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Probability Test - 5

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Probability Test - 5
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  • Question 1
    1 / -0

    Two coins are tossed simultaneously. Then, the probability of getting at most one head is

    Solution

    Let E = event of getting atmost 1 head. Then, 
    E = {TH, HT, HH} and, therefore, n(E) = 3. 
    Therefore, P(getting atmost 1 head) = P(E) = n(E)/n(S) = ¾.

  • Question 2
    1 / -0

    Which of the following cannot be the empirical probability of an event ?

    Solution

    The empirical probability of an event cannot be greater than 1 and the value of 3/2 is1.5.

  • Question 3
    1 / -0

    A standard deck of 52 cards is shuffled. One card is drawn at random. The probability that the card is red or an ace is

    Solution

    Total number of card in a pack of well-shuffled cards = 52

    Number of red cards (including two aces) = 26

    Number of black aces = 2

    Total number of red cards and black aces = 26 +2 = 28

    The probability that the card is red or an ace = 28 / 52 = 7 / 13

  • Question 4
    1 / -0

    A fair die is rolled. Then, the probability of not rolling a number less than 5 is

    Solution

    Total number of outcomes = 6

    Chances of getting numbers less than 5 = 4 (1,2,3 and 4)

    Chances of  not getting numbers less than 5 = 6 - 4 = 2 (5, 6)

    The probability of not rolling a number less than 5 = 2 / 6 = 1 / 3

  • Question 5
    1 / -0

    One card is drawn from a well-shuffled deck of 52 cards. The probability of drawing an ace is

    Solution

    In a deck of playing cards, there are 52 cards.Therefore, the total number of possible outcomes = 52

    Total number of  aces = 4

    Number of favourable outcomes = 4

    The probability of drawing an ace = 4/52 = 1/13

  • Question 6
    1 / -0

    1000 tickets of a lottery were sold and there are 5 prizes on these tickets. If Ruchi purchased one lottery ticket, the probability of winning  a prize is

    Solution

    Number of possible outcomes = 1000

    Possibility of getting a prize = 5

    Probability of winning a prize = 5 / 1000 = 1 / 200

  • Question 7
    1 / -0

    A die is thrown once. The probability of getting a number 3 or 4 is

    Solution

    Number of  possible outcomes = 6

    Possibility of getting 3 or 4 = 2

    Probability of getting a number 3 or 4 = 2 / 6 = 1 / 3

  • Question 8
    1 / -0

    A die is thrown once. The probability of getting a number greater than 3 is

    Solution

    Total number of outcomes = 6

    Numbers greater than 3 = 3 (4, 5, 6)

    The probability of getting a number greater than 3 = 3 / 6 = 1 / 2

  • Question 9
    1 / -0

    Two coins are tossed simultaneously. The probability of getting at least one head is

    Solution

    Let E = event of getting at least 1 head. Then, 
    E = {HT, TH, HH} and, therefore, n(E) = 3. 
    Therefore, P(getting at least 1 head) = P(E) = n(E)/n(S) = ¾.

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