Sound Test

Result

Sound Test - 27

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Weekly Quiz Competition

Question 1
1 / -0

Perforated card boards are used in halls, for

A
reflection of sound

B
absorption of sound

C
refraction of sound

D
as a decorative material

Solution

Perforated cardboard gypsum boards are an economical and efficient option to incorporate into projects, absorbing the sound and reducing the noise level generated by the reverberation through different patterns and shapes.
Question 2
1 / -0

In an auditorium, when a speech is going on, a window is opened beside the audience, then the absorption of sound :

A
increases

B
decreases

C
remains Same

D
becomes zero

Solution

Windows are opened in an auditorium during a speech so that more absorption of the sound takes place by outer atmosphere and no sound gets reflected back which interferes with the original sound resulting in noise (echo).So echoes are reduced.
Question 3
1 / -0

Waves from sitar wire and veena wire distinguished by (of same frequency)

A
Loudness

B
Pitch

C
Quality

D
Both pitch and quality

Solution

The quality or timbre is the characteristic of sound which distinguishes it from another of the same pitch (dependent upon the frequency) and loudness ( dependent upon the amplitude).
Every sound that we hear is dependent on its source. Sound timbre is dependent on the material through which it is produced.
Question 4
1 / -0

A man stands in front of a hillock and fires a gun. He hears an echo after 1.5 sec. The distance of the hill from the man is (velocity of sound in air=330m/s)

A
220m

B
247.5m

C
268.5m

D
292.5m

Solution

The distance traveled by sound for echo is:
$$2x= speed\ of\ sound \times time\ of\ echo $$
$$x=\dfrac{1}{2}\times 330\times 1.5 = 247.5\ m$$
Question 5
1 / -0

If velocity of sound in air is 340 $$m s^{-1}$$, calculate wavelength when frequency is 256 Hz :

A
2.5 m

B
2.56 m

C
1.33 m

D
1.45 m

Solution

Given $$v= 340 m/s $$ ; $$\lambda= ?; \ f=256\ Hz$$

We know, $$ v= f \lambda \implies \lambda= \dfrac{v}{f}= \dfrac{340}{256}= 1.33 \ m$$
Question 6
1 / -0

When we change feeble sound to loud sound we increase its :

A
frequency

B
amplitude

C
velocity

D
wavelength

Solution

The amplitude is the measure of loudness of a sound. When our music system is having a feeble sound by increasing the amplitude, the sound now becomes louder.
Question 7
1 / -0

A person is in front of a vertical mountain fires a bullet and hears its echo after a time 6s. The person walks a distance d towards mountain then fires another bullet and hears its echo after a time 2s. If velocity of sound in air is 340 ms$$^{-1}$$. The value of d is

A
340 m

B
170 m

C
255 m

D
680 m
Question 8
1 / -0

In order to reduce the loudness of a sound we have to:

A
decrease its frequency of vibration of the sound

B
increase its frequency of vibration of the sound

C
decrease its amplitude of vibration of the sound

D
increase its amplitude of vibration of the sound

Solution

The loudness of sound varies directly as the square of the amplitude of vibration of the sound source.
Hence, the in order to reduce the loudness of sound, we have to decrease the amplitude of vibration of the sound.
Question 9
1 / -0

In the curve, half the wavelength is

A
A B

B
B D

C
D E

D
A E

Solution

In a wave, the distance between two successive compressions or rarefactions is a wavelength.
By definition,
Wavelength $$\lambda=AE$$
By symmetry,
$$\dfrac{1}{2} \lambda=AC=CE$$
and
$$\dfrac{1}{4} \lambda=\dfrac{1}{2}AC=\dfrac{1}{2}CE=AB=BC=CD=DE$$

We see, $$BD=BC+CD=\dfrac{1}{4}\lambda+\dfrac{1}{4}\lambda=\dfrac{1}{2}\lambda$$

Hence, BD is half the wavelength.
Question 10
1 / -0

The loudness of sound depends on:

A
its amplitude

B
its frequency

C
its time period

D
its speed

Solution

Some of the sounds appear loud whereas others appear to be faint in the ear. The faint sound has a small amplitude whereas the loud sound has a large amplitude.Thus,the loudness or softness of a sound is determined basically by the amplitude of the wave.

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Re-Attempt Weekly Quiz Competition

Sound Test - 27

Result

Sound Test - 27

Score

-

Rank

-

SHARING IS CARING

Question 1

reflection of sound

absorption of sound

refraction of sound

as a decorative material

Solution

Question 2

increases

decreases

remains Same

becomes zero

Solution

Question 3

Loudness

Pitch

Quality

Both pitch and quality

Solution

Question 4

220m

247.5m

268.5m

292.5m

Solution

Question 5

2.5 m

2.56 m

1.33 m

1.45 m

Solution

Question 6

frequency

amplitude

velocity

wavelength

Solution

Question 7

340 m

170 m

255 m

680 m

Question 8

decrease its frequency of vibration of the sound

increase its frequency of vibration of the sound

decrease its amplitude of vibration of the sound

increase its amplitude of vibration of the sound

Solution

Question 9

A B

B D

D E

A E

Solution

Question 10

its amplitude

its frequency

its time period

its speed

Solution

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