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Lines and Angles Test - 36

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Lines and Angles Test - 36
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following pairs represents pairof corresponding angles.

    Solution

  • Question 2
    1 / -0
    If the supplement of an angle is $$\dfrac { 5 }{ 2 } $$ times the complement of the same angle, find the supplementary angle.
  • Question 3
    1 / -0
    In triangle, three angles are  $$x , x + 10 ^ { \circ } + x + 20 ^ { \circ }$$  then the biggest is
    Solution

  • Question 4
    1 / -0
    Find the lettered angle :

    Solution

  • Question 5
    1 / -0
    If the angles of triangle are in the ratio $$1:4:7$$, then the value of the largest angle is :

    Solution

  • Question 6
    1 / -0
    The complementary angle of $$75^{\circ}$$ is _______.
    Solution

    We know, two angles are complementary when they add up to $$90^o.$$

    Given, measure of one complementary angle is $$75^o.$$

    $$\Rightarrow$$ Measure of other complementary angle $$=90^o-75^o$$ $$=15^o.$$

    $$\therefore$$ Measure of a complementary angle of $$ 75^{o}=15^o$$.

    Hence, option $$C$$ is correct.

  • Question 7
    1 / -0
    In the figure below, $$AA'$$ is parallel to $$CC'$$. The measure $$w$$ of $$\angle A'AB$$ is equal to $$135^\circ$$ and the measure $$z$$ of $$\angle C'CB$$ is equal to $$147^\circ$$. Find $$\angle ABC$$. 

    Solution
    Draw $$BB'$$ parallel to $$AA'$$ and $$CC'$$as shown in the figure below.

    Note that angle $$ABC$$ is given by 
    $$\angle ABC = \angle ABB' + \angle CBB' $$

    $$\angle w'$$ and $$\angle ABB'$$ are alternate interior angles and their measure are equal. 
    $$\angle ABB' = \angle w' $$

    $$\angle z'$$ and $$\angle CBB'$$ are alternate interior angles and their sizes are equal. 
    $$\angle CBB' = \angle z'$$

    Angles $$w$$ and $$w'$$ are supplementary which gives 
    $$w' = 180^\circ - w $$
          $$= 180^\circ - 135^\circ $$
          $$= 45^\circ$$

    Angles $$z$$ and $$z'$$ are also supplementary which gives 
    $$z' = 180^\circ - z $$
         $$= 180^\circ - 147^\circ $$
         $$= 33^\circ$$
    We now substitute $$\angle ABB'$$ by $$w'$$ and $$\angle CBB'$$ by $$z'$$ in $$\angle ABC = \angle ABB' + \angle CBB'$$ found above. 
    $$\angle ABC = w' + z' $$
                   $$= 45^\circ + 33^\circ$$
                   $$ = 78^\circ$$

  • Question 8
    1 / -0
    Complement of $$60^o$$ is?
    Solution

    We know, two angles are complementary when they add up to $$90^o.$$

    Given, measure of one complementary angle is $$60^o.$$

    $$\Rightarrow$$ Measure of other complementary angle $$=90^o-60^o$$ $$=30^o.$$

    $$\therefore$$ Measure of a complementary angle of $$ 60^{o}=30^o$$.

    Hence, option $$A$$ is correct.

  • Question 9
    1 / -0
    Mark the correct alternative of the following.
    An angle of measure $$140^o$$ is?
    Solution
    An angle that measures $$<180^o$$ but $$>90^o$$ is called an obtuse angle.
    Here it is given $$140^o$$, so it is an obtuse angle.
  • Question 10
    1 / -0

    Two supplementary angles are in the ratio $$3:2$$. The smaller angle measures?
    Solution
    Given two supplementary angles are in the ratio $$3:2$$.
    Let the measurement of the angles  be $$3x$$ and $$2x$$.
    Two angles are said to be supplementary if they sum upto $$180^o$$.
    Then we have,
    $$3x+2x=180^{o}$$
    $$5x=180^o$$
    or, $$x=36^o$$.
    So the  smaller angle is $$36^o\times 2=72^o$$.
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