Surface Areas and Volumes Test -8

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Surface Areas and Volumes Test -8

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Weekly Quiz Competition

Question 1
1 / -0

The curved surface area of a cylinder and a cone is equal. If their base radius is same, then the ratio of the slant height of the cone to the height of the cylinder is

A
it is 2 : 1

B
it is 1 : 1

C
it is 1 : 2

D
it is 2 : 3

Solution

CSA of cone = CSA of cylinder

πrl = 2πrh

l= 2h

l: h= 2 : 1
Question 2
1 / -0

If the ratio of the radii of bases of two cones is 3 : 1 and the ratio of their heights is 1 : 3, then the ratio of their volumes is

A
it is 2 : 1

B
it is 1 : 2

C
it is 3 : 1

D
it is 1 : 3

Solution

volume of cone1 : volume of cone2

1/3 πr1²h1 : 1/3 π r2²h2

3² × 1 : 1² × 3

3 : 1
Question 3
1 / -0

The cost of digging a pit of dimensions 4.5m × 2.5m × 2.5m at the rate of Rs 20 per cubic metre is

A
Rs 1687.50

B
Rs 1125.

C
Rs 281.25.

D
Rs 562.50.

Solution

Cost of diging would be =( 4.5m × 2.5m × 2.5m) × 20

= Rs 562.50
Question 4
1 / -0

The volume of resulting cuboid formed when two cubes each of side 6 cm are joined end to end is

A
648 cm³.

B
432 cm³.

C
416 cm³.

D
864 cm³.

Solution

Volume of one cube = side³

= 6³

=216 cm³

so, volume of cuboid when two cubes are added = 2 × 216

= 432 cm³
Question 5
1 / -0

The number of litres that a cuboidal water tank of dimensions 6m × 5m × 4.5m can hold is

A
270000 l.

B
135000 l.

C
270 l.

D
135 l.

Solution

volume of water it can hold =Volume of water tank

= l×b×h

= 6×5×4.5

=135m³

= 135000 litres ( 1 m³ =1000 litres)
Question 6
1 / -0

The surface area of a cuboid whose length, breadth and height are 15 cm, 10 cm and 20 cm respectively is

A
650 cm².

B
1300 cm².

C
2600 cm².

D
1950 cm².

Solution

CSA of cuboid = 2( lb + bh + hl )

=2(15×10 + 10×20 + 20×15)

=2(150 + 200 + 300)

=2 × 650

= 1300 cm²
Question 7
1 / -0

The difference between the total surface area and the lateral surface area of a cuboid of length 20 cm, breadth 10 cm and height 40 cm is

A
800 cm².

B
400 cm².

C
600 cm².

D
200 cm².

Solution

TSA of cuboid = 2(lb + bh + hl), Lateral surface area of cuboid = 2h(l + b)

so , their difference is

= 2(lb + bh + hl) - 2(bh + hl)

=2(lb)

=2 × 10 × 20

= 400cm²

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Re-Attempt Weekly Quiz Competition

Surface Areas and Volumes Test -8

Result

Surface Areas and Volumes Test -8

Score

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Rank

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SHARING IS CARING

Question 1

it is 2 : 1

it is 1 : 1

it is 1 : 2

it is 2 : 3

Solution

Question 2

it is 2 : 1

it is 1 : 2

it is 3 : 1

it is 1 : 3

Solution

Question 3

Rs 1687.50

Rs 1125.

Rs 281.25.

Rs 562.50.

Solution

Question 4

648 cm3.

432 cm3.

416 cm3.

864 cm3.

Solution

Question 5

270000 l.

135000 l.

270 l.

135 l.

Solution

Question 6

650 cm2.

1300 cm2.

2600 cm2.

1950 cm2.

Solution

Question 7

800 cm2.

400 cm2.

600 cm2.

200 cm2.

Solution

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648 cm³.

432 cm³.

416 cm³.

864 cm³.

650 cm².

1300 cm².

2600 cm².

1950 cm².

800 cm².

400 cm².

600 cm².

200 cm².