Profit, Loss and Discount Test

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Profit, Loss and Discount Test - 7

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Question 1
1 / -0

C.P. = ₹ 45and S.P. = ₹ 40, gain or loss percent=?

A
11(1/9)

B
12

C
12(1/7)

D
13(1/7)

Solution

C.P. = ₹ 45and S.P. = ₹ 40
We know that
Loss = C.P. – S.P.
So we get
= 45– 40
= ₹ 5
So we get
Loss percent = (loss × 100)/ C.P.
Substituting the values
= (5 × 100)/ 45
= 100/9
= 11(1/9)%
Question 2
1 / -0

The selling price of an article is ₹ 1700 and costprice is 2000.
Find:profit or loss as percent.

A
12

B
15

C
18

D
9

Solution

Loss = C.P – S.P
Substituting the values
= 2000 – 1700
= ₹ 300
Loss percent = (loss × 100)/ C.P
Substituting the values
= (300 × 100)/ 2000
So we get
= 30/2
= 15%
Question 3
1 / -0

S.P. = ₹ 50 and loss = ₹ 10,gainorlosspercent = ?

A
15(3/7)

B
16(2/3)

C
14(7/9)

D
11(4/5)

Solution

S.P. = ₹ 50 and loss = ₹ 10
We know that
C.P. = S.P. + loss
So we get
= 50 + 10
= ₹ 60
So we get
Loss percent = (loss × 100)/ C.P.
Substituting the values
= (10 × 100)/ 60
= 50/3
= 16 (2/3) %
Question 4
1 / -0

C.P. = ₹ 2000 and S.P. = ₹ 2240,gain or loss percent=?

A
8

B
10

C
12

D
14

Solution

C.P. = ₹ 2000 and S.P. = ₹ 2240
We know that
Gain = S.P. – C.P.
So we get
= 2240 – 2000
= ₹ 240
So we get
Gain percent = (gain × 100)/ C.P.
Substituting the values
= (240 × 100)/ 2000
= 12%
Question 5
1 / -0

A vendor bought 120 sweets at 20 p each. Inhis house, 18 were consumed and he sold the remaining at 30p each. Find hisprofit or loss as percent.

A
17.5

B
22.5

C
27.5

D
32.5

Solution

No. of sweets bought = 120
C.P of 120 sweets = (120 × 20)/ 100 = ₹ 24
No. of sweets consumed = 18
So the balance sweets = 120 – 18 = 102
S.P of 102 sweets = (102 × 30)/ 100 = ₹ 30.60
Gain = S.P – C.P
Substituting the values
= 30.60 – 24
= ₹ 6.60
Gain percent = (gain × 100)/ C.P
Substituting the values
= (6.60 × 100)/ 24
Multiplying both numerator and denominator by 100
= (660 × 100)/ (100 × 24)
= 55/2
= 27.5%
Question 6
1 / -0

Nandu bought a gamefor ₹ 1,50and sold it for ₹ 1,80. Calculate his profit orloss percent.

A
5

B
10

C
15

D
20

Solution

It is given that
C.P of game = ₹ 1,50
S.P of game = ₹ 1,80
We know that
Gain = S.P – C. P
= 180 – 150
= ₹ 30
Gain percent = (Gain × 100)/ C.P
Substituting the values
= (30 × 100)/ 150
= 20%
Question 7
1 / -0

C.P. = ₹ 5500 and gain = ₹ 220, gainorlosspercent = ?

A
1

B
2

C
3

D
4

Solution

C.P. = ₹ 5500 and gain = ₹ 220
We know that
S.P. = C.P. + gain
So we get
= 5500 + 220
= ₹ 5720
So we get
Gain percent = (gain × 100)/ C.P.
Substituting the values
= (220 × 100)/ 5500
= 4%
Question 8
1 / -0

Lemonsare bought at 3 for ₹ 15and all of them are soldat 4 for ₹ 18. Find the loss or gain as percent.

A
5

B
10

C
15

D
20

Solution

We know that
LCM of 3 and 4 = 12
Consider that 12 lemons are bought
So the C.P of 12 lemons = (15 × 12)/ 3 = ₹ 60
S.P of 12 lemons = (18 × 12)/ 4 = ₹ 54
Loss = C.P – S.P
Substituting the values
= 60 – 54
= ₹ 6
Loss percent = (loss × 100)/ C.P
Substituting the values
= (6 × 100)/ 60
= 10%
Question 9
1 / -0

Atoy is bought for ₹ 1,40and is sold at a loss of 15%. Find its selling price.

