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Work, Energy and Power Test - 5

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Work, Energy and Power Test - 5
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Weekly Quiz Competition
  • Question 1
    1 / -0

    The work done by the force is defined to be

    Solution

    Work done is given by 

    W = (Fcosθ)d

    here Fcosθ is the component of applied force  in direction of displacement and d is magnitude of displacement.

     

  • Question 2
    1 / -0

    In a graph of F(x) vs x, the area under the curve

    Solution

    Work done by a variable force is given by 

    above integration gives us area area under F and  x. 

     

  • Question 3
    1 / -0
    The power of a pump, which can pump 200 kg of water to a height of 50 m in 10 s, will be (g = 10 m/s2)
  • Question 4
    1 / -0

    In which case is the work done zero?

    Solution

    Work done is given as

    W = Fdcosθ

    Here θ is the angle between F and d  if both are perpendicular  then θ = 90 degree so cosθ = 0 and thus work done is 0 .

     

  • Question 5
    1 / -0
    A particle is placed at the origin and a force F = Kx is acting on it (where K is positive constant). If U(0) = 0, the graph of U(x) versus x will be (where u is potential energy function)
  • Question 6
    1 / -0

    If F is a force and d is the displacement in the direction of force then the work done by the force is given by

    Solution

    Work done = force in the direction of displacement multiplied by displacement

     

  • Question 7
    1 / -0
    A particle is released from a height 'S'. At a certain height, its kinetic energy is three times its potential energy. The respective height and speed of the particle at that instant are
  • Question 8
    1 / -0
    A body of mass 'm' is accelerated uniformly from rest to a speed 'v' in time 'T'. The instantaneous power delivered by the body as a function of time is given by
  • Question 9
    1 / -0

    The scalar product of two vectors A and B in terms of the projections of the vectors on the x, y and z axis is

    Solution

    A = Ax i+ Ay j+ Azk

    B = Bx i+ Bj+ Bzk

    A. B = (Ax i+ Ay j+ Azk). ( Bx i+ By j+ Bzk) 

    A. B = AxBx + AyBy + AzB

     

  • Question 10
    1 / -0
    An isolated particle of mass m is moving in a horizontal plane (x – y), along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = + 15 cm. The larger fragment at this instant is at
  • Question 11
    1 / -0

    The scalar product of two vectors A and B in terms of the magnitudes and angle θ is

    Solution

    The scalar product of two vectors can be constructed by taking the component of one vector in the direction of the other and multiplying it times the magnitude of the other vector. This can be expressed in the form

  • Question 12
    1 / -0
    Directions: The following question has four choices out of which ONLY ONE is correct.

    The potential energy of a body is given by A - Bx². The magnitude of force acting on the particle is
  • Question 13
    1 / -0
    Directions: The following question has four choices out of which ONLY ONE is correct.

    A force of 60 N is applied on a body at an angle of 60° with a horizontal, and displaces it through 5 m along horizontal. What is the work done?
  • Question 14
    1 / -0
    The relationship between the force 'F' and the position 'x' of a body is as shown in the figure. What will be the work done in displacing the body from x = 1 m to x = 5 m?

  • Question 15
    1 / -0
    A mass m is attached to the end of a rod of length l. The mass goes around a vertical circular path with the other end hinged at the centre. What should be the minimum velocity of mass at the bottom of the circle, so that the mass completes the circle?

  • Question 16
    1 / -0
    A cricket ball is hit at 450 to the horizontal with kinetic energy K.The kinetic energy at the highest point is
  • Question 17
    1 / -0
    Directions: The following question has four choices, out of which ONLY ONE is correct.

    A bullet of mass 10 × 10-3 kg moving with a speed of 20 ms-1 hits an ice block (0oC) of 990 g kept at rest on a frictionless floor and gets embedded in it. If ice takes 50% of KE lost by the system, the amount of ice melted (in grams) approximately is: (J = 4.2 J/cal) (Latent heat of ice = 80 cal/g)
  • Question 18
    1 / -0

    The scalar product of two vectors A and B is

    Solution

    Scalar product means dot product and dot product of 2 vectors gives a scalar  , example  dot product of force and displacement gives work which is scalar

  • Question 19
    1 / -0

    The change in kinetic energy of a particle is equal to the

    Solution

    if a body of mass m move with velocity u under  the action of force F. Its velocity become v after displaced by s. then

  • Question 20
    1 / -0

    The S.I unit of force is

    Solution

    In International System of Units (SI) the newton is the unit for force. It is equal to the amount of net force required to accelerate a mass of one kilogram at a rate of 1 m/sec2 in direction of the applied force. It is named after Isaac Newton in recognition of his work on classical mechanics, specifically Newton's second law of motion.

    11Kgm/sec2

    Dyne is a  cgs unit of force. One dyne is equal to 10−5 N

     

  • Question 21
    1 / -0
    A particle moves from position  to position  under action of force . The work done will be
  • Question 22
    1 / -0
    An electric pump is used to fill an overhead tank of capacity 9 m3 kept at a height of 10 m above the ground. If the pump takes 5 minutes to fill the tank by consuming 10 kW power, then the efficiency of the pump must be (take g = 10 ms-2)
  • Question 23
    1 / -0
    A body of mass 1 kg is moving in a vertical circular path of radius 1 m. The difference between the kinetic energies at its highest and lowest positions is
  • Question 24
    1 / -0
    300 J of work is done in sliding a 2 kg block, up an inclined plane to a height of 10 meters. Taking value of acceleration due to gravity 'g' to be 10 m/s2 , work done against friction is
  • Question 25
    1 / -0

    The scalar product of vectors is

    Solution

    Scalar product is

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