Motion Test

Result

Motion Test - 24

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

In the equation of motion, $$s = ut + \dfrac 12 at^2$$, $$s$$ stands for

A
displacement in $$t$$ seconds

B
maximum height reached

C
displacement in the $$t^{th}$$ second

D
None of these

Solution

In the second equation of motion $$ s=ut+\dfrac { 1 }{ 2 } a{ t }^{ 2 }$$

$$s =$$ displacement in $$t$$ seconds
$$u =$$ Initial velocity of the motion
$$a =$$ acceleration or retardation of the motion

Hence, option A is correct
Question 2
1 / -0

Area under a speed-time graph gives :

A
The time taken by a moving object

B
The distance travelled by a moving object

C
Tthe acceleration of a moving object

D
Tthe retardation of a moving object

Solution

The area under the velocity-time graph gives the distance traveled by a moving object during that time interval.
While the area under the velocity-time graph gives displacement of the particle.
Question 3
1 / -0

The ratio of SI units to CGS units of retardation is

A
$$\displaystyle { 10 }^{ -2 }$$

B
$$\displaystyle { 10 }^{ 2 }$$

C
$$\displaystyle 10$$

D
$$\displaystyle { 10 }^{ -1 }$$

Solution

SI unit of retardation is $$ms^{-2}$$ and CGS unit is $$cms^{-2}$$.
Also, we know that $$1 \ m = 100 \ cm$$
Thus ratio,
$$ratio = \dfrac{ms^{-2}}{cms^{-2}}$$
$$\Rightarrow ratio = \dfrac{100\ cm\ s^{-2}}{cm\ s^{-2}}$$
$$\Rightarrow ratio = 10^2$$
Question 4
1 / -0

The SI unit of retardation is _____.

A
m/s$$\displaystyle ^{2}$$

B
m/s$$\displaystyle$$

C
m$$\displaystyle ^{2}$$

D
s$$\displaystyle ^{2}$$

Solution

Si unit of retardation is same as that of acceleration as $$m/s^2$$.
Question 5
1 / -0

What is the velocity of vertically projected body at its maximum height (h)?

A
$$\displaystyle \sqrt { 2\ gh } $$

B
zero

C
$$\displaystyle \frac { { h }^{ 2 } }{ g } $$

D
$$\displaystyle \sqrt { \frac { 2h }{ g } } $$

Solution

When particle is at maximum height it's Potential energy = $$mgh$$
also maximum .
But when it was at ground it's Potential energy =$$0$$
It means all of it's Kinetic energy at ground was converted into Potential energy at top most point so Kinetic energy at top point=$$0$$
$$\frac{mv^2}{2}=0$$
so$$v=0$$
Hence velocity at maximum height=
$$0$$
Question 6
1 / -0

When the distance an object travels is directly proportional to the time, it is said to travel with

A
Constant speed

B
Zero velocity

C
Constant acceleration

D
Uniform velocity

Solution

When the distance an object travels is directly proportional to time, it is said to travel with Constant Speed.

$$ Speed = \dfrac{distance \ travelled}{time}$$
Question 7
1 / -0

In Figure as shown above BC represents a body moving:

A
backward with uniform velocity

B
forward with uniform velocity

C
backward with non-uniform velocity

D
forward with non-uniform velocity

Solution

Velocity of an object from displacement-time graph is given by its slope.
ie $$\dfrac{dy}{dt}=V$$ so slope from B to C is constant and negative so body is moving backward and with a constant velocity.
so best possible option is option A.
Question 8
1 / -0

Retardation means

A
negative acceleration

B
positive acceleration

C
zero acceleration

D
none of these

Solution

If the velocity of a moving object is decreasing with respect to time then you can say that body is in retardation or deacceleration or negative acceleration.
In other words; Retardation is a negative rate of change of velocity.
Question 9
1 / -0

If a body undergoes retardation, its velocity

A
increases

B
decreases

C
remains same

D
may increase or decrease

Solution

Retardation means negative acceleration. It is rate of decrease of velocity with time.
So, if a body undergoes retardation, its velocity decreases.
Question 10
1 / -0

A body executing non-uniform motion:

A
Undergoes acceleration

B
Never undergoes acceleration

C
May or may not undergo acceleration

D
Never undergoes constant acceleration

Solution

If a body undergoes non-uniform motion, its speed changes and a body with changing speed undergoes acceleration.
This acceleration may or may not be constant.
Acceleration of the particle is given as-
$$\text{acceleration} = \dfrac{ \text{ change in velocity } }{ \text{ time } }$$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Motion Test - 24

Result

Motion Test - 24

Score

-

Rank

-

SHARING IS CARING

Question 1

displacement in $$t$$ seconds

maximum height reached

displacement in the $$t^{th}$$ second

None of these

Solution

Question 2

The time taken by a moving object

The distance travelled by a moving object

Tthe acceleration of a moving object

Tthe retardation of a moving object

Solution

Question 3

$$\displaystyle { 10 }^{ -2 }$$

$$\displaystyle { 10 }^{ 2 }$$

$$\displaystyle 10$$

$$\displaystyle { 10 }^{ -1 }$$

Solution

Question 4

m/s$$\displaystyle ^{2}$$

m/s$$\displaystyle$$

m$$\displaystyle ^{2}$$

s$$\displaystyle ^{2}$$

Solution

Question 5

$$\displaystyle \sqrt { 2\ gh } $$

zero

$$\displaystyle \frac { { h }^{ 2 } }{ g } $$

$$\displaystyle \sqrt { \frac { 2h }{ g } } $$

Solution

Question 6

Constant speed

Zero velocity

Constant acceleration

Uniform velocity

Solution

Question 7

backward with uniform velocity

forward with uniform velocity

backward with non-uniform velocity

forward with non-uniform velocity

Solution

Question 8

negative acceleration

positive acceleration

zero acceleration

none of these

Solution

Question 9

increases

decreases

remains same

may increase or decrease

Solution

Question 10

Undergoes acceleration

Never undergoes acceleration

May or may not undergo acceleration

Never undergoes constant acceleration

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.