Light Energy Test

Result

Light Energy Test - 8

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Weekly Quiz Competition

Question 1
1 / -0

The line OQ is called the :

A
reflected ray

B
incident ray

C
normal

D
refracted ray

Solution

The line OQ is called the reflected ray.
Question 2
1 / -0

To see full image of ourselves, we should take the minimum size of the plane mirror is-

A
should be twice of our height

B
should be of our height

C
should be half of our height

D
depends upon our distance from mirror

Solution

According to the question the correct option will be ‘C’ because If we want to see our full image then the minimum size of the plane mirror should be half of our height.
Question 3
1 / -0

A virtual image formed by a plane mirror is in the form of-

A
Diminished

B
Inverted

C
Erect

D
Enlarged

Solution

According to the question the correct option will be ‘C’ because a plane mirror always forms erect image and of same size as well.
Question 4
1 / -0

Ifthe angles of incidence is 50^o, what will be the angle of reflection with respect to the normal drawn perpendicular at the point of reflection?

A
50^o

B
100^o

C
160^o

D
20^o

Solution

According to the question the correct option will be ‘A’ because The angle of incidence is equal to the angle of reflection.

Here, angle of incidence = 50°

Therefore, angle of reflection = 50°
Question 5
1 / -0

an image is formed by a plane mirror is a type of-

A
Real & inverted

B
Real & erect

C
Virtual & erect

D
Virtual & inverted

Solution

According to the question the correct option will be ‘D’ because The image that is formed by a plane mirror will be virtual, upright, same size and inverted

The object distance and the image distance will be equal.

Thus, the image formed by a plane mirror is virtual and inverted.
Question 6
1 / -0

In the following cases we cannot get virtual image using a mirror that will be-

A

B

C

D

Solution

According to the question the correct option will be ‘C’ because for virtual image the reflected rays should not meet in real, they should appear to meet when the reflected ray is extended backward to its direction of propagation.
In this case shown in the figure above we cannot get the virtual image of object as the reflected ray will meet in front of the mirror to form a real image.
Option C is the correct answer.
Question 7
1 / -0

Reeta and Preeta were sitting around a round table. They noticed that they could see their own and each other's image onto the table top. Then table top is made of

A
Unpolished wood, covered with white cloth

B
Polished glass of red color

C
Glass covered with cellophane paper

D
Smoked glass covered with green color cloth.

Solution

According to the question the correct option will be ‘B’ because polished glass of red color reflects some of the light incident on it so images of the both persons are formed on it.
Question 8
1 / -0

which of the following is an invalid difference between Real and Virtual image -

A
A real image can be caught on a screen whereas a virtual image cannot be caught on a screen

B
A real image is formed by the actual intersection of light rays whereas a virtual image is formed by the imaginary intersection of light rays.

C
A real image is always erect whereas a virtual image is always inverted.

D
A real image is formed when the rays of light after reflection or refraction actually meet at some point whereas a virtual image is formed when the rays of light after reflection or refraction appear to meet at a point.

Solution

According to the question the correct option will be ‘C’ because

A real image is always inverted whereas a virtual image is always erect.

A real image is formed when the rays of light after reflection or refraction actually meet at some point whereas a virtual image is formed when the rays of light after reflection or refraction appear to meet at a point.

Real images can be projected or seen on a screen. Virtual images cannot be seen or projected on a screen.
Question 9
1 / -0

it is difficult to read the image of the text of a page formed due to reflection by plane mirror because -

A
Due to lateral inversion

B
It is virtual

C
Due to reflection

D
No difficulty

Solution

According to the question the correct option will be ‘A’ because in a plane mirror, each point on the image is as far behind the mirror plane as the corresponding point on the object is in front. So, the image of an object is reversed in the direction perpendicular to the surface of the mirror. Therefore, the concept is called as Lateral inversion. It is the apparent reversal of left and right that we often see in a plane mirror image. Due to this lateral inversion, it is difficult to read the image of a text page formed due to reflection by a plane mirror.
Question 10
1 / -0

When a divergent beam of light is incident on a plane mirror, the image formed is

A
Upright and real

B
Upright and virtual

C
Inverted and virtual

D
Inverted and real

Solution

It should be remembered that the plane mirror always forms a virtual and erect image.
Question 11
1 / -0

the silvering on the back surface of can be done by a mirror is-

A
Silver

B
Mercury

C
both

D
none

Solution

According to the question the correct option will be ‘B’ because a plane mirror is made from a few mm thick glass plates. One surface of glass plate is polished to a high degree of smoothness. This forms the front part of the mirror. And the other (back) surface is silvered (i.e. painted with silver, mercury or some other material).
Question 12
1 / -0

Images can be caught on a screen is-

A
real

B
inverted

C
virtual

D
erect

Solution

According to the question the correct option will be ‘A’ because Real and Inverted images can be caught on screen.
Question 13
1 / -0

A person looks into the mirror by placing it close to his face. The image of his face was erect, laterally inverted and of the same size. Formed by the mirror-

A
plane

B
concave

C
convex

D

plane or concave

Solution

According to the question the correct option will be ‘A’ because the nature of the image formed by a plane mirror is virtual, erect, of the same size and also laterally inverted.
Question 14
1 / -0

Apparatus required for the laws of reflection is-

A
A spherical mirror

B
A plane mirror, a laser light, a pencil, a protractor

C
A mirror with black paper

D
A ray of light

Solution

According to the question the correct option will be ‘B’ because to prove the laws of reflection, a ray of laser light is allowed to strike the plane mirror and the light is reflected back. With a pencil, mark the path of the light and the mirror's base. With a protractor, measure the angle of incidence and the angle of reflection and it is found that:
Angle of incidence = Angle of reflection
Question 15
1 / -0

If $x_{1}$ be the size of the magnified image and $x_{2}$ the size of the diminished image in Lens Displacement Method, then the size of the object is

A
$\sqrt{x_{1} x_{2}}$

B
$x_{1} x_{2}$

C
$x_{1}^{2} x_{2}$

D
$x_{1} x_{2}^{2}$

Solution

According to the question the correct option will be ‘A’ because the size of the object in accordance with the Fresnel's displacement law is given by
$\sqrt{x_{1} x_{2}}$ .