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Forces and Laws of Motion Test - 55

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Forces and Laws of Motion Test - 55
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  • Question 1
    1 / -0
    Four alternatives are given to the following incomplete statement/question. Choose the right answer.
    If the forces acting on an object are balanced then 
    Solution
    From Newton's second law of motion - $$F=ma$$, where $$F$$ is the net force acting on a body, $$m$$ is the mass of the body, and $$a$$ is the acceleration of the body.
    If the forces acting on the object are balanced then $$F=0$$.
    $$\therefore a=0$$, as $$m$$ can not be zero.
    Hence, the body will not have any acceleration.
  • Question 2
    1 / -0
    What is the momentum of an object of mass m, moving with a velocity $$V$$ ?
    Solution

    Correct Answer: D

    Explanation:

    Momentum defined as the quantity of motion of a body. It is a vector quantity and measured by the product of mass and velocity of the body. So,

     momentum = mass ×velocity

                            $$=m×V=mV$$ 

    Hence Option (D) is the right answer.


  • Question 3
    1 / -0
    Newton’s second law of motion says that the mass of object times its acceleration is equal to the net force on the object. Which of the following gives the correct units for force?
    Solution
    The SI unit of mass is $$kg$$.
    The SI unit of acceleration is $$m/s^2$$.
    We know,
    $$\text{Force}=\text{mass}\times \text{acceleration}$$
    The unit of force is $$kg.m/s^2$$.
  • Question 4
    1 / -0
    A body of mass $$10\ kg$$ undergoes a change in velocity of $$10\ m/s$$ in $$5\ s$$. What is the force acting on it?
    Solution
    Acceleration $$ a = \dfrac{\text{velocity}}{\text{time}} $$ 
    Given , 
    Velocity $$ = 10\ m/s $$ 
    Time $$ = 5s $$ 
    Mass $$ = 10\ kg $$

    $$a= \dfrac{10}{5}\ m/s^{2} $$ 
        
           $$ = 2\ m/s^{2} $$ 

    Force = mass $$ \times $$ acceleration 
       
             $$ = 10 \times 2 = 20 N $$
  • Question 5
    1 / -0
    In the above figure, a locomotive has broken through the wall of a train station. During the collision, what can be said about the force exerted by the locomotive on the wall?

    Solution
    Answer (B). Newton’s 3rd law describes all objects, breaking or whole. The force that the locomotive exerted on the wall is the same as that exerted by the wall on the locomotive. The framing around the wall could not exert so strong a force on the section of the wall that broke out.
  • Question 6
    1 / -0
    An athlete jumps straight up in the air to catch a ball. If he took $$0.4$$ seconds to jump up and $$0.4$$ seconds to come back down, how high did he jump? Take $$g = 9.8\ m/s^{2}$$.
    Solution
    Given,
    Time taken by the athlete to jump up $$=$$ Time taken by the athlete to come down
    $$t=0.4\ s$$
    Distance travelled by the athlete while moving up $$=$$ distance travelled by the athlete while coming down
    Let the distance travelled while moving up or down be $$h$$

    While coming down,
    Initial velocity, $$u=0$$
    Acceleration due to gravity, $$g=9.8\ m/s^2$$

    Using Newton's second equation of motion :
    $$s = ut + \dfrac{1}{2} at^{2} $$ 

    $$h = ut + \dfrac{1}{2} gt^{2} $$ 

    $$ \therefore h = (0\times 0.4) +\dfrac{1}{2} \times 9.8 (0.4)^{2} $$ 

    $$ h =\dfrac{1}{2} \times 9.8\times 0.16 $$ 

    $$h = 0.784\ m $$ 

  • Question 7
    1 / -0
    Which of these examples can be explained by Newtons first law of motion ?
    Solution
    The first law of motion was Inertia and when a runner reaches a finish line he does not comes to stop immediately due to inertia.
    Newton's first law of motion states that a body at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.
  • Question 8
    1 / -0
    A bullet of mass A and velocity B is fired into a block of wood of mass C. If loss of any mass and friction be neglected, then velocity of the system must be
    Solution
    Given:
    The bullet strikes the block and after collision they become a system and
    $$(Mass)_{bullet} = A$$
    $$(Velocity)_{bullet} = B$$ 
    $$(Mass)_{block} = C$$
    $$(Velocity)_{block} = 0$$ 
    Momentum before impact = Momentum after impact
    $$AB + 0 =(A+C)(v)_{system
    }$$
    $$(v)_{system}=\dfrac{AB}{A+C}$$
    The velocity of the system $$(v)_{system}=\dfrac{AB}{A+C}$$
  • Question 9
    1 / -0
     A shell of mass 100 g moving with the speed of $$50 m s^{-1}$$ along a straight line bursts into two pieces. The piece of mass 60 g starts moving horizontally with a speed of $$50 m s^{-1}$$. The other piece moves with a speed of
    Solution

  • Question 10
    1 / -0
    When a bus starts suddenly, the passengers are pushed back. This is an example of which of the following?
    Solution

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