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Forces and Laws of Motion Test - 34

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Forces and Laws of Motion Test - 34
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  • Question 1
    1 / -0
    Two bodies of masses 1m and 4m have the same KE. What is the ratio of their momenta?
    Solution
    The relation between kinetic energy $$(K)$$ and momentum $$(p)$$ is given by, $$K=\dfrac{p^2}{2m}$$ where $$m$$ be the mass of the body
    So, $$p=\sqrt{2mK}$$
    Hence, $$\dfrac{p_1}{p_2}=\dfrac{\sqrt{2(m)K_1}}{\sqrt{2(4m)K_2}}=\sqrt{(1/4)}=2/1$$   as they have same kinetic energies so $$K_1/K_2=1$$
  • Question 2
    1 / -0
    A 10 N force applied on a body produces in it an acceleration of $$2 \,m\, s^{-2}$$, then the mass of the body is ______.
    Solution
    $$F=10N$$
    $$a=2m/s^{2}$$
    By newton second law
    $$F=ma$$
    $$10=2M$$
    $$M=5Kg$$
  • Question 3
    1 / -0
    Which of the following safety features are used in vehicles to reduce the negative effects of inertia?
    (i)Safety seat belts
    (ii)Automatic air bags
    (iii)Absorber bumpers
    Solution
    $$Force=mass \times \dfrac{momentum}{time}$$
    since the effect of inertia depend on force if the time of impact is increased and hence the same force will produce less effect of inertia the safety seat belt,automatic air bag,Absorber bumpers produce the same effect to decrease the negative effect of inertia.
  • Question 4
    1 / -0
    A man weighing 60 kg is walking with a uniform velocity of 4 m $$s^{-1}$$. Calculate the momentum of a man.
    Solution
    Given,
    $$m=60\ kg\\v=4\ m/s$$
    Momentum = mass $$\times$$ velocity.
    Momentum of man $$p=m\times v=60\times 4=240\ kg m/s$$
  • Question 5
    1 / -0
    Identify the type of force in diagram

    Solution
    When a force is exerted in such a way that movement caused is towards oneself, such type of force is pull.
  • Question 6
    1 / -0
    A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is
    Solution
    When the man gets straight up and stand in this process initially for the man to move upward he needs a net external force in the upward direction which can only be provided by the normal reaction($$N$$) from the ground.
    Therefore, $$N-mg>0\quad \Rightarrow N>mg$$   (initially)
    and later when he stands up and becomes static then $$N=mg$$
  • Question 7
    1 / -0
    On a stationary sail boat, air is blown from a fan attached to the boat. The boat
    Solution
    In this case air blown by the fan will try to push the sail boat in a certain direction.But at the same time due to Newton's third law of motion the fan will experience a force due to the air blown in a direction opposite to the direction in which the sail boat will experience the force due to the blown air.So, as a whole the system will be at rest and it will not move
  • Question 8
    1 / -0
    If set of forces acting on a body are balanced, the body
    Solution
    If there is a balanced force, the object will remain in its present state, i.e., if it is moving, it will keep on moving with uniform speed. If it is at rest, it will remain at rest.
  • Question 9
    1 / -0
    When a bus suddenly takes a turn, the passengers are thrown outwards because of 
    Solution
    According to the law of inertia of motion, a body will continue moving with constant velocity unless any force acts on it. When a bus is moving straight the passengers inside are also moving straight but when suddenly bus turn left passengers still continue to move straight  because no force is acting on passengers so they will move with same magnitude and direction i.e. outwards when bus turns .

  • Question 10
    1 / -0
    What causes a moving body to resist a change in its state of motion?
    Solution
    The property of a body by virtue of which it resists any change in its state of rest or of motion in a straight line on its own is called its inertia.
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