Atoms and Molecules Test

Result

Atoms and Molecules Test - 2

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

The formula of a chloride of a metal M is MCl₃, the formula of the phosphate of metal M will be

A
MPO₄

B
M₂PO₄

C
M₃PO₄

D
M₂(PO₄)₃

Solution

Valence of M in MCl₃ = 3+

Valence of PO₄ = 3-

Therefore, it will form MPO₄
Question 2
1 / -0

The ratio of H:O by mass in hydrogen peroxide (H₂O₂) is

A
16 : 1

B
1 : 8

C
1 : 32

D
1 : 16

Solution

Mass of hydrogen (H) = 2u and Mass of oxygen (O) = 32 u

Ratio of H:O = 2/32 = 1/16 = 1:16
Question 3
1 / -0

Which has the largest number of molecules?

A
54 g of N₂O₅

B
28 g of CO₂

C
36 g of H₂O

D
46 g of C₂H₅OH

Solution

To calculate no. of molecules, first calculate the mass of 1 molecule. After that, divide the given mass by mass of 1 molecule.

For example, Mass of 1 molecule of H2O = 18g

Therefore, No. of molecules in 36 g of H2O = 36/18 = 2
Question 4
1 / -0

The molecular formula of zinc phosphate is

A
Zn(PO₄)₃

B
Zn₂PO₄

C
Zn₃(PO₄)₂

D
ZnPO₄

Solution

Valence of Zn = 2+

Valence of PO₄ = 3-

Molecular formula of zinc phosphate = Zn₃(PO₄)₂
Question 5
1 / -0

The accepted unit of atomic mass and molecular mass is

A
amu

B
g

C
kg

D
g mol^-1

Solution

amu (atomic mass unit) is accepted unit of atomic mass and molecular mass.
Question 6
1 / -0

Valence of noble gases is

A
1

B
0

C
2

D
none of these

Solution

Noble gases always complete its duplet or octet. Thus, its valency is 0.
Question 7
1 / -0

The number of atoms of hydrogen present In 1 mole of ethyne (C₂H₂) is

A
4 x 6.023 x 10²³

B
2 x 6.023 x 10²³

C
6.023 x 10²³

D
8 x 6.023 x 10²³

Solution

No. of molecules in 1 mole C₂H₂ = 6.023 x 10²³

No. of atoms of H in ethyne = 2

No. of atoms of hydrogen present In 1 mole of C₂H₂ = 2 x 6.023 x 10²³
Question 8
1 / -0

The law of definite proportions was proposed by

A
John Dalton

B
Richter

C
Joseph Proust

D
A. Lavoisier
Question 9
1 / -0

The reference standard used for defining atomic mass unit is

A
H

B
C-12

C
C-13

D
C-14

Solution

atomic mass unit used to express atomic and molecular weights, equal to one twelfth of the mass of an atom of carbon-12.
Question 10
1 / -0

The element whose gram-atomic mass and gram-molecular mass are the same is

A
argon.

B
nitrogen.

C
oxygen.

D
hydrogen.

Solution

Argon is a noble gas which exist as monoatomic molecule. It also complete its octet therefore its molecular mass and atomic mass is same.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Atoms and Molecules Test - 2

Result

Atoms and Molecules Test - 2

Score

-

Rank

-

SHARING IS CARING

Question 1

MPO4

M2PO4

M3PO4

M2(PO4)3

Solution

Question 2

16 : 1

1 : 8

1 : 32

1 : 16

Solution

Question 3

54 g of N2O5

28 g of CO2

36 g of H2O

46 g of C2H5OH

Solution

Question 4

Zn(PO4)3

Zn2PO4

Zn3(PO4)2

ZnPO4

Solution

Question 5

amu

g

kg

g mol-1

Solution

Question 6

1

0

2

none of these

Solution

Question 7

4 x 6.023 x 1023

2 x 6.023 x 1023

6.023 x 1023

8 x 6.023 x 1023

Solution

Question 8

John Dalton

Richter

Joseph Proust

A. Lavoisier

Question 9

H

C-12

C-13

C-14

Solution

Question 10

argon.

nitrogen.

oxygen.

hydrogen.

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.

MPO₄

M₂PO₄

M₃PO₄

M₂(PO₄)₃

54 g of N₂O₅

28 g of CO₂

36 g of H₂O

46 g of C₂H₅OH

Zn(PO₄)₃

Zn₂PO₄

Zn₃(PO₄)₂

ZnPO₄

g mol^-1

4 x 6.023 x 10²³

2 x 6.023 x 10²³

6.023 x 10²³

8 x 6.023 x 10²³