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Coordinate Geometry Test - 6

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Coordinate Geometry Test - 6
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Ordinate of a point is negative in

    Solution

    Since,sign of point in 3rd quadrant            is (—,—),

    And in 4th quadrant it is (+,—),

    So,Ordinate of a point is -ve only in 3rd and 4th quadrant

  • Question 2
    1 / -0

    Which of the following are the signs of abscissa and ordinate of a point in quadrant I ?

    Solution

    The signs of abscissa and ordinate of a point in quadrant I are both +ve i.e. (+,+)

  • Question 3
    1 / -0

    The signs of abscissa and ordinate of a point in quadrant II are:

    Solution

    Abscissa means just the horizontal axis i.e. x axis. Ordinate means just the vertical acis i.e. y axis. 

    x-corrdinate and y-corrdinate make a point. 

    The signs of abscissa and ordinate of a point in quadrant II are (−,+)

  • Question 4
    1 / -0

    The signs of abscissa and ordinate of a point in quadrant III are

    Solution

    The signs of abscissa and ordinate of a point in quadrant III are both —ve, 

    i.e, in quadrant III co-ordinates Of point is (—,—).

  • Question 5
    1 / -0

    The signs of abscissa and ordinate of a point in quadrant IV are

    Solution

    In Cartesian plane ,if co-ordinate of any point P is P(x,y),then

    X-coordinate is called abscissa of the point and,

    Y-coordinate is called ordinate of the point.

    The signs of abscissa and ordinate of a point in quadrant IV is (+,—)

  • Question 6
    1 / -0

    If A(2, 3) and B(-3, 4), then (abscissa of A) – (abscissa of B) is

    Solution

    Here we have, abscissa of A=2,

    And abscissa of B= —3,

    So,according to question,

    (abscissa of A) – (abscissa of B)

    =2 — (—3)

    =5

  • Question 7
    1 / -0

    If P(3, 9) and Q(-3, -4), then (abscissa of P) – (ordinate of Q) is

    Solution

    From the given data we have,

    Abscissa of P=3 and,

    Ordinate of Q=—4,

    So,according to question,

    (abscissa of P) – (ordinate of Q) 

    = 3 — (–4)

    =7

  • Question 8
    1 / -0

    Which of the following points lie on the line y = 3x – 4 ?

    Solution

    When we put x=2 in the given equation,

    Then, y = (3×2)–4

          y =6–4 = 2, so point is (2 ,2)satisfied the given equation, 

    Hence point (2,2) will lie on the               line y=3x—4

  • Question 9
    1 / -0

    Which of the following point does not lie on the line y = 2x + 3 ?

    Solution

    Let us put x=3 in the give equation,

    Then, y=2(3)+3

    y=6+3=9

    So, the point will be (3,9)

    For x=3, y=9. But in the given option, y=7

    So, the given point (3,7) will not lie on the line y=2x+3.

  • Question 10
    1 / -0

    The area of a triangle whose vertices are (0,0), (4,0) and (0,6) is:

    Solution

    We have a point (0,0) i.e. origin.

    A point (4,0) whose y-coordinate is zero.

    So, this point is having 4 units in x-axis=base (let)

    A point (0,6) i.e. 6 units in y-axis=height of a trianglea

    So,these point forms a right angle triangle

    so, Area of a triangle =½× Base × Height

    Area of a triangle = ½×6×4 =12 sq. units

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