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Fundamental Concepts Test - 1

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Fundamental Concepts Test - 1
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  • Question 1
    1 / -0

    Which statement correctly represents the equation 2(x + 2) = x − 2?

    Solution

    The given equation is 2(x + 2) = x − 2.

    The expression (x + 2) means two more than x.

    Thus, 2(x + 2) means the product of two and two more than x.

    The expression x − 2 means two less than x

    Thus, 2(x + 2) = x − 2 means ‘the product of two and two more than x equals two less than x’.

  • Question 2
    1 / -0

    What is the product of mx2 and x(2 + y + mx)?

    Solution

    The product of mx2 and x(2 + y + mx) is

    mx2{x(2 + y + mx)}

    mx2{2x + xy + mx2}

    = 2mx3 + mx3y + m2x4

    Thus, the required product is 2mx3 + mx3y + m2x4.

  • Question 3
    1 / -0

    The information in which of the following alternatives is incorrectly matched?

    Solution

    The numerical factor of a term is said to be its coefficient.

    In the expression 8z2 + 7yz + 7z –7y, the coefficient of z2 is 8, that of yz is 7, and that of y2 is 0 (this expression does not contain any term with y2).

    Thus, the information in alternative D is incorrectly matched.

  • Question 4
    1 / -0

    Which of the following polynomials is not cubic?

    Solution

    A polynomial of degree 1 is known as linear polynomial.

    A polynomial of degree 2 is known as quadratic polynomial.

    A polynomial of degree 3 is known as cubic polynomial.

    A polynomial of degree 0 is known as constant polynomial.

    Number 0 is known as zero polynomial.

    Since the degree of the polynomial 3y + 3 is 1, it is not a cubic polynomial. It is a linear polynomial.

  • Question 5
    1 / -0

    Which expression is obtained by adding the expressions 3ab2 + c+ 37b2a + 26a2band −2a2b2 − 3ab2 +32 3c+ 13b3a2?

    Solution

    The expressions 3ab2 + c3+ 37b2a + 26a2band −2a2b2 − 3ab2 +32 3c+13b3acan be added as follows:

    3ab2 + c+ 37b2a + 26a2b−2a2b2 − 3ab2 +32 3c+ 13b3a2

    = (3ab− 3ab2) + (26a2b2−2a2b2) + 37b2a + (c3+32 3c3) + 13b3a2

    = 24a2b2 + 37b2a + (32 3+1)c3 + 13b3a2

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