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Work and Energy Test - 48

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Work and Energy Test - 48
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  • Question 1
    1 / -0
     Work is always done on a body when
    Solution
    Work done is given by
    $$W=Fd$$   where $$F$$ is Force and $$d$$ is displacement 
    Hence two conditions need to be satisfied for work to be done: 
    (i) a force should act on an object
    (ii) the object must be displaced.
    So option A is correct.
  • Question 2
    1 / -0
    The $$SI$$ unit of energy, the Joule is equivalent to 
    Solution

  • Question 3
    1 / -0
    The amount of work done on an object when a constant force of $$\dfrac { 1 }{ 10 }\ N$$ displaces it by $$10\ cm$$ along the line of action of the force is:
    Solution
    Given,
    Force applied, $$F= \dfrac {1}{10}\ N$$

    Displacement, $$d=10\ cm$$

    $$d=\dfrac {10}{100}=\dfrac{1}{10} \ m$$


    Work done, $$W=F\times d$$

    $$W=\dfrac {1}{10} \times \dfrac{1}{10}$$

    $$W=\dfrac {1}{100}\ J$$
  • Question 4
    1 / -0
    A lawn roller is pulled along a horizontal surface through a distance of $$20 \ m$$ by a rope with a force of $$200 \ N$$. If the rope makes an angle of $$60^o$$ with the vertical while pulling, the amount of work done by the pulling force is:
    Solution
    Correct Answer: Option A

    Hint: Use the equation for work done, $$ W=Fscos\theta$$, where F is force, s is displacement and $$\theta$$ is the angle between force and displacement.

    Explanation of Correct Option:

    • Given, force $$F=200N$$, distance $$s=20m$$, 
    • Angle rope make with vertical is $$\theta=60^{\circ}$$, so angle rope makes with horizontal $$\theta=30^{\circ}$$

    • Work done by pulling force,$$W=F.s$$
    $$W=Fscos\theta$$

    $$W = 200 \times 20 \times \dfrac{\sqrt3}{2}$$               $$\left( {\because \theta  = 30^\circ ,\cos 30^\circ  = \dfrac{\sqrt3}{2}} \right)$$

    $$W = 3464J$$


    The amount of work done by pulling force is $$3464J$$ .

  • Question 5
    1 / -0
    In $$10 s$$, a body of $$6 kg$$ mass is dragged $$8 m$$ with uniform velocity across a floor by a steady force of $$20 N$$. The K.E of the body is:
    Solution

  • Question 6
    1 / -0
    A body of mass m is rotating in a vertical circle of radius 'r' with critical speed. The difference in its K.E. at the top and the bottom is _____.
    Solution

  • Question 7
    1 / -0
    A body of mass 0.5 kg is moving at a constant velocity, work done is
    Solution
    $$Work=Force \times displacement$$
    Since moving with same velocity so no acceleration hence no force . So
    $$W= 0\times displacement$$
    $$W=0$$
  • Question 8
    1 / -0
    In which of the following, law of conservation of energy is violated? 
    Solution
    The law of conservation of energy is never violated. in all the given processes, one form of energy is converted into other forms. But the total energy of the system is always conserved.
  • Question 9
    1 / -0
    Which of the following does not possess the ability to do work because of motion?
    Solution

  • Question 10
    1 / -0
    If the kinetic Energy possessed by a man of $$50$$kg is $$625J$$, the speed of man is 
    Solution

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