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Work and Energy Test - 32

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Work and Energy Test - 32
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  • Question 1
    1 / -0
    A body is under the action of two equal and opposite forces, each of 10 N. The body is displaced by 5 m.The work done is
    Solution
    Given
    Applied forces $$F=10\ N$$
    Displacement $$=5$$
    As the situation given in the question,
    Resultant force acting on the block $${F}{}_{net}=F+(-F)$$
    Hence $${F}{}_{net}=0$$
    $$W={F}{}_{net} \times displacement\\ W=0\times 5=0$$

    $$\therefore$$ Work done is $$ ZERO$$

  • Question 2
    1 / -0
    The spring of the winding knob of a watch has
    Solution
    We know that total energy is kinetic energy plus potential energy. 

    Now, kinetic energy is 

    $$E=\frac { 1 }{ 2 } M{ V }^{ 2 }$$

    Which depends on velocity. In watch there is no displacement in the knob, hence velocity is zero. So there is no kinetic energy. Only potential energy is there.



     
  • Question 3
    1 / -0
    The energy possessed by wind is
    Solution
    Kinetic energy is the energy possessed by an object due to its motion. The energy possessed by the wind is kinetic energy due to the motion of air.
  • Question 4
    1 / -0
    You lift a suitcase from the floor and keep it on the table. The work done by you on the suitcase depends on
    Solution
    The work done by a person in lifting an object is stored as its potential energy $$mgh$$.
    Hence, work done depends on the weight of the object $$mg$$.
    Thus option C is correct.
  • Question 5
    1 / -0
    A body at rest may have
    Solution
    The body at rest may have energy. 
    For example: A body put on height at rest has potential energy = mgh.
  • Question 6
    1 / -0
    The work done in lifting 1 kg mass to a height of 9.8 m is about
    Solution
    The work done in lifting an object is stored as its potential energy.
    Mass of object  $$m = 1$$ kg
    Height upto which it is lifted  $$h = 9.8$$ m
    Hence work done  $$W= m g h = 1 \times  9.8 \times 9.8 = (9.8)^2 J$$
    Thus option C is correct.
  • Question 7
    1 / -0
    Work done by centripetal force in revolving a satellite around the earth is
    Solution
    Centripetal force is always perpendicular to the velocity of the satellite. So work done by the centripetal force is zero.
  • Question 8
    1 / -0
    Asha lifts a doll from the floor and places it on a table. If the weight of the doll is known, what else does one need to know in order to calculate the work Asha has done on the doll?
    Solution

  • Question 9
    1 / -0
    If a body moves along a frictionless horizontal surface its weight:
    Solution
    Work done by the force of gravity on an object (weight) depends on vertical displacement.
    Vertical displacement, $$h = 0$$
    Mass, $$m$$
    Acceleration due to gravity, $$g$$
    Work done, $$W = mgh$$
    $$W=mg\times 0$$
    $$W = 0\ J$$

    $$\therefore$$ If a body moves along a frictionless horizontal surface its weight does not work.
  • Question 10
    1 / -0
    $$kg m^2s^{-2}$$ represents the unit of :
    Solution
    Work done is same as energy which is measured in joules. 1 joule is same as 1 newton expanded over 1 meter which is force multiplied by distance.
    Force is defined as mass into acceleration. Hence if we accelerate 1kg mass by 1m/s$$^{2}$$ in a straight line for a distance of 1 meter, we have indirectly expanded 1 joule of energy .
    Also acceleration is distance per second squared.
    Thus we have (mass $$\ast$$ acceleration $$\ast$$ distance) which is Kg m$$^{2}$$ S$$^{-2}$$.
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