Motion in a Straight Line Test

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Motion in a Straight Line Test - 1

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Weekly Quiz Competition

Question 1
1 / -0

The distance x covered by a body moving in a straight line in time t is given by:

x² = t² + 2t + 3

The acceleration of the body will vary as

A
1/x

B
1/x²

C
1/x³

D
1/x⁴
Question 2
1 / -0

The acceleration of a particle starting from rest varies with time according to the relation a = kt + c, where k and c are constants of motion.

The velocity v of the particle after a time t will be

A
kt + ct

B
(1/2)kt² + ct

C
(1/2)(kt² + ct)

D
kt² + (1/2)ct
Question 3
1 / -0

The acceleration a (in ms^-2) of a body starting from rest varies with time t (in s) according to the relation:

a = 3t + 4

The velocity of the body at time t = 2 s will be

A
10 ms^-1

B
12 ms^-1

C
14 ms^-1

D
16 ms^-1
Question 4
1 / -0

for motion in a straight line

A
position to the right of the origin is taken as positive and to the left as negative.

B
position to the left of the origin is taken as positive and to the right as negative.

C
motion away from origin is positive

D
motion towards origin is positive

Solution

To describe motion along a straight line, we can choose an axis, say X-axis, so that it coincides with the path of the object. We then measure the position of the object with reference to a conveniently chosen origin, say O, Positions to the right of O are taken as positive and to the left of O, as negative.
Question 5
1 / -0

The position of an object moving in a straight line can be specified with reference to

A
a conveniently chosen origin

B
a triangle

C
an arbitrary star

D
another straight line

Solution

To describe motion along a straight line, we can choose an axis, say X-axis, so that it coincides with the path of the object. We then measure the position of the object with reference to a conveniently chosen origin, say O, Positions to the right of O are taken as positive and to the left of O, as negative.
Question 6
1 / -0

A body moving in a straight line with constant acceleration of 10 ms^-2 covers a distance of 40 m in the 4^th second. How much distance will it cover in the 6^th second?

A
50 m

B
60 m

C
70 m

D
80 m
Question 7
1 / -0

At t = 0, an arrow is fired vertically upwards with a speed of 98 ms^-1. A second arrow is fired vertically upwards with the same speed at t = 5 s. Then,

A
the two arrows will be at the same height above the ground at t = 10 s

B
the two arrows will reach back to their starting points at t = 20 s and t = 30 s

C
the ratio of the speed of the first arrow and that of the second arrow at t = 20 s will be 2 : 1

D
the maximum height attained by either arrow will be 980 m

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Re-Attempt Weekly Quiz Competition

Motion in a Straight Line Test - 1

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Motion in a Straight Line Test - 1

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SHARING IS CARING

Question 1

1/x

1/x2

1/x3

1/x4

Question 2

kt + ct

(1/2)kt2 + ct

(1/2)(kt2 + ct)

kt2 + (1/2)ct

Question 3

10 ms-1

12 ms-1

14 ms-1

16 ms-1

Question 4

position to the right of the origin is taken as positive and to the left as negative.

position to the left of the origin is taken as positive and to the right as negative.

motion away from origin is positive

motion towards origin is positive

Solution

Question 5

a conveniently chosen origin

a triangle

an arbitrary star

another straight line

Solution

Question 6

50 m

60 m

70 m

80 m

Question 7

the two arrows will be at the same height above the ground at t = 10 s

the two arrows will reach back to their starting points at t = 20 s and t = 30 s

the ratio of the speed of the first arrow and that of the second arrow at t = 20 s will be 2 : 1

the maximum height attained by either arrow will be 980 m

User

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My Perfomance

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1/x²

1/x³

1/x⁴

(1/2)kt² + ct

(1/2)(kt² + ct)

kt² + (1/2)ct

10 ms^-1

12 ms^-1

14 ms^-1

16 ms^-1