Percentage And Its Applications Test-2

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Percentage And Its Applications Test-2

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Question 1
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In an examination, it is required to get 36% of maximum marks to pass. A student got 113 marks and was declared fail by 85 marks. The maximum marks are

A
500

B
550

C
640

D
1008

Solution

The correct option is B.
Let maximum marks be x.
Then
36% of x = (113+85). So x = (198*100/ 36) = 550
Question 2
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In an examination, 42% students failed in Hindi and 52% failed in English. If 17% failed in both the subjects, the percentage of those who passed in both the subject is

A
23%

B
27%

C
34%

D
40%

Solution

It is given that 42% fail in Hindi and 52% fail in English and 17% fail in both

So total fail percentage would be

42+52-17 ( because we have counted the 17 % 2 times)

=>77 % who have failed SO the percentage passing in both would be

100-77= 23%
Question 3
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In a college election, a candidate secured 62% of the votes and is elected by a majority of 144 votes. The total number of votes polled is

A
600

B
800

C
925

D
1200

Solution

∵ (62% of N - 38% of N) =144

⇒ 24% of N = 144

∴ N = (144 x 100)/24 = 600
Question 4
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The price of sugar is increased by 20%. If the expenditure is not allowed to be increased, the ratio between the reduction in consumption and the original consumption is

A
1 : 3

B
1 : 4

C
1 : 6

D
1 : 5

Solution
Question 5
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On decreasing the price of TV set by 30%, its sale is increased by 20%. What is the effect on the revenue received by the shopkeeper?

A
10% increase

B
10% decrease

C
16% increase

D
16% decrease

Solution

Lets take the orignal price as 100. Then on decreasing the price by 30% we get= 70. Now the sale is increased by 20%=84 (20% of 70 or 20/100*70= 14 now 70+14=84) So we can say that Cp=100 and Sp=84 Thats loss as cp is bigger. Loss=16 Loss%=16/100*100 =16%
Question 6
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The value of a machine depreciates 10% annually. If its present value is Rs. 4000, its value 2 years hence will be:

A
Rs. 3000

B
Rs. 3240

C
Rs. 3260

D
Rs. 3280

Solution

The correct option is B.
Present value - 4000
Depreciation - 10% of present value annually
After one year value of machine will be = 4000 - 400(10% of 4000) = 3600
After 2nd year value of machine will be = 3600 - 360(10% of 3600) = 3240
Question 7
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The population of a town increases by 5% annually. If it is 15435 now, its population 2 years ago was:

A
13700

B
14000

C
14800

D
15000

Solution

Let y be the population of the town initially
y x 105/100 x 105/100 = 15435
y = (15435 x 100 x 100) / (105 x 105)
On solving we get,
y = 14000
Question 8
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A man ’s wages were decreased by 50%. Again the reduced wages were increased by 50%. He has a loss of:

A
0%

B
0.25%

C
2.5%

D
25%

Solution

using the formula A + B + AB/100
where A = - 50(as the wages were decreased) , B = 50
-50 + 50 - (50 x 50/100)
-2500/100 = - 25 = 25% decrease
Question 9
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A number when increased by 37 ½% gives 33. The number is:

A
22

B
24

C
25

D
27
Solution
Let the number be y

according to the question.

y + y x (37.5/100) = 33

y x 137.5/100 = 33

y = 3300/137.5 = 24
Question 10
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The price of an article has been reduced to 25%. In order to restore the original price, the new price must be increased by:

A

B

C

D

Solution