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Statistics Test - 19

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Statistics Test - 19
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  • Question 1
    1 / -0
    In the class interval $$35 - 46$$, the lower limit is _____
    Solution
    For the class interval $$35 - 46$$, the lower limit is $$35$$ and upper limit is $$46$$
  • Question 2
    1 / -0

    Directions For Questions

    Use the table given below to find:
    Class IntervalFrequency
    $$30 - 34$$$$7$$
    $$35 - 39$$$$10$$
    $$40 - 44$$$$12$$
    $$45 - 49$$$$13$$
    $$50 - 54$$$$8$$
    $$55 - 59$$$$4$$

    ...view full instructions

    The upper and lower limits of the fifth class.
    Solution
    Class Interval         Frequency
    $$30 - 34$$$$7$$
    $$35 - 39$$$$10$$
    $$40 - 44$$$$12$$
    $$45 - 49$$$$13$$
    $$50 - 54$$$$8$$
    $$55 - 59$$$$4$$
  • Question 3
    1 / -0
    The value of $$\pi$$ upto $$50$$ decimal places is :
    $$3.14159265358979323846264338327950288419716933993751$$

    What is the frequency of digit $$0$$.
    Solution
    The given value of $$\pi$$ is
    $$3.14159265358979323846264338327950288419716933993751$$
    Digits after decimal will be considered for counting the frequency

    Digits             Frequency
      $$0$$                       $$1$$
      $$1$$                       $$5$$
      $$2$$                       $$5$$
      $$3$$                       $$9$$
      $$4$$                       $$4$$
      $$5$$                       $$5$$
      $$6$$                       $$4$$
      $$7$$                       $$4$$
      $$8$$                       $$5$$
      $$9$$                       $$8$$

    Hence, frequency of $$0$$ is $$1$$.






















  • Question 4
    1 / -0
    In the class interval $$35 - 46$$; the lower limit is $$35$$ and upper limit is _____
    Solution
    Class interval is defined by the lower limit- upper limit.
    Hence, for the class interval $$35 - 46$$
    The lower limit is $$35$$ and upper limit is $$46$$
  • Question 5
    1 / -0

    Directions For Questions

    The cost of $$250$$ articles is given below:
    Cost (in Rs.)     No. of articles
    less than $$20$$
    less than $$30$$
    less than $$40$$
    less than $$50$$
    less than $$60$$
    less than $$70$$
            $$22$$
            $$40$$
            $$75$$
          $$190$$
          $$228$$
          $$250$$         
    Construct a frequency distribution table for the data given above and answer the following:

    ...view full instructions

    How many articles have cost Rs. $$50$$ ?
    Cost (in Rs.) :$$10 - 20$$$$20-30$$$$30-40$$$$40-50$$$$50-60$$$$60-70$$
    Frequency :$$22$$ $$18$$$$35$$ $$115$$ $$38$$$$22$$
    Solution
    The frequency distribution table is -
    Cost (in Rs.) Class Interval        No. of articles(freq)
    $$10$$ to $$20$$$$22$$
    $$20$$ to $$30$$$$18$$
    $$30$$ to $$40$$$$35$$
    $$40$$ to $$50$$$$115$$
    $$50$$ to $$60$$ 
    $$38$$
    $$60$$ to $$70$$$$22$$

    The articles which cost Rs.$$50 = 38$$  
  • Question 6
    1 / -0
    The range of the data $$7, 13, 6, 25, 18, 20 , 16 $$ is _____
    Solution
    The data is: $$7,13,6,25,18,20,16$$
    Lowest value $$= 6$$
    highest value $$= 25$$
    Range $$=$$ Highest Value $$-$$ Lowest value $$= 25 - 6 = 19$$
  • Question 7
    1 / -0
    Find the class mark of the class $$11 - 19$$
    Solution
    Class interval : $$11-19$$
    Lower limit: $$11$$
    Upper limit: $$19$$
    Class Mark $$= \cfrac{\text{Lower} + \text{Upper}}{2}$$
    Class Mark $$= \cfrac{11 + 19}{2}$$
    Class Mark $$= 15$$
  • Question 8
    1 / -0
    Range of $$14, 12, 17, 18, 16$$ and $$x$$ is $$20$$. Find $$x$$ $$(x > 0)$$
    Solution
    Let  $$x$$ be the highest no. and here lowest no. is $$12$$
    Since, Range $$=$$ Highest value $$-$$ Lowest value
    $$\therefore  20 = x - 12 $$
    $$\therefore   x =32 $$
    $$\therefore $$ Option $$C$$ is correct.
  • Question 9
    1 / -0
    What is the average of squares of consecutive odd numbers between $$1$$ and $$13 $$?
    Solution
    The consecutive odd numbers from $$1$$ to $$13 = 3, 5, 7, 9, 11$$
    Thus required average = $$\displaystyle \frac{3^{2}+5^{2}+7^{2}+9^{2}+11^{2}}{5}=\frac{9+25+49+81+121}{5}=\frac{285}{5}=57$$
  • Question 10
    1 / -0
    Mean of the first six even numbers is
    Solution
    Formula used:
    $$Arithmetic\ mean= \dfrac{Sum\ of\ given\ numbers}{Total\ numbers}$$

    Apply the above formula, we get
    Mean$$=\displaystyle \frac{2+4+6+8+10+12}{6}$$
    = $$\displaystyle \frac{42}{6}=7$$
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