A
111

B
119

C
123

D
145

Solution

It is given that
C.P. of the toy = ₹ 1,40
Loss percent = 15%
We know that
S.P = [C.P (100 – loss percent)]/ 100
Substituting the values
= [140 (100 – 15)]/ 100
By further calculation
= (140 × 85)/ 100
= ₹ 119
Question 10
1 / -0

The selling price of sweet is ₹ 1,20 and cost price is 5/4 times of its selling price.
Find:cost price of the sweet

A
250

B
200

C
150

D
180

Solution

S.P of an sweet = ₹ 1,20
We know that
C.P = 5/4 of S.P
Substituting the values
= 5/4 × 120
= ₹ 150
Question 11
1 / -0

By selling a cyclefor ₹ 8100,a loss of 10 percent is suffered. Find itscost price.

A
3000

B
6000

C
9000

D
8890

Solution

It is given that
S.P of = ₹ 8100
Loss percent = 10 %
We know that
C.P. = (S.P. × 100)/ (100 – loss percent)
Substituting the values
= (8100 × 100)/ (100 – 10)
So we get
= (8100 × 100)/ 90
= ₹ 9000.
Question 12
1 / -0

C.P = ₹ 50 and gain = 25%,sellingprice = ?

A
42.7

B
59.5

C
62.5

D
67.7

Solution

C.P = ₹ 50 and gain = 25%
We know that
S.P. = [C.P. (100 + gain percent)]/ 100
Substituting the values
= [50 (100 + 25)]/ 100
We get
= (50 × 125)/ 100
= ₹ 62.5
Question 13
1 / -0

An article bought for ₹ 700is sold at a profit of 10%. Find its sellingprice.

A
770

B
777

C
840

D
None of the above

Solution

It is given that
C.P of an article = ₹ 700
Profit = 10%
We know that
S.P = [C.P (100 + profit percent)]/ 100
Substituting the values
= [700 (100 + 10)]/ 100
So we get
= (700 × 110)/ 100
= ₹ 770
Question 14
1 / -0

Lemonsare bought at 5 for ₹ 10 and sold at 6 for ₹ 15. Find profit or loss aspercent.

A
10

B
15

C
20

D
25

Solution

We know that
LCM of 5 and 6 = 30
Consider that 30 lemons are bought
So the C.P of 30 lemons = (30 × 10)/ 5 = ₹ 60
S.P of 30 lemons = (30 × 15)/ 6 = ₹ 75
Gain = S.P – C.P
Substituting the values
= 75 – 60
= ₹ 15
Gain percent = (gain × 100)/ C.P
Substituting the values
= (15 × 100)/ 60
= 25%
Question 15
1 / -0

C.P. = ₹ 60 and loss = 12 ½ %,sellingprice = ?

A
48.5

B
52.5

C
36.5

D
59.5

Solution

C.P. = ₹ 60 and loss = 12 ½ %
We know that
Loss = 12 ½ % = 25/2%
Here
S.P. = [C.P. (100 – Loss percent)]/ 100
Substituting the values
= [60 (100 – 25/2)]/ 100
So we get
= [60 (200 – 25/ 2)]/ 100
We can write it as
= (60 × 175)/ (2 × 100)
= ₹ 105/2
= ₹ 52.50

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Re-Attempt Weekly Quiz Competition

Profit, Loss and Discount Test - 7

Result

Profit, Loss and Discount Test - 7

Score

-

Rank

-

SHARING IS CARING

Question 1

11(1/9)

12

12(1/7)

13(1/7)

Solution

Question 2

12

15

18

9

Solution

Question 3

15(3/7)

16(2/3)

14(7/9)

11(4/5)

Solution

Question 4

8

10

12

14

Solution

Question 5

17.5

22.5

27.5

32.5

Solution

Question 6

5

10

15

20

Solution

Question 7

1

2

3

4

Solution

Question 8

5

10

15

20

Solution

Question 9

111

119

123

145

Solution

Question 10

250

200

150

180

Solution

Question 11

3000

6000

9000

8890

Solution

Question 12

42.7

59.5

62.5

67.7

Solution