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Coordination Compounds Test - 7

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Coordination Compounds Test - 7
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  • Question 1
    1 / -0.25

     

    One or More than One Options Correct Type

    Direction (Q. Nos. 1-5) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

    Q. 

    An example of double salt is/a

     

    Solution

     

     

    Common alum is K2 SO4 .AI2 (SO4 )3 .24H2 O  and carnallite is KCl.MgCl2 .6H2 O.

     

     

  • Question 2
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    Type of bonding in K4 [Fe(CN)6 ] is/a

     

    Solution

     

     

    The complex K4 [Fe(CN)6 ] whose formula can be written like that of double salt. Fe(CN)2  . 4KCN, dissociates to give K+ and [Fe(CN)6 ]4-  ions in the aqueous solution.

     

     

  • Question 3
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    The effective atomic number of Fe in  Fe(CO)5 is

     

    Solution

     

     

    The answer is 36 because in coordination compound we use EAN method due to which inert group atomic number or noble gas atomic number is more stable.

     

     

  • Question 4
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    Which of the following statements is/are correct?

     

    Solution

     

     

    [Co(en)3 ]CI3 produces 4 ions in solution as follows :
    [Co(en)3 ] CI3 →[Co(en)3 ]3+ + 3CI-

     

    1. is correct as charge on the complex ion will be +1

    2.  is incorrect as the complex will form 4 ions in solution

    3. is correct as there is no charge on the complex

    4. is also correct as cu+2 has blue color in solution

    Hence A, B and C are correct.

     

     

  • Question 5
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    A freshly prepared aqueous solution of Pd(NH3 )2 CI2 does not conduct electricity, it suggests that

     

    Solution

     

     

    In the aqueous solution of Pd(NH3 )2 CI2 , the atoms of chlorine I are in coordination sphere and the van 't Hoff factor of the ] compound are unite.

     

     

  • Question 6
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    Comprehension Type

    Direction : This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

    Passage

    Complex compounds are addition compounds formed by the stoichiometric combination of two or more simple salts but do not decompose into constituent ions completely. The first such complex prepared by Tassaert is hexamine cobalt (III) chloride. Later many such compounds were prepared and their properties were studied. The chloramines complexes of cobalt (III) chromium (III) not only exhibit a spectrum of colours but also differ in the reactivity of their chlorides. Moreover, greater the number of ions produced by a complex in solution, greater is the electrical conductivity. This type of information was obtained for several series of complexes.

    Q. 

    Coordination number of Co in CoCl3 . 5H2 O  is six. The volume of 0.1 N AgNO3 needed to precipitate the chlorine in 200 mL of 0.01 M solution of complex is

     

    Solution

     

     

    Since, the oxidation number of Co is + 3 hence, the complex compound would be [CoCI . 5H2 O]CI2 .

    Hence, 1 mole of [CoCI . 5H2 O]CI2 gives 2 moles of Cl-  ion.
    Given, moles of [CoCI . 5H2 O]CI2 = 200 mL x 0.01 M = 2 millimol
    2 millimol of [CoCI . 5H2 O]CI2 will give 4 millimol of Cl- .

    Now, to neutralise 4 millimol of Cl- , 4 millimol of AgNO3 is required.
    Let the volume o! AgNO3 = VmL
    Millimoles of AgNO3 = 0.1 x V
    0.1 x V  = 4 millimol

     

     

  • Question 7
    1 / -0.25

     

    Complex compounds are addition compounds formed by the stoichiometric combination of two or more simple salts but do not decompose into constituent ions completely. The first such complex prepared by Tassaert is hexamine cobalt (III) chloride. Later many such compounds were prepared and their properties were studied. The chloramines complexes of cobalt (III) chromium (III) not only exhibit a spectrum of colours but also differ in the reactivity of their chlorides. Moreover, greater the number of ions produced by a complex in solution, greater is the electrical conductivity. This type of information was obtained for several series of complexes.

    Q. 

