Sound Test

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Sound Test - 33

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Weekly Quiz Competition

Question 1
1 / -0

Bats detect the obstacles in their path by receiving the reflected

A
infrasonic waves

B
ultrasonic waves

C
micro waves

D
radio waves

Solution

The answer is B.

Bats emit a series of high-frequency sounds from their mouths or nostrils that bounce off objects and then return to the ears of bats. These high-frequency sounds are called ultrasonic waves. with the help of the reflection of ultrasonic waves, bats detect the obstacles in their path.
Question 2
1 / -0

Arrange the speed of sound in gases $$V_g$$ , solids $$V_s$$ and liquids $$V_l$$ in an ascending order.

A
$$V_g < V_l < V_s$$

B
$$V_l < V_g < V_s$$

C
$$V_s < V_l < V_g$$

D
Data insufficient

Solution

The speed of sound depends on two factors: elasticity and density. The more elastic a medium, the greater the speed. The more dense the medium the slower the speed of sound. For example steel is 6000 times more denser than air but 2,000,000 times more elastic than air, so sound travels 16 times faster in steel than in air.
More elasticity means a large bulk modulus, tension, pressure, or some other physical quantity that makes it more difficult to deform the medium. Density is just the inertial property that makes it difficult to accelerate the medium.
The speed of sound varies as the square root of the ratio of the "elastic properties" or "bulk properties". The more elastic a substance and the least dense, the faster the speed of sound in general. So the speed in increasing order is: $$V_{gas}<V_{liquid}<V_{solid}$$.
Question 3
1 / -0

The speed of sound in air at $$0^oC$$ is nearly:

A
$$1450 \ m s^{-1}$$

B
$$450 \ m s^{-1}$$

C
$$5100 \ m s^{-1}$$

D
$$330 \ m s^{-1}$$

Solution

Answer is D.
The speed of sound changes with air temperature, humidity, and even air quality. The speed of sound is about 331.5 m/s at 0 degree-Celsius. The speed of sound increases by 0.6 meters per second (m/s) for every degree-Celsius increase in temperature.
Question 4
1 / -0

The speed of sound in air is _________ temperature?

A
independent of

B
directly proportional to

C
indirectly proportional to

D
None

Solution

Sound waves require a medium in order to travel. A medium can be a solid, liquid, or a gas such as air. The speed of sound depends on both the elasticity and density of the medium. When the elasticity increases and density decreases of a medium, sound is allowed to travel faster.
Temperature affects the speed of sound by changing the density of the medium in which a sound wave travels. In most cases, when the temperature of a medium increases, so does the speed of sound through that medium. Higher temperatures lower the density of a medium, which puts less resistance on the sound waves.
The speed of sound increases by $$0.6 \ m/s$$ for every $$^0C$$ increase in temperature..
Question 5
1 / -0

A longitudinal wave is composed of _________.

A
Rarefaction

B
Compression

C
Both $$A$$ and $$B$$

D
None of these

Solution

The waves in which the individual particles of the medium move in a direction parallel to the direction of propagation of the disturbance are known as longitudinal waves. The waves propagate in the medium as a series of
compressions and rarefactions.
Question 6
1 / -0

Speed of sound is ______ in solids and _____ in gases.

A
least, least

B
maximum, maximum

C
least, maximum

D
maximum, least

Solution

Sound travels fastest in solids and slowest in air. Water is in between. This is because the particles in solids are closer together than the particles in liquids or gases, and the particles in liquids are closer together than the particles in gases. The tighter particles are packed in a space, they collide more frequently. This allows sound, which is simply the combined collisions of particles, to travel fastest in solids. So, to reiterate, sound travels the fastest in solids, then water and slowest in air.
Question 7
1 / -0

The heart of a man beats $$75$$ times a minute. What is its time period?

