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Lines and Angles Test - 24

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Lines and Angles Test - 24
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  • Question 1
    1 / -0
    The value of $$y$$ in the given figure is _____

    Solution
    Given, $$\angle ABC=115^{\circ}$$

    $$\angle ABC$$ and $$\angle CBD$$ form linear pair.

    So,
    $$\angle ABC+\angle CBD=180^{\circ}$$
    $$\Rightarrow 115^{\circ}+y^{\circ}=180^{\circ}$$
    $$\Rightarrow y^{\circ}=180^{\circ}-115^{\circ}$$
    $$\Rightarrow y^{\circ}=65^{\circ}$$

    Hence, the value of $$y$$ is $$65$$.
  • Question 2
    1 / -0
    Sum of two obtuse angle results in:
    Solution
    Obtuse angle ranges from $$\displaystyle { 90 }^{ o }$$ to $$\displaystyle { 180 }^{ o }$$
    So, sum of least obtuse angle is $$\displaystyle { 91 }^{ o }+{ 91 }^{ o }={ 182 }^{ o }$$, which is a reflex angle.
    Now, sum of maximum obtuse angle is $$\displaystyle { 179 }^{ o }+{ 179 }^{ o }={ 358 }^{ o }$$, which is also a reflex angle.

    Acute angle is the angle which is greater than $$\displaystyle { 0 }^{ o }$$ and less than $$\displaystyle { 90 }^{ o }$$.
    Obtuse angle is the angle which is greater than $$\displaystyle { 90}^{ o }$$ and less than $$\displaystyle {180 }^{ o }$$.
    Right angle is the angle which is equal to $$90^o$$.
    Reflex angle is the angle which is greater than $$\displaystyle {180}^{ o }$$ and less than $$\displaystyle {360 }^{ o }$$.
  • Question 3
    1 / -0
    Which of the following is not an obtuse angle ?
    Solution
    Acute angle is the angle which is greater than $$\displaystyle { 0 }^{ \circ }$$ and less than $$\displaystyle { 90 }^{ \circ}$$.
    Obtuse angle is the angle which is greater than $$\displaystyle { 90}^{ \circ }$$ and less than $$\displaystyle {180 }^{ \circ }$$.
    Right angle is the angle which is equal to $$90^{\circ}$$.
    Reflex angle is the angle which is greater than $$\displaystyle {180}^{ \circ }$$ and less than $$\displaystyle {360 }^{ \circ }$$.
    $$\therefore \displaystyle { 182 }^{ \circ }$$ is a reflex angle, so it is not an obtuse angle.
  • Question 4
    1 / -0
    A pair of angles with a common vertex and common arm are called
    Solution


    A pair of angles with a common vertex and common arm are called adjacent angles.

  • Question 5
    1 / -0
    Find the measure of the missing angle in the triangle below.

    Solution
    By angle sum property, the sum of angles is $$180^o$$.
    If we subtract the two given angles from $$ 180^0 $$, the result will be the missing angle which is $$ = 180^0 - 95^0 - 35^0 = 50^0 $$.
    Therefore, the missing angle is $$ 50^0 $$.
  • Question 6
    1 / -0
    If sum of two angles is $$\displaystyle { 90 }^{ o }$$. They will be:
    Solution
    By definition we know that two angles, the sum of whose measure is $$ { 90^o } $$ are called complimentary angles.
    Then, such angles are called complement of each other.

    E.g.: Let the measure of one complementary angle is $$58^o.$$

    $$\Rightarrow$$ Measure of other complementary angle $$=90^o-58^o$$ $$=32^o.$$

    $$\therefore$$ Measure of the complementary angle of $$ 58^{o}=32^o$$.

    Hence, $$ 58^{o}$$ and $$32^o$$ are complements of each other.

    That is, if the sum of two angles is $$90^o$$

    Therefore, option $$C$$ is correct.

  • Question 7
    1 / -0
    If one angle at a point is reflex angle, the other at that point may be :
    Solution
    We know, the angle formed at a point is $$\displaystyle { 360 }^{ o }$$. 
    When one of angle is reflex, it range from $$\displaystyle { 180 }^{ o }$$ to $$\displaystyle { 360 }^{ o }$$. 
    If angle is $$\displaystyle { 200 }^{ o }$$ then the other angle is $$\displaystyle { 160 }^{ o }$$, i.e obtuse angle. 
    If one reflex angle is $$\displaystyle { 300 }^{ o }$$ then other angle is $$\displaystyle { 60 }^{ o }$$ i.e acute angle.
    Hence, the option $$D$$ is correct.
  • Question 8
    1 / -0
    Two angles are supplementary, if one of them is $$\displaystyle { 49 }^{ o }$$. Find the other angle?
    Solution
    Since, two angles are supplementary their sum is $$\displaystyle { 180 }^{ o }$$
    $$\displaystyle \angle 1+\angle 2={ 180 }^{ o }$$
    $$\displaystyle { 49 }^{ o }+\angle 2={ 180 }^{ o }$$ (As one of the angle is $$\displaystyle { 49 }^{ o }$$
    $$\displaystyle \angle 2={ 180 }^{ o }-{ 49 }^{ o }$$
    $$\displaystyle ={ 131 }^{ o }$$
  • Question 9
    1 / -0
    Which of the following is a reflex angle?
    Solution
    We know, reflex angle must be between $$\displaystyle { 180 }^{ o }$$ and $$\displaystyle { 360 }^{ o }$$. It can't be equal to $$\displaystyle { 180 }^{ o }$$ or $$\displaystyle { 360 }^{ o }$$ as these are straight and complete angle, respectively.

    Here, only $$204^o$$ is greater than $$180^o$$ and less than $$360^o$$.
    Therefore, option $$C$$ is correct.
  • Question 10
    1 / -0
    In the figure aove, $$C$$ is the intersection of $$\bar { AD } $$ and $$\bar { BE } $$. If it can be determined, what is the measure of $$\angle BAC$$?

    Solution
    $$\angle BCA=\angle DCE$$  (Vertically opposite angles)
    $$\Rightarrow \angle BCA=45^{\circ}$$
    Now in $$\triangle ABC$$  using angle sum property
    $$\angle BAC+\angle CBA+\angle BCA=180^{\circ}$$
    $$\Rightarrow \angle BAC+{ 35 }^{ \circ  }+{ 45 }^{ \circ  }={ 180 }^{ \circ  }\\ \Rightarrow \angle BAC={ 180 }^{ \circ  }-{ 80 }^{ \circ  }\\ \Rightarrow \angle BAC={ 100 }^{ \circ  }$$

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