5

$$\displaystyle { 40 }^{ o }$$

$$\displaystyle { 90 }^{ o }$$

$$\displaystyle { 45 }^{ o }$$

$$\displaystyle { 60 }^{ o }$$

Solution

Question 6

will decrease

will increase

will remain constant

will either increase or decrease

Solution

Question 7

The ray that comes after reflection makes $$\displaystyle { 60 }^{ o }$$ with the mirror

The incident ray do not come back

The incident ray retraces its path

None of the above

Solution

Question 8

Holds good irrespective of shape of the reflecting surface

Holds good only for plane reflecting surface

Holds good only for curved reflecting surface

Never holds good

Solution

Question 9

i-c ,ii-d,iii-a,iv-b

i-a,ii-c,iii-b,iv-d

i-d,ii-a,iii-b,iv-c

i-b,ii-c,iii-d,iv-a

Solution

Question 10

a-i,b-iii,c-iv,d-ii

a-ii,b-i,c-iv,d-iii

a-iii,b-iv,c-i,d-ii

a-iv,b-iii,c-ii,d-i

Solution

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