A
$$0.75s$$

B
$$1.33s$$

C
$$1.25s$$

D
$$0.8s$$

Solution

To calculate the frequency in hertz, we have to measure the time in seconds.
That is, t= 1 minute = 60 seconds.
Number of time it beats = 75 times per minute.
Frequency is given as,
Number of times it beats/Total time taken in seconds = 75/60 = 1.25 Hz.
Hence, the frequency of a man's heartbeat is 1.25 times per second.
The time period is given as the inverse of frequency, that is, $$T=\dfrac { 1 }{ f } =\dfrac { 1 }{ 1.25 } = 0.8\; seconds$$.
Hence, the time period of a man's heart beat is 0.8 seconds.
Question 8
1 / -0

Complete the following sentence.

Sound can not travel through ..............................., but it requires a ................... .

A
$$air, medium$$

B
$$water, medium$$

C
$$solids, medium$$

D
$$vacuum, medium$$

Solution

Sound waves need to travel through a medium such as a solid, liquid, or gas. The sound waves move through each of these mediums by vibrating the molecules in the matter. The molecules in solids are packed very tightly. Liquids are not packed as tightly as solids. And gases are very loosely packed. The spacing of the molecules enables sound to travel much faster through a solid than a gas. Sound travels about four times faster and farther in water than it does in air.
Sound waves are travelling vibrations of particles in media such as air, water or metal. So it stands to reason that they cannot travel through empty space, where there are no atoms or molecules to vibrate.
Hence, Sound cannot travel through vacuum, but it requires a medium.
Question 9
1 / -0

The heart of a man beats $$75$$ times a minute. What is its frequency?

A
$$1.25 \ s^{-1}$$

B
$$2.5 \ s^{-1}$$

C
$$7.5 \ s^{-1}$$

D
$$75 \ s^{-1}$$

Solution

To calculate the frequency in hertz, we have to measure the time in seconds.
That is, t= 1 minute = 60 seconds.
Number of time it beats = 75 times per minute.
Frequency is given as,

Number of times it beats/Total time taken in seconds = 75/60 = 1.25 Hz.

Hence, the frequency of a man's heartbeat is 1.25 times per second.
Question 10
1 / -0

The time period of a simple pendulum is $$2 \ s$$. Find its frequency?

A
$$0.5 \ Hz$$

B
$$1 \ Hz$$

C
$$1.5 \ Hz$$

D
$$2 \ Hz$$

Solution

The Time period of a simple pendulum is given as 2 seconds.
The frequency is given as the inverse of time period, that is, $$f=\dfrac { 1 }{ T } $$
$$f =\dfrac { 1 }{ 2 } \quad =\quad 0.5\quad Hz$$

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Sound Test - 33

Result

Sound Test - 33

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Question 1

infrasonic waves

ultrasonic waves

micro waves

radio waves

Solution

Question 2

$$V_g < V_l < V_s$$

$$V_l < V_g < V_s$$

$$V_s < V_l < V_g$$

Data insufficient

Solution

Question 3

$$1450 \ m s^{-1}$$

$$450 \ m s^{-1}$$

$$5100 \ m s^{-1}$$

$$330 \ m s^{-1}$$

Solution

Question 4

independent of

directly proportional to

indirectly proportional to

None

Solution

Question 5

Rarefaction

Compression

Both $$A$$ and $$B$$

None of these

Solution

Question 6

least, least

maximum, maximum

least, maximum

maximum, least

Solution

Question 7

$$0.75s$$

$$1.33s$$

$$1.25s$$

$$0.8s$$

Solution

Question 8

$$air, medium$$

$$water, medium$$

$$solids, medium$$

$$vacuum, medium$$

Solution

Question 9

$$1.25 \ s^{-1}$$

$$2.5 \ s^{-1}$$

$$7.5 \ s^{-1}$$

$$75 \ s^{-1}$$

Solution

Question 10

$$0.5 \ Hz$$

$$1 \ Hz$$

$$1.5 \ Hz$$

$$2 \ Hz$$

Solution

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