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Work and Energy Test - 41

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Work and Energy Test - 41
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  • Question 1
    1 / -0
    A father holds his child on his shoulders during a parade. The father does no work during the parade because:
    Solution
    We know , work is given by ,
         $$W=fd \ cos\theta$$
    In the given example, father exerts force on child in upward direction and his displacement is in forward direction , therefore angle between force and displacement is $$90^{o}$$  due to this  work done is zero. Also there is no upward or downward displacement of child is taking place as work done is zero. Hence child's distance from the ground remains the same.
  • Question 2
    1 / -0
    Calculate the work done by the person to push a box with a force of $$20 N$$ over a distance of $$8.0 m$$ in the direction of the force?
    Solution
    Work done $$(W)$$        
    $$W = F\times S$$
    $$F$$; applied force
    $$S$$; displacement
    Given :    
    $$F = 20N$$            
    $$S = 8.0$$ m      
    $$\Rightarrow W = 20 \times 8.0$$
    $$\Rightarrow W = 160\ J$$ 
  • Question 3
    1 / -0
    Identify the wrong statement about work.
    Solution
    Work done by a force  is given by dot product of force and displacement      $$W = F.S =F S$$ $$cos\theta$$
    Work done is a scalar quantity.
    It is measured in joules and thus has the same units as energy.
    Hence statement given in option B is wrong.
  • Question 4
    1 / -0
    How much work does a person do in pushing a box with a force of 10 N over a distance of 8.0 m in the direction of the force? 
    Solution
    The work done$$(W)$$ by a force-
    $$W = \text{force} \times \text{displacement}$$
    $$F = 10\ N$$
    $$\text{dispalcement} = 8\ m$$
    $$\Rightarrow W = 10 \times 8$$
    $$\Rightarrow W = 80\ J$$
  • Question 5
    1 / -0
    Which of the following is NOT a unit of energy?
    Solution
    Hint: Energy and work have same units.
    Explanation :-
    $$\bullet$$ Joule, Calorie ,Kilowatt hour and eV are the units of energy while ‘watt’ is the units of power 
    $$\bullet$$ $$P=\frac{w}{ t} =\frac {joule}{time } =Watt$$
    $$\bullet$$ $$ watt \times$$ unit of time is equal to unit of energy ,so Kilowatt hour is unit of energy 
    $$\textbf{Hence option A correct}$$
  • Question 6
    1 / -0
    Identify the best definition of energy?
    Solution
    Energy is defined as the ability to do work and its SI unit is Joule.
  • Question 7
    1 / -0
    Person $$A$$ stands on the right side of a cart, while Person $$B$$ stands on the left side. The cart is initially at rest. Person $$A$$ pushes on the cart with a force of $$22.0 N$$, and Person $$B$$ pushes on the cart with a force of $$33.0 N$$.
    The cart, with no other forces acting on it, starts to move and rolls through a distance of $$2.0 m$$ while both people continue to push with their respective forces.
    How much work was done on the cart by Person $$B$$?
    Solution
    Force exerted by person B       $$F_B = 33.0$$ N
    Displacement of the box in the direction of $$F_B$$          $$S = 2.0$$ m
    $$\therefore$$ Work done by person B           $$W_B = F_B\times S = 33.0 \times 2.0 = + 66.0$$  J
  • Question 8
    1 / -0
    Define one watt:
    Solution
    Watt is a SI unit of power which is defined as the energy per unit time   i.e   $$P =\dfrac{E}{t}$$
    Hence one watt is defined as one joule of energy used in one second.
    $$\therefore$$  $$W = \dfrac{J}{s}$$
  • Question 9
    1 / -0
    A block of mass 10 kg is pulled by a constant horizontal force of 19 N and it is displaced by 15 m across the floor. Calculate the work done.
    Solution
    Given :   Force $$F =19 N$$                 
    Displacement    $$S=  15$$ m                        
    Work done by a force is     $$W= F S $$         
    $$\therefore$$   $$W = 19 \times 15   = 285$$  $$J$$                           
  • Question 10
    1 / -0
    How much work does a person do in pushing a box with a force of $$20\ N$$ over a distance of $$8.0\ m$$ in the direction of the force? 
    Solution
    Given,
    Force applied, $$F = 20\ N$$
    Displacement, $$d=+8.0\ m$$ (in the direction of the force)

    Work done, $$W$$
    $$W=F\times d$$
    $$W=20\times 8$$
    $$W=160\ J$$
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