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Forces and Laws of Motion Test - 26

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Forces and Laws of Motion Test - 26
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  • Question 1
    1 / -0
    The force needed to produce an acceleration of $$6 m/s^2$$ in a ball of mass $$ 4 kg$$ will be
    Solution
    $$F=ma$$
    $$F=6\times4$$
    $$F=24N$$
    So, the required force is $$F=24N$$.
  • Question 2
    1 / -0
    When will a body under the action of several forces have 0 acceleration? 
    Solution
    Referring formula $$\displaystyle F =ma$$
    Thus acceleration will be zero, when resultant force is zero. In option (d), the point body is to be considered. A point body does not mean a body of zero mass. A point body or a particle is ideally a piece or quantity of matter having practically no linear dimensions but only a position. The measure of this quantity of matter is the mass of the particle. It is a usual convention to imagine bodies as point objects when we are only concerned about their mass and not about the distribution of mass. Thus earth can be considered as a point body when we describe its motion about sun.
  • Question 3
    1 / -0
    Every action has reaction. These action-reaction are 
    Solution
    According to Newton third law 
    The forces of action and reaction are equal, opposite and act on different bodies.
    The effect of action and reaction is always visible separately on both the interacting bodies in opposite directions. Therefore, the forces of action and reaction are equal, opposite and act on different bodies.
  • Question 4
    1 / -0
    A body is said to be underbalanced forces when the resultant force acting on the body is 
    Solution
     If the net force acting on a body is zero, then the body is said to be in equilibrium, or a body is said to be underbalanced forces when the resultant force acting on the body is zero.
  • Question 5
    1 / -0
    A driver accelerates his car first at the rate of 1.8 m/s$$^2$$ and then at the rate of 1.2 m/s$$^2$$. The ratio of the forces exerted by the engines will be respectively equal to
    Solution
    We have to find $$\dfrac{{F}_{1}}{{F}_{2}}$$ 
    $$F\propto a$$
    $$\dfrac{{F}_{1}}{{F}_{2}}=\dfrac{{a}_{1}}{{a}_{2}}$$.
    Which gives the ratio $$3:2$$.
  • Question 6
    1 / -0
    When a force of 1 newton acts on a mass of 1 kg that is able to move freely, the object moves with a/an
    Solution
    According to Newton's second law of motion 
    $$ F= ma$$
    Here,
    Force $$F= 1 \ N$$
    Mass $$m=1 \ kg$$
    So, 
    $$ 1 \ N = (1 \ kg)\ \times a$$
    $$\Rightarrow a  =1 \ m/s^2 $$

    Option B is correct.

  • Question 7
    1 / -0
    A ball of mass $$0.2 kg$$ moves with a velocity of $$20 m/s$$ and it stops in $$0.1 s$$, then the force on the ball is 
    Solution
    $$\displaystyle F=ma=m\left( \frac { \upsilon -u }{ t }  \right) =\frac { -mu }{ t } $$
    Substituting the values and neglecting the negative sign (because none of the options is negative)
    $$\displaystyle F=\frac { 0.2\times 20 }{ 0.1 } =40$$N
  • Question 8
    1 / -0
    When a body is in translatory equilibrium 
    Solution
    When a body is in translatory equilibrium , the net force acting on a body is zero, and  the body is said to be in translational equilibrium. In  translatory equilibrium, the center of mass of the body remains either at rest or moves rectilinearly with constant velocity. Hence, the body is definitely in the state of uniform motion or in rest.
  • Question 9
    1 / -0
    A body is said to be under balanced forces when the resultant force acting on the body is
    Solution
    Forces are said to be balanced if resultant of the forces is zero i.e.  $$F_R = 0$$
    Acceleration of the body  $$a = \dfrac{F_R}{m} = 0$$
    Thus a body under balanced forces has zero acceleration.
  • Question 10
    1 / -0
    A cannon after firing recoils due to 
    Solution
    Correct Option is D.
    Explanation for the correct:
    $$\bullet$$ Newton's Third Law of Motion states that to every Action there is equal and opposite Reaction. Thus firing of bullet from cannon is an Action and there is opposite Reaction on the cannon due to which it recoils. Option D is correct.
    $$\bullet$$ Conservation of Energy states that Energy can neither be created nor destroyed. It can only change it forms.
    $$\bullet$$ Backward thrust of gases is not a Law. It is also one of the consequences of Third Law of Motion.
    $$\bullet$$ First Law of Motion states that if a body is at rest/motion it will continue to remain at rest/motion until any external force is applied.

    Thus, Only Option D is correct.
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