Forces and Laws of Motion Test

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Forces and Laws of Motion Test - 7

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Weekly Quiz Competition

Question 1
1 / -0

A force of 7 kg-wt acts on a body of mass 10 kg calculate the acceleration produced.

A
8 ms⁻²

B
10 ms⁻²

C
7 ms⁻²

D
6 ms⁻²

Solution

Force = 7 kg-wt = 7 × 10 = 70 N, mass = 10 kg. therefore, acceleration produced in the body = F/a = 70/10
= 7 ms^-2.
Question 2
1 / -0

The physical quantity which is equal to the rate of change of momentum is

A
power

B
energy

C
impulse

D
force

Solution

Rate of change of momentum=(final momentum-initial momentum)/time taken

=(mv-mu)/t

=m(v-u)/t

=ma

=F
Question 3
1 / -0

Which of the following physical quantity is associated with Newton’s second law of motion?

A
mass

B
time

C
velocity

D
all of these

Solution

Newton’s second law of motion states that rate of change in momentum is equal to force applied. Momentum is the product of mass and velocity. So, mass, velocity and time all are associated with Newton’s second law of motion.
Question 4
1 / -0

State whether the following statement is true or false “force can be measured using first law of motion”

A
true

B
false

C
partially true

D
partially false

Solution

The force can be measured by newton’s second law of motion. First law of motion states that object in rest or uniform motion tends to remain in its state.
Question 5
1 / -0

“A body moves with a constant speed of 5m/s. This shows that no unbalanced forces are acting on the body” is a

A
true statement

B
false statement

C
partially true

D
partially false

Solution

Since the body is moving with constant speed this means that there is no acceleration. Thus the forces acting are balanced. Hence there are no unbalanced forces acting on the body.
Question 6
1 / -0

A force of 100N applied on an object accelerates it with an acceleration of 2ms⁻². How much force is required to produce the same acceleration when identical object of same mass is tied with the first object?

A
100N

B
200N

C
300N

D
50N

Solution

Force= 100N, acceleration = 2ms^-2, Mass = force/ acceleration = 100/ 2 = 50 kg. when mass is doubled, mass = 100 kg, required acceleration = 2ms^-2, than force required = m × a
= 100 × 2
= 200N.
Question 7
1 / -0

Which would require a greater force – accelerating a body A of mass 2kg at 5ms⁻² or a body B of mass 5kg at 2ms^-2?

A
body A

B
body B

C
both have equal forces

D
none of these

Solution

Mass of body A = 2Kg, acceleration = 5 m/s², than force
= m × a
= 2 × 5 10N.
Mass of body B = 5kg, acceleration= 2 m/s². Force
= 5 × 2
= 10 N.
so, both require equal force.
Question 8
1 / -0

Essential characteristic of equilibrium is

A
momentum equals zero

B
acceleration equals zero

C
K. E equals zero

D
none of these

Solution

At equilibrium, the acceleration is equal to zero. So, there is no net change in acceleration of the moving body.
Question 9
1 / -0

To every action there is an,

A
Equal and no reaction

B
Unequal and opposite reaction

C
Equal and opposite reaction

D
None of the above

Solution

To every action, there is an equal and opposite reaction. This is the newton’s third law of motion.

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Re-Attempt Weekly Quiz Competition

Forces and Laws of Motion Test - 7

Result

Forces and Laws of Motion Test - 7

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SHARING IS CARING

Question 1

8 ms−2

10 ms−2

7 ms−2

6 ms−2

Solution

Question 2

power

energy

impulse

force

Solution

Question 3

mass

time

velocity

all of these

Solution

Question 4

true

false

partially true

partially false

Solution

Question 5

true statement

false statement

partially true

partially false

Solution

Question 6

100N

200N

300N

50N

Solution

Question 7

body A

body B

both have equal forces

none of these

Solution

Question 8

momentum equals zero

acceleration equals zero

K. E equals zero

none of these

Solution

Question 9

Equal and no reaction

Unequal and opposite reaction

Equal and opposite reaction

None of the above

Solution

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8 ms⁻²

10 ms⁻²

7 ms⁻²

6 ms⁻²