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Three Dimensional Geometry Test - 3

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Three Dimensional Geometry Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0

    The locus of a point which moves so that the difference of the squares of its distances from two given points is constant, is a:

  • Question 2
    1 / -0

    The radius of the sphere through the points ( 4 ,3 , 0 ) , ( 0 , 4 , 3 ) ,( 0 , 5 , 0 ) and ( 4 , 0 , 3 ) is

    Solution

    we know that general equation of sphere is x2+y2+z2+2gx+2fy+2hz+c=0

    since sphere passing through the points ( 4 ,3 , 0 ) , ( 0 , 4 , 3 ) ,( 0 , 5 , 0 ) and ( 4 , 0 , 3 ) so putting these values one by one in given equation , we get

    16+ 9+ 8g + 6f + c=0 =>8g +6f +c = -25 -------------1)

    16 +9 +8f +6h +c=0 =>8f + 6h +c= -25 -----------2)

    25 + 10f +c = 0 -----------------------3)

    16+ 9+ 8g + 6h +c=0 =>8g +6h +c= -25 -------------4)

    by 2) - 4 ) we have f = g

    using this in 1) we have 16f +c = -25 -------5)

    Now solving 3) and 5) we get f=0 

    using value of f we have g= 0 , h= 0 , c= -25

    Now radius =√(−g)2+(−f)+(−h)2−c = √25 =5

     

  • Question 3
    1 / -0

    The direction ratios of normal to the plane through (1, 0, 0) and (0, 1, 0), which makes an angle π/4 with the plane x + y = 3, are

  • Question 4
    1 / -0

    If the direction cosines of a straight line are < k , k , k > , then what will be the value of k

    Solution

    We know that if  l , m , n are direction cosines of a lines then l2 +m+n2= 1

     so, k2 + k2 +k2 = 1

    3 k2 = 1

    k= 1/3 

    taking squareroot on both sides , we have k=1/√3ork=−1/√3

     

  • Question 5
    1 / -0

    The angle between the lines x = 1, y = 2 and y = 1, z = 0 is

  • Question 6
    1 / -0

    the numbers 3, 4 , 5 can be

    Solution

    the numbers 3, 4 , 5 can be direction ratio of any line these not satisfying any other option

     

  • Question 7
    1 / -0

    The cosine of the angle between any two diagonals of a cube

  • Question 8
    1 / -0

    The shortest distance from the plane 12x + 4y + 3z = 327 to the sphere x2 + y2 + z2 + 4x – 2y – 6z = 155 is:

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