    The number of ions per mole of the complex CoCI3  . 5NH3 in aqueous solution will be

     

    Solution

     

     

    [Co(NH3 )5 CI]CI2 →[Co(NH3 )5CI]2+ + 2Cl-  
    Hence, 3 ions are present for one mole of the complex in the solution.

     

     

  • Question 8
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    Matching List Type

    Direction : Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

    Q. 

    'Match the Column I with Column II and mark the correct option from the codes given below.

     

    Solution

     

     

    (i) →(r), (ii) →(q), (iii) →(p), (iv) →(s)

     

     

  • Question 9
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    One Integer Value Correct Type

    Direction : This section contains 5 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

    Q. 

    Formula of Mohr ’s salt is FeSO4  . (NH4 )2 SO4  . xH2 O. Here x value is

     

    Solution

     

     

    Formula of Mohr ’s salt is FeSO4  . (NH4 )2 SO4  . 6H2 O  . Here, x is 6

     

     

  • Question 10
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    When AgNO3 solution is added in excess to 1 M solution of CoCI3  . xNH3 , one mole of AgCI is formed. The value of x is

     

    Solution

     

     

    AgNO3 solution is added in excess of 1 M solution of CoCI3   . xNH3 .
    CoCl3 ​.xNH3 ​ +AgNO3 ​→AgCl  (1mole)

    This precipitation of 1 mol of AgCl by this reaction shows that there is only one  Cl  outside the coordination sphere, which is not as a ligand ( as ligands are not ionisable).

    Hence, the compound must be as follows:(showing the coordination sphere) [Co(NH3 ​)4 ​Cl2 ​]Cl, as this is the octahedral complex, where it is clear that there are only 2 Cl as ligand and other ligands are  NH3 ​. 

    So, 6 −2 = 4  NH3 ​ ligands.

     

     

  • Question 11
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    The volume (in mL) of 0.1 M AgNO3  required for complex precipitation of chloride ions present in 30 mL of 0.01 M solution of [Cr(H2 O)5 Cl]Cl2 , as silver chloride is close to

     

    Solution

     

     

    The correct answer is Option D
    Number of ionisable Cl −in [Cr(H2 O)5 Cl]Cl2 is 2.
    ∴Millimoles of Cl −=30 ×0.01 ×2=0.6
    ∴Millimoles of Ag+ required =0.6
    Now, 0.6/V(in ml)  = 0.1
    or, V=6 ml.

     

     

  • Question 12
    1 / -0.25

     

    Oxidation state of cobalt in Co(CO)6 is

     

    Solution

     

     

    ln Co(CO)6
    Let the oxidation state of Co is x.
    x + 6 x 0 = 0
    [Carbonyl (CO) is a neutral ligand hence, zero charg]
    x = 0
    Hence, Co has zero oxidation state.

     

     

  • Question 13
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    In the complex PtCl4 . 5NH3 if coordination number of platinum is 6, number of chloride ions precipitated by adding AgNO3  are

     

    Solution

     

     

    Coordination number of platinum is 6.
    ∴Number of chloride ions precipitated by adding AgCI are 3.

     

     

  • Question 14
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    Statement Type

    Direction : This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

    Q. 

    Statement I : Oxidation state of Fe in Fe(CO)5 is zero.
    Statement II : EAN of Fe in this complex is 36.

     

    Solution

     

     

    Statement I is true because CO is a neutral ligand, Statement II is true because
    EAN of Fe
    = Atomic number of Fe + Electrons gained by coordination
    = 26 + 2 x 5 = 36
    But Statement II is not the correct explanation. Correct explanation is that oxidation state of Fe in Fe(CO)5 is zero because CO is a neutral ligand.

     

     

  • Question 15
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    Statement I : The oxidation num ber of platinum in Zeise ’s salt is +4.

    Statement II : Zeise ’s salt is ionic complex.

     

    Solution

     

     

    Statement I The oxidation number of Pt in Zeis e ’s salt is +2.
    Statement II Zeise ’s salt is ionic complex with the formula K[PtCl3 (C 2 H4 )].
    Hence, statement II is correct but statment I is incorrect.

     

     

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