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Atoms and Molecules Test - 3

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Atoms and Molecules Test - 3
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  • Question 1
    1 / -0

    The mass percentage of hydrogen (H) in water is

    Solution

    Mass of hydrogen = 2 u

    Mass of water = 2 + 16 = 18 u

    Mass percentage of hydrogen in water = 2/18 x 100 = 100/9 = 11.11

     

  • Question 2
    1 / -0

    The ratio of H:O by mass in water is

    Solution

    2 molecules of hydrogen combine with 1 molecule of oxygen to form water.

    Mass of H = 1 u

    Mass of O = 16 u

    Ration H:O = 2:16 = 1:8

     

  • Question 3
    1 / -0

    The indivisibility of atom was proposed by

  • Question 4
    1 / -0

    Copper reacts with oxygen to form two oxides, Cu2O and CuO. The ratio between the masses of copper which react with a fixed mass of oxygen is

    Solution

    Mass of copper = 63.5

    Ratio = Mass of Cu2/Mass of Cu = 127/63.5 = 2/1 = 2:1

     

  • Question 5
    1 / -0

    The modern atomic symbols were proposed by

  • Question 6
    1 / -0

    The mass of one Avogadro’s number of N atoms is equal to

    Solution

    one Avogadro’s number of N atoms = 14 g of N

     

  • Question 7
    1 / -0

    An atom is the

  • Question 8
    1 / -0

    The mass of sulphur dioxide that will contain 6.023 x 1022 molecules is

    Solution

    No. of molecules in 64 g of SO2 = 6.023 x 1023

    Mass of 6.023 x 1022 molecules of SO2 = (6.023 x 1022/6.023 x 1023) x 64 g = 1/10 x 64 = 6.4 g

     

  • Question 9
    1 / -0

    The number of gram-molecules of O2 in 6.023 x 1024 CO molecules is

    Solution

    1 mole of CO = 1 gram-atom of O or 6.023 x 1023 molecules of CO = ½ gram molecule of O2. Hence, 6.023 x 1024 molecules of CO = ½ x (6.023 x 1024/6.023 x 1023) = ½ x 10 = 5

     

  • Question 10
    1 / -0

    Which of the following is a binary compound?

    Solution

    A binary compound contains two elements in it.

     

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